How to find Square Root of Complex Number
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- Опубліковано 7 вер 2024
- Square root of negative numbers leads to complex numbers. They can be represented on Polar coordinate or Argand diagrams. We will discuss, in details, operations and representation of complex numbers in this playlist.
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Your explanation was extremely clear and easy to follow. Thank you for taking the time to make such a fine video. I will be looking for others that you have done.
At 1:45 how b²i² is equal to -b²??
@@tcs20264 hopefully your question has been answered but I^2 = sqrt(-1) so if i square a square root it cancels so it's just negative 1 so b^2i^2 =b^2(-1) = -b^2
You have explained very well in comparison to other you tubers. . I liked this way a lot.. THANKING YOU 😎
Fantastic explanation. I am trying to help my niece with her maths tests. This is really going to help. Thank you so much for posting.
Thanks. Here is related Playlist: ua-cam.com/video/prH82IUcLfI/v-deo.html
you are really helping us. thanks sir!
Thanks for appreciation
thank you this was very helpful!
Thank you Prof. Anil Kumar. I was a little bit confused about taking square root of a complex number , but now it is clear to me.
explained this lesson in perfection. thank you very much and yes the result with the imaginary number being substituted is very interesting
Thanks a lot for appreciation
Very good explanation thanks for clearing doubts
love your voice. Great teacher
This explaination was better than the ones they gave at school zzz
Thank you so much you have helped me alot
We got a^2+4=0
a^2=-4 (as i^2=-1)
We can replace a^2=4i^2
And a=+-2i.
So we got imaginary number +-2i
thanks that was very very helpful to me
thanks much Sir. I'm confused about the second equation in question 1.
I thought it is supposed to be. 2ab=-12?
please I'm begging you to clarify me how the - sign disappeared in front of 12.
Exactly why I'm reading the comments, I don't know what made the sign to disappear
Thank you, its beneficial for complex analysis
Nicely explained....
Thank you sir.
Thanks. Playlist on Complex Numbers: ua-cam.com/video/prH82IUcLfI/v-deo.html
you can also convert it to phasor form and find the square root of that then convert it back to complex
yo this was a perfect lesson! Thanks so much bro
Thanks teacher iam very happy now😀,
Acroding to before watching this vedio
I get i get iget
this was an amazing explanation, thank u so much anil!!!
Thank you sir
Thanks for appreciation
perfect, cheers
Great explanation prof. Thanks
Although the result may be interesting, isn’t the reasoning up until you sub in values of (a) to get values of (b) only valid if (a) and (b) are real? In other words, a^2 +4 cannot be factorised over the real plane, and thus the other result although coincidentally correct, uses invalid logic to acquire it.
thank you
Thank you very much sir, your explanations are clear and concise. I comprehend the relation between imaginary and real numbers better now.
How to find the square root of Andrew kolita ?
Thank you, very clear and concise video !!
Awesome
Thank you so much sir, I was at a loss with why the square root of complex numbers have 2 values, when real numbers only have one. Thank you so much sir
At 1:45 how b²i² is equal to -b²??
@@tcs20264i is the square root of negative one so if you have i^2 that's equal to negative one
@@ghotifish1838 oh. Thnkz
this is so cool!!! thank you for making this video!
Thank you!
well explained
Nice explanation🥰🥰🥰🥰
Helpful
nice and to the point explanation sir thank U
where did the i go from abi when u separated the two equations at 2:13
Superb! Thank you.
how do you find the absolute value of a complex number that has both a numerator and a denominator
Sir at 4:45 , square of (a) cannot be equal to (-4), as square of any no. cannot be equal to any negative no.
Technically we do not need to considerthe imaginary solutions of a=2i and a = -2I as z = sqrt(5-12i) = a+bi, where a and b are real numbers.
I have 5 minutes left in class of taking this test and this damn video is 9 minutes longggggg
Nice!
Thank you so much
How do we solve the question - Find All Roots of (1 - i)1/4?
Your written letters look more standard font than my typed ones.
I saw on byjus, they told that +- in front of the bracket will not come.
