Thank you your comprehensive video tutorial on how charge pumps and boost converters work, and the disadvantages of each type of DC-DC voltage boost cct. You have covered numerous important considerations in circuit design. Great job!
Really enjoyed this video in which you show your evolution in implementing V-boosts. Dealing with power systems (solar) has intrigued me with using boost circuits to draw more power from my small solar array. Ignoring the subtleties of charging modes, a low battery can actually double the current flow, balancing out the power flow for changes in irradiance, as well as a few other tricks can cause a meaningful boost to the energy captured. Inductors are simpler than capacitors and less prone to failure.....they are great storage devices.
thanks dude. this was the video i needed on charge pumps. your initial demonstration at the beginning was just the right thing to show for this to make sense.
Hey thanks a lot for this video,i've looked online for some useful charge pump circuits and came across some of the ones you showed, but the last one is by far the most practical one, despite it not being able to deliver much current.
This was great man. I am working on a charge pump system to bias photodetectors, and when i was plugging a load, the voltage was dropping drastically, but now i know why and how to fix it. Thank you.
Wow, I mean Great 👍. Finally someone speaking in favour of voltage multipliers. I have used them to create negative rail voltage for operational amplifiers
The step by step explanation of the Dickson pump is brilliant, it shows very clearly how the capacitors sort of "bucket brigade" their charge along the circuit
It seems counterintuitive to be able to boost voltage. Maybe it is a bit like increasing the PSI of the flow of water by changing the diameter of a pipe. In any case, thanks for making another great video.
It's more like using 2 hydraulic rams to lift a weight, and then only having one connected for letting it back down again. The same weight will force twice the pressure, but only half as much water.
On diagram 3:00 technically you could getaway with polarized capacitors, but if the load is low impedance or a short, they can be exposed to alternate current. Unless there's an extra diode
I tried a charge pump with 47uF caps and 25kHz using an Arduino Nano. I was only doubling the voltage from 5 to 10 (roughly), but when driving a MOSFET and gate driver IC the voltage would drop below 5.5, but I need it to be around 6.5V-10V to keep everything working well. Do you have any suggestions for how I can improve the voltage stability? You mentioned bigger caps in the video, but I'm worried about total current through the microcontroller as I don't want to burn it out. I have a couple transistors (I think P-channel but I can't remember), would it make sense to use a transistor or two instead of the MC to do the charge pump control and use bigger caps? If so, can you help me with a diagram please? Thanks!
@@Enigma758 the previous stage boosts it one more time when CLK goes high: First cap 5v when CLK low. Second cap 10v when CLK high (5v + 5v cap in series). Third cap 15v when CLK2 high (5v + 10v cap in series). Fourth cap 20v when CLK high (5v + 15v cap in series).
@@davadoff If you have a cap with one end grounded and charge it to 5v, it will stay at 5v even if you apply 5v to the positive terminal. The reason the voltage pump works is that after charging the cap, the negative side is boosted to 5v. Since the voltage across the capacitor can't change instantly, it now has a 10v potential relative to ground. That is not true for a smoothing cap which is permanently grounded. I just made a video demonstrating this in a falstad simulation, search for a youtube video titled Falstad voltage pump with smoothing capacitor. There you can see the output of the pump is around 18v and removing the smoothing capacitor only makes the output less smooth.
@@Enigma758 I understand it’s the negative side that gets boosted 5v. The third cap is charged to 15v when CLK is at 0v as per video, yes? Then what happens next when CLK switches to 5v? You’d have 5v + 15v in series, yes? If you simulated it and got more than 15v with or without diode losses then that proves I’m correct.
@@Enigma758 at the end of your 35s video it looks like the third cap switches between 15v & 20v relative to ground. Like I explained: the cap and clock voltage add up in series. Every time I say 10v/15v/20v I’m assuming ideal diodes are used; and I’m assuming you understand real diodes will cause a small voltage drop. Just to recap… at 5:39 the video has a correction saying 15v, and I’m saying: no, he was correct the first time, it’s actually 20v.
Better is to multiply ac than us for DC. To multiply DC you need more clocks means more connection of voltage. Depends upon where we need multiplication.
Because it divides the DC voltage in half. Notice that the first circuit uses 10V to achieve the +5V/-5V AC wave in order to work, whereas the second circuit only needs 5V. The second circuit avoids using AC, it just uses a 5V "clock" to produce pulsed DC.
Thank you your comprehensive video tutorial on how charge pumps and boost converters work, and the disadvantages of each type of DC-DC voltage boost cct. You have covered numerous important considerations in circuit design. Great job!
Thank you for watching! :)
chatgpt comment
Really enjoyed this video in which you show your evolution in implementing V-boosts.
Dealing with power systems (solar) has intrigued me with using boost circuits to draw more power from my small solar array. Ignoring the subtleties of charging modes, a low battery can actually double the current flow, balancing out the power flow for changes in irradiance, as well as a few other tricks can cause a meaningful boost to the energy captured. Inductors are simpler than capacitors and less prone to failure.....they are great storage devices.
thanks dude. this was the video i needed on charge pumps. your initial demonstration at the beginning was just the right thing to show for this to make sense.
Hey thanks a lot for this video,i've looked online for some useful charge pump circuits and came across some of the ones you showed, but the last one is by far the most practical one, despite it not being able to deliver much current.
