The Gradient in Polar Coordinates

We derive the form of the gradient in polar coordinates.
#MikeDabkowski, #ProfDabkowski, #mikethemathematician , #calc3

[@guilherme_719]

Saudações do Brasil! 🇧🇷
Em nosso país, não temos muitos materiais no UA-cam de tão boa qualidade como seu vídeo. Continue com o canal. +1 inscrito.
Obrigado e sucesso com o canal.

[@mikethemathematician]

@guilhermeandrade4954
Obrigado! Visitei o Brasil há dez anos para visitar amigos em Belo Horizonte. Você tem um lindo país!

[@Okrst12398]

Marvelous! Finally a channel simply explaining clearly and without fluff and at a reasonable speed.

[@mikethemathematician]

Thanks @borisk8372 I am going to make videos on orthogonal curvilinear coordinates soon! That will generalize this result!

[@장성진-k9g]

Crystal clear...
You are gifted!!!!

[@mikethemathematician]

Thank you very much! I always am willing to take requests for video topics! I plan on making videos that generalize this idea: how to compute the gradient in orthogonal curvilinear coordinates!

[@sgiri2012]

Sir, my humble request is would you please take me separate class for me on tensors ?

[@midul1690]

Thanks a lot sir...❤

[@mikethemathematician]

@midul1690 sure thing! 👍

[@andreaduranti8541]

What if f is a function of x and y and x and y are functions of r and theta?

[@mikethemathematician]

Great question! The tree flips and you can use the same idea!

[@armanavagyan1876]

PROF UR growing is mater of time)

[@mikethemathematician]

Thanks Arman! I have lots of ideas for future videos too!

[@armanavagyan1876]

PROF tan^(-1) x =? Arctan(x) =? 1/tan(x) thanks)

[@mikethemathematician]

tan^{-1}(x) = arctan(x), but these are not 1/tan(x) which is cot(x).

[@armanavagyan1876]

@@mikethemathematician thanks PROF UR very clear)