Thank you for reaching out!! I have a ton of SAT prep Videos on my channel: be sure to subscribe and check it all out! Also, if you’re interested in accessing the full version of SAT Crash Course, let me know and I’ll send you the link to access a special offer for my UA-cam viewers/subscribers…
Problem 36 is actually very simple: proportions: 360 is to 20pi as x is to 5.5 (or any number between 5 and 6), this leads to x about 31, (30 will be the answer if you use 5.454545454545
@candicem4014 sure! 20pi is the total circumference of the circle (remember C=2(pi)r… so if you know the length of the arc (anything between 5 and 6, I think we made it 5.5), then the fraction of the circumference is just (5.5)/20pi… Once you know the fraction. If the total circumference that the arc is, just multiply that fraction (or decimal) by 360 to find the Angle formed by an arc of that length. Make sense?
Good question!! You can use a surprising amount of logic and visual estimation in the Digital SAT, yes!!! Doesn’t work on every question, but works on many, if not most!
Ha! That’s ok!! I sometimes tell my students, “You need to ‘think dumb’ on the geometry questions”… sure there are some questions where you need to do a specific geometry operation, but that’s only true for maybe 1/3rd of the geometry questions on the SAT… the rest you can use visual estimation and common sense!
Yes! I have seen the values in the answer choices being closer together on some recent SATs, but still applicable to the majority of the questions that are drawn to scale… all of the questions that appear in the videos are from official SAT tests released by the College Board, the makers of the test…
But even if you choose to solve the questions using an operations-based approach, the correct answer still has to make sense visually, so at the very least you can use these methods to confirm that your operations are on the right track!
Thanks for reaching out, Rachel! The geometry operation on #30 is so crazy tough… it’s one of the most famously difficult questions on any SAT… basically you need to recognize that each interior angle inside the hexagon is 120 degrees using the formula 180(n-2) where in is the number of sides in a regular polygon. You get 720 degrees total divided by the number of sides, 6, giving you 120 for each interior angle. Then you divide the hexagon into 6 equilateral triangles (each angle being 60 degrees) and then dividing the equilateral triangles in half, giving you 12 different 30-60-90 right triangles… with me so far?
Then you need to realize that each of the twelve 30-60-90 right triangle in the hexagon have an area of 32 times the square root of 3, because (384/12 is 34) and then you use the ratios of the 30-60-90 right triangle and the area formula for a triangle to solves for the base of the triangles, and then multiply the base by 2 to get each side of the hexagon (you get 16). Because the side of the hexagon is the same as the side of the square, the area of the square is 16 times 16, which is 256.
![[November SAT Math] Everything You Need To Know - Geometry Full Review](http://i.ytimg.com/vi/3mjs5_0uWAk/mqdefault.jpg)
This is one of the best videos I have watched, it easily sinks in. I will love to have more of this.
Thank you for reaching out!! I have a ton of SAT prep Videos on my channel: be sure to subscribe and check it all out! Also, if you’re interested in accessing the full version of SAT Crash Course, let me know and I’ll send you the link to access a special offer for my UA-cam viewers/subscribers…
And let me know if you have any questions… Thanks!
Thank you so much for doing these!!
I’m so happy to help!!! Please let me know if you have any questions… Thanks!!
Problem 36 is actually very simple: proportions: 360 is to 20pi as x is to 5.5 (or any number between 5 and 6), this leads to x about 31, (30 will be the answer if you use 5.454545454545
That works! I’m down with anything that gives you the right answer!! Great job finding the solution!
you have done a great service to many students, congrat!
Thank you!! I’m happy to help!!
hey @hqs9585 could you explain why you used 20pi for your proportions
@candicem4014 sure! 20pi is the total circumference of the circle (remember C=2(pi)r… so if you know the length of the arc (anything between 5 and 6, I think we made it 5.5), then the fraction of the circumference is just (5.5)/20pi…
Once you know the fraction. If the total circumference that the arc is, just multiply that fraction (or decimal) by 360 to find the Angle formed by an arc of that length.
Make sense?
Your sub count is fire right now
Thanks for reaching out! That’s a good thing, right?
Wait, I get it now… Ha!
Is this still good to watch for the digital sat?
Good question!! You can use a surprising amount of logic and visual estimation in the Digital SAT, yes!!! Doesn’t work on every question, but works on many, if not most!
got it at the right name sat on 2nd october 2021 and watching it on 23rd july 2021
Best of luck on the test! Let me know if you have any questions... Thanks!
bro,tks for your help you have helped me so much.
Vinícius Oliveira Thanks for reaching out!! Let me know if you have any questions or if I can help in any other way!
I don’t feel particularly smarter after watching this, but atleast my nerves were calmed somewhat!
Ha! That’s ok!! I sometimes tell my students, “You need to ‘think dumb’ on the geometry questions”… sure there are some questions where you need to do a specific geometry operation, but that’s only true for maybe 1/3rd of the geometry questions on the SAT… the rest you can use visual estimation and common sense!
Anyway, thanks for reaching out, and let me know if you have any questions!
Are these methods still applicable on current Sat tests?
Yes! I have seen the values in the answer choices being closer together on some recent SATs, but still applicable to the majority of the questions that are drawn to scale… all of the questions that appear in the videos are from official SAT tests released by the College Board, the makers of the test…
But even if you choose to solve the questions using an operations-based approach, the correct answer still has to make sense visually, so at the very least you can use these methods to confirm that your operations are on the right track!
thanks for this nice video, helpful
I’m so happy to help!!! Please let me know if you have any questions!!
How do you calculate area and volume of a triangular figure with uneven side lengths?
To be perfectly honest, I’m not sure... but I’ve never seen a volume question like that on the SAT, so I wouldn’t worry about it!
As far as area of a triangle, here’s the formula:
Area = 1/2(base)x(height)
Let me know if you have any other questions... Thanks!!
do you have a way of downloading your matching document?
Shoot me an email at tooheycollegeprep@gmail.com!
thanks!!!!!!!!
I’m so happy to help!! Best of luck on the SAT!!
can someone explain how to do 30 with geometry 😭
Thanks for reaching out, Rachel! The geometry operation on #30 is so crazy tough… it’s one of the most famously difficult questions on any SAT… basically you need to recognize that each interior angle inside the hexagon is 120 degrees using the formula 180(n-2) where in is the number of sides in a regular polygon. You get 720 degrees total divided by the number of sides, 6, giving you 120 for each interior angle. Then you divide the hexagon into 6 equilateral triangles (each angle being 60 degrees) and then dividing the equilateral triangles in half, giving you 12 different 30-60-90 right triangles… with me so far?
Then you need to realize that each of the twelve 30-60-90 right triangle in the hexagon have an area of 32 times the square root of 3, because (384/12 is 34) and then you use the ratios of the 30-60-90 right triangle and the area formula for a triangle to solves for the base of the triangles, and then multiply the base by 2 to get each side of the hexagon (you get 16). Because the side of the hexagon is the same as the side of the square, the area of the square is 16 times 16, which is 256.
Or you could just use visual estimation and find the right answer in like 30 seconds, which is what I recommend.
@@MichaelToohey thanks so much! That makes a lot of sense. I did geometry back in 9th which got cut short because of covid so it’s really rusty.
You and half the world, Rachel… but don’t worry… you can use estimation, logic, and common sense all over this test even if your operations are rusty!