I agree, just keep the current to a minimum. :)
This was great man. I am working on a charge pump system to bias photodetectors, and when i was plugging a load, the voltage was dropping drastically, but now i know why and how to fix it. Thank you.
Wow, I mean Great 👍. Finally someone speaking in favour of voltage multipliers.
I have used them to create negative rail voltage for operational amplifiers
I am so glad I found this channel! Great explanation! You have a gift for making complicated topics simple to understand.
Thank you! It's good to hear that my videos are helpful. :)
That’s exactly what I needed for a project I just built that is very low amps but needs 12 volts
It's the perfect circuit for that situation! :)
The step by step explanation of the Dickson pump is brilliant, it shows very clearly how the capacitors sort of "bucket brigade" their charge along the circuit
It seems counterintuitive to be able to boost voltage. Maybe it is a bit like increasing the PSI of the flow of water by changing the diameter of a pipe. In any case, thanks for making another great video.
Not really though because when you make the pipe thinner the thick part gets the higher pressure
Its exactly that, PSI = voltage, Flow = Power (W)
It's more like using 2 hydraulic rams to lift a weight, and then only having one connected for letting it back down again. The same weight will force twice the pressure, but only half as much water.
On diagram 3:00 technically you could getaway with polarized capacitors, but if the load is low impedance or a short, they can be exposed to alternate current. Unless there's an extra diode
GREAT Help! Learn something new.. inventor with two patents and on to the third! Thanks.. Roland
Thanks for the info!
I tried a charge pump with 47uF caps and 25kHz using an Arduino Nano. I was only doubling the voltage from 5 to 10 (roughly), but when driving a MOSFET and gate driver IC the voltage would drop below 5.5, but I need it to be around 6.5V-10V to keep everything working well. Do you have any suggestions for how I can improve the voltage stability? You mentioned bigger caps in the video, but I'm worried about total current through the microcontroller as I don't want to burn it out. I have a couple transistors (I think P-channel but I can't remember), would it make sense to use a transistor or two instead of the MC to do the charge pump control and use bigger caps? If so, can you help me with a diagram please? Thanks!
Could you please tell me what component model specs you used? Like the type of capacitors,diode. And what is the max current that can generate?
Could chage pumps be used as a circuit to verify if voltage transducers are reading voltage correctly? 300VDC transducer.
How’s it differ from ICs like MAX1044 or LT1054? They don’t fluctuate the same way?
I used charge pump for my class A power amp i had built years ago... To boost the voltage for pre amp part..
And Then there are the charge pump, that make use of mos switches to make 5V to +/÷ 10V in the Maxim patent, used in the MAX232
5:41 no, it is 20v out (with ideal diodes). The third cap = 15v with CLK low. When CLK next goes high you have 5v + 15v in series = 20v out.
No, the last capacitor acts as a smoothing capacitor since it is tied to ground, it is not in series with the output as the previous capacitors are.
@@Enigma758 the previous stage boosts it one more time when CLK goes high:
First cap 5v when CLK low. Second cap 10v when CLK high (5v + 5v cap in series). Third cap 15v when CLK2 high (5v + 10v cap in series). Fourth cap 20v when CLK high (5v + 15v cap in series).
@@davadoff If you have a cap with one end grounded and charge it to 5v, it will stay at 5v even if you apply 5v to the positive terminal. The reason the voltage pump works is that after charging the cap, the negative side is boosted to 5v. Since the voltage across the capacitor can't change instantly, it now has a 10v potential relative to ground. That is not true for a smoothing cap which is permanently grounded. I just made a video demonstrating this in a falstad simulation, search for a youtube video titled Falstad voltage pump with smoothing capacitor. There you can see the output of the pump is around 18v and removing the smoothing capacitor only makes the output less smooth.
@@Enigma758 I understand it’s the negative side that gets boosted 5v. The third cap is charged to 15v when CLK is at 0v as per video, yes? Then what happens next when CLK switches to 5v? You’d have 5v + 15v in series, yes?
If you simulated it and got more than 15v with or without diode losses then that proves I’m correct.
@@Enigma758 at the end of your 35s video it looks like the third cap switches between 15v & 20v relative to ground. Like I explained: the cap and clock voltage add up in series.
Every time I say 10v/15v/20v I’m assuming ideal diodes are used; and I’m assuming you understand real diodes will cause a small voltage drop.
Just to recap… at 5:39 the video has a correction saying 15v, and I’m saying: no, he was correct the first time, it’s actually 20v.
How much current available this circuit?
Better is to multiply ac than us for DC. To multiply DC you need more clocks means more connection of voltage. Depends upon where we need multiplication.
Whats the bgm?
Great Video☝️
Thank you :)
So we need sine wave to make it work
You need some sort of AC signal.
Impractical, unless that is you have a functionally limitless supply of 350v 130,000uf electrolytic capacitors.
I have like at least 2000 different capacitors of different sizes in my kit
1:32 "The voltage drop in the loudest place across it." What?
OK. Nice!. But you definitely have to improve your diction, because is very poor.
5:17 Why is it "better" to avoid virtual grounds and intermediate AC signals?
Because it divides the DC voltage in half. Notice that the first circuit uses 10V to achieve the +5V/-5V AC wave in order to work, whereas the second circuit only needs 5V. The second circuit avoids using AC, it just uses a 5V "clock" to produce pulsed DC.
7:52 Why "a couple hundred milliamps"? Why not more?