🟡05 - Limit and Continuity of Functions of Two Variables

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  • Опубліковано 2 лип 2024
  • In this lesson we shall look at continuity of functions of two variables.
    A function of two variables is said to be continuous at a point (a, b) if the function satisfies the following three conditions, if
    a. f(a,b) is defined
    b. lim f(x,y) as (x,y) approaches (a,b) exist
    c. if lim = f(a,b)
    00:00 - Introduction
    03:30 - Ex 1
    06:10 - Ex 2
    11:00 - Ex 3
    13:17 - Ex 4
    15:10 - Ex 5
    18:36 - Ex 6
    25:10 - Ex 7
    Playlists on various Course
    1. Applied Electricity
    • APPLIED ELECTRICITY
    2. Linear Algebra / Math 151
    • LINEAR ALGEBRA
    3. Basic Mechanics
    • BASIC MECHANICS / STATICS
    4. Calculus with Analysis / Calculus 1 / Math 152
    • CALCULUS WITH ANALYSIS...
    5. Differential Equations / Math 251
    • DIFFERENTIAL EQUATIONS
    6. Electric Circuit Theory / Circuit Design
    • ELECTRIC CIRCUIT THEOR...
    7. Calculus with Several Variables
    • CALCULUS WITH SEVERAL ...
    Make sure to watch till the end.
    Like, share, and subscribe.
    Thank you.

КОМЕНТАРІ • 76

  • @user-pn4zq8dq1t
    @user-pn4zq8dq1t 8 місяців тому +7

    Can’t thank you enough. My maths professor make these seems so difficult and i was really struggling to catch up.

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  8 місяців тому +3

      Awww sorry about that. But finally, you understand now. Thanks for watching and commenting to show your appreciation.
      Tell me where you come from?

    • @HussainShah-tr8yz
      @HussainShah-tr8yz Місяць тому +1

      ❤❤❤

  • @makyzainelabdin
    @makyzainelabdin 7 місяців тому +2

    Thank you for your beautiful explanation. It helped me a lot in understanding mathematical problems. I did not understand anything from the book after your explanation. I understood, thank you very much 👏🏻👏🏻

  • @TheForgottenOne1
    @TheForgottenOne1 9 місяців тому +2

    Your a genius! Life saver!!

  • @manavsood6020
    @manavsood6020 7 місяців тому +3

    concept crystal clear
    i don't know why in every other vidio i watched in yt every one is doing 0/0=0 which is creating big confusion

  • @blurzzbee
    @blurzzbee 4 місяці тому +2

    thank you so much sir, i can finally understand how to do it now

  • @chriscadag3374
    @chriscadag3374 5 місяців тому +1

    This video is very helpful. Thanks to this, i was able to understand our lesson

  • @SkanCityAcademy_SirJohn
    @SkanCityAcademy_SirJohn  8 місяців тому +2

    Right answer for Q4,
    step 1: g(1,2) = 0,
    step 2: lim of (x^2 + 4y) as x,y approaches 1,2 = 9,
    step 3, since value for step 1 is not equal to that of step 2, the function is not continues at (1,2).

  • @agirl8369
    @agirl8369 3 місяці тому +2

    thank u for this clear explanation

  • @SamNITP
    @SamNITP 3 місяці тому +2

    sir I am from India love you so much sir you are gem

  • @muchimwanamwila5259
    @muchimwanamwila5259 11 місяців тому +2

    Thank you so much

  • @surendrakverma555
    @surendrakverma555 Місяць тому +1

    Very good. Thanks 🙏

  • @mughal___hu-------yara
    @mughal___hu-------yara 2 місяці тому +1

    Billions and trillions of thanks ♥️

  • @AkhilaChirumamilla-kc2dg
    @AkhilaChirumamilla-kc2dg 6 місяців тому +1

    Thank you so much.... Actually I have exam in 2 days... And I cleared one of my confusing topics...

