FANTASTIC Observation at HC Verma sir's Sopan Ashram by NMS Sir | Olympiad Level Problem
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- Опубліковано 11 чер 2024
- Recently NMS sir visited Kanpur. He met Dr HC Verma sir at his Sopan Ashram in Kanpur.
While sitting in the ashram, NMS sir thought about an amazing concept regarding gravitational force.
He though if he considered a hollow planet and a satellite at a distance r from the planet. if the satellite is illuminating the planet and a certain region of the planet is covered by the light of the satellite.
What will be the force exerted by the illuminated area?
What next, the vibe of the Sopan ashram of HC Verma sir, promoted him to find the answer and he got something very interesting.
He discussed the same with HC Verma sir and he agreed with the concept & calculations.
In this video, NMS sir will explain the same concept to you.
If you are a JEE aspirant or a physics lover you wish to solve core & fundamental problems of physics, this video is for you.
Check out the complete video and comment down you inputs on the concept.
#physics #jee2025 #jeeadvanced #physicsolympiad #olympiad #physicslovers #iitjee #hcverma #nmssir
NMS sir main apka fan hu main Physics JEE-NEET ko 15 salo se pada raha hu apke concepts jabardast note hain…….main kanpur (Panki) se hu……….mere ghar ke samne apke ek bahut old friend rahte hain jinka name Pankaj Chandel hai.
Me bhi panki me hu 👀
The Logic is right and hence the conclusion also. Its the same logic Newton gave to prove that in the interior of a hollow shell of mass M, the gravitational force would be zero.
Although keep up with the ideas. Only a thinking brain can produce thinking brains. So keep up NMS sir
Nice sir question from physics galaxy on similar concept
Eureka from archimedes😂❤❤
Down to earth hc verma 🗿
This result might be also possible for a charge and a ring system when charge kept out of the ring.
And vice versa for mass.
Isn't it Sir?
Awesome 💯, amazing explanation 😀
Dono sir really fantastic and intresting physics teachers
Thanks and welcome
@@NMSPhysicsISAC ek question doubt hai
Amazing
Hello sir,
I have a doubt. I hope that you will clear it.
Why em waves can not be deflected by external e.f & m.f
Really Fantastic .... 🎉❤
Really Cocacolastic .... 🎉❤
how dA = cr^2theta
Eureka nahi😂
Thekua moment 😊
Sir jaha light incident ho rahi h waha ka mass kam h but distance kam h mass m se toh ak probability h ki dono equal force ho❤❤❤
NMS sir the goat of physics ❤❤❤
But sir i have a doubt , u used Rd@ to find the radius of the small part of the sphere but how can u take it as a circle. Although its small but integrating it will make a difference
Kux samajh me toh nhi aaya magar sunn kar accha laga😂
God of physics for a reason ❤ thanks nms sir for affordable batches !
Welcome. Best wishes for future
Sir will your argument be valid for angle near the tangent, as the angle will no longer be normal to the area element.
You r really fantastic teacher.
Thank you! 😃
Hii sir
I have a question that in photoelectric effect, the photoelectric current doesn't depend upon frequency of incifent radiation. But Sir if we increase the frequency of incident radiation the the kinetic energy of emitted electron increases which means the fastly reach at collector plate so time will decrease and current should be increase in that case ? Please sir explain kar do ek baar bhit confusion hoti ha isme.
inversely distance square waale forces ki maths mein saara khel solid angle ka hai kyuki solid angle mein bhi distance square aata hai. inversely proportional to distance hota to inki maths ka sara khel plane angle ka hota.
❤
Sir, what proportion surface area will get lit of a spare if a point source emitting light is seprated by some finite distance from spare? Would not it be 50% of surface area. Same analogy is here.
Fun fact: Iss comment par jo jo click karega toh usse ek mavic dikhega
Considering a sphere to be maximum bulged at the equater, light will reach at all points of max bulge in front of it. That is exactly half part of the sphere. Therefore mass of that part would be M/2. Considering that the force of attraction comes out to be (G*M/2*m)/r^2.
But sir, if you consider the point (source of light) very close to sphere then how the half part of the sphere will be enlighten?
At that scenario the process of NMS sir is correct.
King
Ashish Arora sir has solved similar question to prove electric field zero inside shell to be zero, in advanced illustration.
He proved that by same solid angle method
Yes, you are right.
Newton shell theorem hai woh ander ke liye waise hi hota hai newton ne diya tha baahar ke liye kisi ne nhi kiya
@@NMSPhysicsISAC 👍👍
Really sir ,aap physics ke sath jite hai,wah wah
@@NMSPhysicsISAC yes sir exactly , I think he also want say ashish sir used the same theorem given by newton to prove that.
Respected sir, I m neither a student nor a teacher. But I like to study physics. I am struggling to solve infinite grid equivalent resistance problem in irodov. Please help and give a suitable concept to solve such types of problems.
sir isko aap kya pakka keh sakte hain? kyoki aisa proof maine gauss law ke liye dekha hai par uss case mein area ka dot product liya jata hai yaani uska component perpendicular to position vector liya jaata hai. Toh fir waha par angle ka tension nahi hota, but yaha par bhi angles equal honge ye bolna muskil lag raha hai dA1 aur dA2 ke liye
Olympiad corner
Seriously sir it is good but it can solve easly using logic
Right
maza aa gya sir
Glad to know this
Eureka eureka i got u sir
Sir❤ jab samne pura ka pura body pada hai to fir vo kisi dusre body par fraction of force kyu lagayeega?? Ha theoretically dimag ka dahi banane ke liye thik hai. Baki practical se iska koi lena dena nahi hai
Natwarlaal of physics
potential jee question in future
Can come
Aur sb to thik isme mjedaar kya h. Kya h Bhut suprising
Don't just confine physics to JEE and JEE teachers....
At PhD level. ..we all think about these things...and already thought of this.
bhai 17 saal ke aur 23 saal ke insaan ke dimaag mei farq hoga naa
Koi bhut bada physical significance to deekh nhi rha h
Mr sir is best