JEE Main Physics Optics #2 Young's Double Slit
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- Опубліковано 6 січ 2025
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In a young’s double-slit experiment the width of one of the slits is three times the width of the other slit. The amplitude of the light coming from a slit is proportional to the slit width. Find the ratio of the maximum to the minimum intensity in the interference pattern is:
A) 4:1
B) 2:1
C) 3:1
D) 1:4
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I did all the reasoning with the mean value of the integral etc to get the same result 😅
Good method.