  • @NeolAlemu-jp2fl
    @NeolAlemu-jp2fl 8 місяців тому +2

    Your video is really helpful can't thank you enough, the explanation s very clear too u are a great teacher trust me keep it up❤ live long mister but if you have worked examples on level curves and graphs of several variables please
    Baay'een sitti gammade ulfaadhu!!!!!!!!! replay me soon

  • @rohitpurkait1969
    @rohitpurkait1969 5 місяців тому +1

    Thank you so much sir

  • @yassjobe6764
    @yassjobe6764 11 місяців тому +2

    Your video is really helpful can't thank you enough, the explaination s very clear too u ar a great teacher trust me keep it up❤

  • @amhakabaw
    @amhakabaw 7 місяців тому +1

    Tnx sir🙏🙏 your video is help full me

  • @muzzammilyousuf2265
    @muzzammilyousuf2265 Місяць тому +1

    What if the question also stated that also find whether is function has removable discontinuity?
    How will we determine this?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Місяць тому +1

      Since the limits along different paths are not the same, the limit does not exist.
      Because the limit does not exist uniformly, this discontinuity is not removable.

  • @Myles_.webster
    @Myles_.webster 8 місяців тому +2

    Your videos are very helpful, but l am a bit stuck as to where l should actually use the polar coordinate approach, how do l necessarily know that it applies here.

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  8 місяців тому

      It comes by experience, you can't really tell, but then as you solve more and more examples, you get to know where exactly to use it.
      Thanks so much for your words of appreciation.
      Where do you watch me from?

  • @alexandra-amaliacodreanu4700
    @alexandra-amaliacodreanu4700 10 місяців тому +2

    why wasn't polar coordinates used in the first and you used them in the second and third?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  10 місяців тому +2

      polar coordinates were not used in Ex 2 and 3, but rather Ex 6 and 7. In addition i want to understand that you want to ask why eg 1 was quite simpler as compared to 2, and 3. Eg 1 is a polynomial function in x and y, hence it is continuous everywhere, however for eg 2 and 3, we have a rational function, a rational function is continuous everywhere except where the denominator is zero making the whole function undefined, at that point, the function is discontinuous.

  • @peaceofmind9775
    @peaceofmind9775 Рік тому +1

    when do we use the polar coordinates method?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  Рік тому +1

      You can use it anytime, just that that approach does not also confirm the limit of the function...

  • @NelumboNucifera-gh1pe
    @NelumboNucifera-gh1pe 3 місяці тому +1

    Sir in the last question why polar coordinates were used?can we do it by approaching x axis,y axis,y=mx?????how to know when to use polar coordinates?

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  3 місяці тому +2

      yes you can approach the limit point from different directions. In fact you can choose to use polar coordinates all the time, but it's usually dependent of the question. I feel with much experience gathered as a result of constant practice, you will know the best approach to use, because sometimes approaching from different directions will help you to get the results faster

  • @zeraiikhlass1184
    @zeraiikhlass1184 6 місяців тому +1

    i don't understand why u didn't use the HR in the first example.

  • @emeldahowell8668
    @emeldahowell8668 4 місяці тому +1

    Is It okay to put it as (r,theta) approaches (0,0)

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  4 місяці тому

      Kindly reference the time in the video for easy identification of your question

    • @emeldahowell8668
      @emeldahowell8668 4 місяці тому +1

      24.44 -25.30
      Instead of just writing r->0 is it correct to have it as (r,theta)->(0,0)

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  4 місяці тому

      @emeldahowell8668 yes please, you can

    • @emeldahowell8668
      @emeldahowell8668 4 місяці тому

      @@SkanCityAcademy_SirJohn Thankyou

  • @frankkalobwe107
    @frankkalobwe107 8 місяців тому +1

    For example 4, why did you refer to (0,0) and not (1,2)

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  8 місяців тому +1

      you are perfectly right, i was supposed to reference (1,2) and not (0,0), that was a mistake from my end. Thanks so much for notifying me.

    • @thespaceagent3991
      @thespaceagent3991 5 місяців тому +1

      could you go through that part in another video?@@SkanCityAcademy_SirJohn

    • @SkanCityAcademy_SirJohn
      @SkanCityAcademy_SirJohn  5 місяців тому

      Noted