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Example 2 - Chapter 8- Class 10 | Introduction to Trigonometry | NCERT Maths | CBSE
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- Опубліковано 15 сер 2021
- Example 2 : If ∠ B and ∠ Q are acute angles such that sin B = sin Q, then prove that ∠ B = ∠ Q.
In this tutorial, you will find the explanation of the following:
Example: 2
Class: 10th
Chapter: 8, Introduction to Trigonometry
Textbook: NCERT
#Class10Math #Class10Maths #TrigonometryClass10
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Sir The background And Your Explanation Is Too Good ✌✌🙏🙏👏👏👏👏👏
Thank you so much 😀
Thank-you for the great explanation sir! 2023-2024 batch
You are most welcome and thanks for appreciating my work. Please share it.
Watch complete chapter here: ua-cam.com/video/o1n-m0kWBGU/v-deo.html
Sir, instead of using sss , we can use sas becaus angle b and angle q both are 90 degree
Thanks sir you are tooooo good
Sir i have a doubbbt
Cannt we solve this ques by taking only single triangle for example ∆ABQ whichh would be easier is this method correct ???
If we take single triangle that would lead us to conclude that AB=AQ which means triangle is isosceles. Eventually this would mean angles are equal. But this question is about two triangles. Keep in mind that in general we never take triangles like ABQ. It is standard to use triangles like ABC and PQR. Hope this clarifies your doubt.
@@Mathemafia okkie thankk you sirr ❤️
Best teacher ever 🤗
Nice explaination sir...
Thanks for liking
Sir can you tell me some important questions of this chapter
Sir isko side Angel side s kar sakte hai ky Angel A = Angle p so jayega 90 degree and do side given h to by sas similarity Similar ho jayega then angle b Angel Q ke equal Ajayega , Kya esa kr Skte h sir ?
Sir hum Hypotenuse se Perpendicular ko divide kyo karenge plz tell
I would suggest to watch the tutorial again at slow pace. Pause and watch. You will get it.
Sir, u have explained it very well 🥰
But I have a doubt,
Instead of proving both the triangles similar, can we also prove them congruent by ASS property?
And then by Cpct *angle B = angle Q
I am going out for sometime. Will have a look when back home and then I will respond. Remind me if i do not get back to you by EOD.
I will make a separate video to explain it with SAS similarity. I will try to upload the video on Sunday.
But ASS is not a congruency rule
@@shwetaupadhyay824he meant SAS
Understood, thank you!
Sir are u a iitian?
I am a Thaparian and PU student.
Amazing sir
Thanks a lot sir🙏
Welcome
best video sir till i watch on youtube
Glad to hear that. Please share it 🙂
Jada fak mat
I understood clearly bro ... thanks
Welcome. Please share it.
Can we apply RHS theorem instead? Since this way is quite diffucult.
No, we can't. Actually it is kind of converse of RHS. In RHS, we use the result that we have to prove in this question. And that is, if sinA = sinB then A = B. But this is what we have to prove now so we need to follow a different path. I hope you got my point.
It is same given in ncert
Good
Nice explanation sir❤
Pls share
Thanks sir 😊
Welcome
Awesome
thankyouiii
Welcome
sir can we solve it using one triangle only like we did in ex 8.1 s 6th ques? it would be short and easy then ..
This question is about 2 triangles :)
Dhanayawad sir❤
Sir apne PBP / HHB kyo likha hai iska koi use hai kya sir
Watch this video completely to understand it. ua-cam.com/video/o1n-m0kWBGU/v-deo.html
After watching this video, watch this chapter from this link. www.mathemafia.com/class-10-chapter-08-all-solutions-introduction-to-trigonometry/
Sir please keep making study videos for us
Nice background ❤
𝓔𝔁𝓬𝓮𝓵𝓵𝓮𝓷𝓽 𝓮𝔁𝓹𝓵𝓪𝓷𝓪𝓽𝓲𝓸𝓷 𝓼𝓲𝓻👍
Thank you. How do you use this font?
Explain it without k pls
That outro 💀
Sir 4:55 - 5:30 tak ka samaj ni aaya
Ek baar fir se dekho. Slow speed pe, pause kar kar ke. Fir bhi na samaj aaye to batana.
Hello sir, I had a doubt.
Can I say that AC / AB = PR / PQ (Given)
Therefore, this can be rewritten as :-
AC / PR = AB / PQ ---- (1)
Also, In ∆ACB & ∆ PRQ,
Angle ACB = Angle PRQ (Both are right triangles, therefore 90°) ---- (2)
Therefore, from (1) and (2)
∆ACB ~ ∆PRQ by SAS
Therefore, angle B = angle Q (Corresponding angles of similar triangles are equal)
👆 Is this way correct? 👆
First of all Angle ACB and angle PRQ is not 90 degree.
Anyhow, SAS similarity means
1) Two corresponding sides are proportional
2) Angles in between these corresponding sides are equal
But here we do not know if the angle between the proportional sides are equal. Also the right angles are not in between the proportional sides.
Is it clear?
If you have any doubt - Watch this video to understand SAS - ua-cam.com/video/TKd6aaAqXvQ/v-deo.html
@@Mathemafia but sir, if ACB and PRQ are not 90° then how did we use Pythagoras theorem? It's only applicable for right angled triangles right
I understand the SAS point though, for it to be similar through SAS, the angle will have to be between the sides, right?
@@MotivationMindsConquer I think you are confused how to write an angle. If the right angle is at vertex A, then we write it as
@@Mathemafia yes sir, this is clear.
i was talking about how did we apply Pythagoras theorem if the angle in NCERT figure (
@@MotivationMindsConquer I would suggest you to watch the tutorial again. Pause it in between to understand it clearly. I am sure You will get it. Try once more.
Sir, instead of using sss , we can use sas becaus angle b and angle q both are 90 degree
Hi Kiran, I misinterpreted your query earlier. The SAS solution that you are seeking is not feasible because the angle is not in between the corresponding proportional sides. This way it is becoming SSA which is not a similarity criterion. However, we can use RHS Similarity Criterion which states that "'If in two right triangles, hypotenuse and one side of one triangle are proportional to the hypotenuse and one side of the other triangle, then the two triangles are similar."
Eventually what you are saying is correct and is a possible solution but only the similarity criterion will be RHS. But as RHS I hope this is clear now. I will make a video on this soon.