This was great! Can you do this using Euler’s formula?
NNNNOOOOOOOO
Nahh it's a representation of a complex no.
Nice
amazing explanation and very calming voice! :)
Thanks
At 1:45 how b²i² is equal to -b²??
find the square root of (a to the power 2) +(1/a to the power 2) + 4 i (a+1/a)-2
Sir I want to know the square root of 1-i in form of x+iy.. please teach
Try some questions from this video: ua-cam.com/video/prH82IUcLfI/v-deo.html
Thanks
4:37 where is the square root symbol ? it should be a=+- squareroot 3
I think it should be 2ab=-12.
That's my worry too. thank God you also saw this....
he corrected it later in the video
@@cedriclow28 oh okkkk
@@cedriclow28 thanksss
2ab=-12??
Solve the equation w^2=1+i............how do i solve this question.thank you
Very nice explanation. There's one doubt though. When you got the values for 'a' after solving the equation, how did you decide which value is complex and real? Because I get different answers when I did a = 3i and a = 2, instead of what you did.
At 1:45 how b²i² is equal to -b²??
@@tcs20264 since I=√-1 so i^2 would be √-1×√-1 which is -1 so (bi)^2 =b^2×-1
=-b^2
Thank you sir.love your work
Thank you so much Sir!😃😇
Wow u saved me thanks
Check few more questions on this: ua-cam.com/video/prH82IUcLfI/v-deo.html&list=PLJ-ma5dJyAqqImxqXhid9SQxjMyTOx4zj&index=4
Thanks
How did you directly found out that sir.
😅😅
I have to write factors and then find.
Please reply.
a^2 - 9 = 0, you may factor and then get the answer
or you can use -3 and +3 with experience.
Soon yo will also write it directly.
Thanks
Ok sir.
Thanks.
Cant i use the (a^2 + 4 = 0)? give me some explaination
he did a^2+4 =0 can factor into (a+2i)(a-2i) which he did use
Well explained. I like it.
I don't get it how u find a and b
Lol
is there any short trick for this if it is then plz upload sir
yea there is
just split the complex number in a perfect square as the square of a complex number can be represented as a^2 - b^2 +- 2abi
the given complex number in the video 5 - 12i can be written as 9 - 4 +2(3)(2)i which is 3^2 - 2^2 - 2(3)(2)i which is (3-2i)^2 so you get the answer directly in like 15 seconds
Thanxx sir,,, its so qualitative explanation,,,..🙏🙏🙏
use Euler's formula
No sir i want ask that how to choose the value between a=+-3 and a=+-2 for futher calculation after factorization of the equation
Thanks, will make a video for you in this regard. Thanks
I have a confusion sir
Is it nessesary to take the first value of a as real number and if yes so the second value is always a imaginary number isit?
We started with a + bi, so b is the imaginary part and a is the real part. a = 3 or -3; Find b for these values. to get the result.
Later half is showing that the result will not change even if you use a as 2i. Ignore it, if it creates confusion.
Thanks
Which pen do you use???
Will share with you soon. Thanks
Here you can see the Pens: ua-cam.com/video/2H55P6mMBL0/v-deo.html
Thanks
@@MathematicsTutor Thanks alot !!!!
Sir why did u took a=2i why not a=3i
a^2 + 4 = 0 gives that result. Thanks
Because it's square root of -4
👌👌👌👌👌👌👌👌
2ab=-12 not 12
I have used 2ab = -12 only.
Hope that is ok
Thanks
Find the sqroot of (1+i) without using quadratic formula?
How you got a=+_2i?
Its real part
ans: {+ - (3+2i) , (-3-2i)} is that correct?
I’m in 6th grade and doing this lol
Keith Carden same, it's easy
find the square root of complex number
\sqrt{8 + 6i}8+6i
how he did it at 4:18
Take a^4 as k^2 and a^2 as k which forms a quadratic equation. After you solve it input the original values..
😭😭😭😭 this helped so much but my answer is still wrong. I officially quit. 😂😂😂😂
Sierra Fairbanks don’t give up keep trying you will get it eventually
False
thank you sir
Thank you