Thanks ❤️ you this way of finding an Exact trig functions value is so intuitive and easy to understand, You taught it so Easily.. Thank you so much 🤗...
@@MrsALovesMath Agreed. Perhaps its less about easy vs. hard problems and more about special angles vs. general angles. A general formula is always more useful than any of it's special cases. Example: cos nπ = (-1)^n = 1 (for even n) or -1 (for odd n) for *ANY* integer n. Now imagine most UA-cam videos choosing some specific n and solving only for that one super-simple and individual case. I tried solving sin and cos (m π / n) for random and much larger integers m and n and it turned out to be fun but way more challenging. My friends also found it very hard and a few solved them successfully. We were all surprised that UA-cam videos *ONLY* cover easy problems and could have been so much more helpful in sharing some best practices in solving moderately harder problems. Hope mathematics experts can show how harder problems are solved when such a large number of videos already cover easier problems. BTW every video is important and helpful to some, so thanks so much for all your efforts in making these videos.
(11*pi/6) radians is equal to 330 degrees (To convert the angle from radians to degrees, multiply (11*pi/6) by (180°/pi), and simplify). Since this angle is 30 degrees ((pi/6) radians) away from the x-axis, it is a reference angle to (pi/6) (i.e., 30°), in the fourth quadrant (This angle is 30 degrees (i.e., (pi/6) radians) away from the positive x-axis, where we began, or in other words, 30 degrees away from completing a full revolution (360 degrees, or equivalently, 2*pi radians) around the Unit Circle). Hence, (11*pi/6) will have almost the exact same trig values as (pi/6), only differing by the sign (i.e., whether it's positive or negative). Remember that tan is negative in the second and the fourth quadrants. So, tan(11*pi/6) = - tan(pi/6) (Notice the negative sign attached to the tan(pi/6)), as was claimed. In the video, she put the negative sign on the answer, but she did not do that in the previois step.
excellent explanation. still helping many years later :)
Thanks a lot. I’m in grade 12 calculus rn and for some reason I didn’t know how to do this without a calculator. In calculus no calculators!!
Omnipresent_ Ninja so glad it was helpful. Please share and subscribe 😊
Thanks ❤️ you this way of finding an Exact trig functions value is so intuitive and easy to understand, You taught it so Easily.. Thank you so much 🤗...
You’re so welcome 😊
This helped me a lot, thank you
Excellent explanation....This is wonderful
Robin Kunda thank you so much. Please subscribe and share 😊
@@MrsALovesMathhow would I get the triangle part
@@Liam-tg5lf ua-cam.com/video/sLkdwNoEIs4/v-deo.htmlsi=Nu4ymTF5TZzhNvqo
Love this thank you so much!!
Easy to understand thankyouuuuuu
It's helpful for me... Thnks mom
WOW this was so helpful
Can you find exact values in a ti-84?
It gives me the decimal answer every time but I need to convert that into square root/fraction form
Lot of videos on easy problems. Why no video on hard problems - e.g. how to calculate sin π/17 ?
pi/17 is not a special angle value so it would not fit into this expectation. My videos focus on Ontario curriculum. Enjoy.
@@MrsALovesMath Agreed. Perhaps its less about easy vs. hard problems and more about special angles vs. general angles. A general formula is always more useful than any of it's special cases. Example: cos nπ = (-1)^n = 1 (for even n) or -1 (for odd n) for *ANY* integer n. Now imagine most UA-cam videos choosing some specific n and solving only for that one super-simple and individual case. I tried solving sin and cos (m π / n) for random and much larger integers m and n and it turned out to be fun but way more challenging. My friends also found it very hard and a few solved them successfully. We were all surprised that UA-cam videos *ONLY* cover easy problems and could have been so much more helpful in sharing some best practices in solving moderately harder problems. Hope mathematics experts can show how harder problems are solved when such a large number of videos already cover easier problems. BTW every video is important and helpful to some, so thanks so much for all your efforts in making these videos.
THANK YOU
Thank you❤️❤️
Dear Mrs A, the tangent of 11pi/6 is not equal to the tangent of pi/6.
Jacques Masuret tan 11pi/6 = - tan pi/6. Make sure you are working in radians.
(11*pi/6) radians is equal to 330 degrees (To convert the angle from radians to degrees, multiply (11*pi/6) by (180°/pi), and simplify).
Since this angle is 30 degrees ((pi/6) radians) away from the x-axis, it is a reference angle to (pi/6) (i.e., 30°), in the fourth quadrant (This angle is 30 degrees (i.e., (pi/6) radians) away from the positive x-axis, where we began, or in other words, 30 degrees away from completing a full revolution (360 degrees, or equivalently, 2*pi radians) around the Unit Circle). Hence, (11*pi/6) will have almost the exact same trig values as (pi/6), only differing by the sign (i.e., whether it's positive or negative). Remember that tan is negative in the second and the fourth quadrants.
So, tan(11*pi/6) = - tan(pi/6) (Notice the negative sign attached to the tan(pi/6)), as was claimed.
In the video, she put the negative sign on the answer, but she did not do that in the previois step.
thanks bae ily
Sooo helpful🤗
Thx!
There's something wrong for number 2.. I know tan=opp/adj so definitely the answer is -√3/1
Piliin Jenna Mikah Briongos you’re looking at tan (pi/6). Please check again.
I love you for making this. Now I might not fail math class 🫀🫀🫀
So hard
reckonnn that’s what she said
Ur writing is so small
😮