Geometric Meaning of the Gradient Vector

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  • Опубліковано 21 січ 2025

КОМЕНТАРІ • 280

  • @destreme9189
    @destreme9189 9 місяців тому +30

    My professor rambled on for 2 hours and I didn't understand anything. Here you are explaining it perfectly in 15 minutes. THANK YOU SO MUCH

  • @RyanMcCoppin
    @RyanMcCoppin 2 роки тому +119

    I was very confused when people said the gradient was "normal" to the curve. I thought they meant the function itself, not the "level curve". Now it makes complete sense! Thanks!

    • @juanbautistasoria757
      @juanbautistasoria757 11 місяців тому

      Same!

    • @sumittete2804
      @sumittete2804 11 місяців тому

      Is rate of change of function minimum in the direction of tangent vector or in the direction opposite to gradient vector ?

    • @Suyogya77
      @Suyogya77 11 місяців тому +2

      ​@@sumittete2804 rate of change of the function is minimum in the direction of the tangent vector i.e. in you move perpendicular to the gradient vector

    • @sumittete2804
      @sumittete2804 11 місяців тому

      @@Suyogya77 But if i move opposite to gradient vector i.e 180° I'm getting rate of change of function as negative which is less than 0. Moving along tangent vector the rate of change of function is zero. So how ??

    • @Suyogya77
      @Suyogya77 11 місяців тому

      @@sumittete2804 do you use telegram or something?

  • @PantheraOncaTV
    @PantheraOncaTV 9 місяців тому +2

    Man, you really teach what's important to understand the concepts, and you explain yourself perfectly! Amazing! You've gained a new subscriber 😁

  • @peterfriedman4912
    @peterfriedman4912 4 роки тому +13

    Thank you so much. I read my textbook and understood about half of this material and watched this video a couple of times and now understand the gradient vector much better. You really helped me.

    • @DrTrefor
      @DrTrefor  4 роки тому +1

      Glad it was helpful!

  • @engrfawadiqbalkhan786
    @engrfawadiqbalkhan786 2 роки тому +9

    I am a civil engineer , now a days I am pursuing master's in structural engineering ,in structural engineering we use these concepts to find maximum stresses/strains , Before this video I tried a lot but couldn't get into the depth of concept but after watching this video ,I got the concept of it ,animations are very helpful .thankyou and keep up the good work.

  • @9888565407
    @9888565407 4 роки тому +88

    dude I love ya. that cleared everything about gradients in my mind. Thanks a lot bud.

    • @DrTrefor
      @DrTrefor  4 роки тому +21

      Glad it helped!

  • @rafidahmed2796
    @rafidahmed2796 Рік тому +5

    I usually don't comment on videos but that's the best explanation i've ever watched to understand... i had this confusing for a long time and this lecture cleared that up! you deserve more subs!

  • @Anonymous-nz8wd
    @Anonymous-nz8wd 4 роки тому +8

    I have never seen such a beautiful explanation ever of Gradients love you

  • @alkankondo89
    @alkankondo89 4 роки тому +14

    Great derivation and application! The derivation of the gradient-vector formula and its justification were both quite easy to follow!

  • @dustincondon5557
    @dustincondon5557 4 роки тому +22

    Beautifully presented! It's such a cool topic, and using mountains as an analogy makes everything so intuitive.

  • @zukofire6424
    @zukofire6424 2 роки тому +1

    had seen the videos pop up in the search results and never found the time to have a look. Now just did : I'm a fan! Thanks Prof. Bazett! :)

  • @sadpotato5111
    @sadpotato5111 3 роки тому +3

    It is a wonderful thing to see your passion about mathematics, I'm assure you it is contagious and I love you because of it. I wish best for you with my all heart. Please do continue to make videos like that.

  • @Conorstew
    @Conorstew 4 роки тому +2

    My new favourite video of yours, the mountain example was great :) You taught me calc1 at Uvic last year and now you are teaching me calc 3. A true godsend, thanks Trefor!

    • @DrTrefor
      @DrTrefor  4 роки тому +1

      Thanks Conor, really appreciate that. Good luck with math 200!

  • @user-wu8yq1rb9t
    @user-wu8yq1rb9t 3 роки тому +1

    Of course I enjoyed it.
    For better understanding of the Gradient, I searched this subject, fortunately, I saw you and I just clicked!
    Thank you so much

  • @liuqing1995
    @liuqing1995 3 роки тому +4

    The great combination of theory and a real example of a mountain in Vancouver. I enjoy the lesson series of Calculus so much.

  • @walac
    @walac 4 роки тому +5

    Best math channel on UA-cam!

  • @johnnytoobad7785
    @johnnytoobad7785 3 роки тому +38

    Man if my college calculus profs. were as articulate as Dr. Bazett..I would have gotten better grades in those classes. I'm now a retired software "geek" and really love watching these presentations. Very few folks who understand advanced math (and EE-Comp Sci) are good at teaching it to "undergrads". Of course I love the animations also.

    • @codstary1015
      @codstary1015 Рік тому

      Couldn't agree more, lot of lectures I have i can barely understand what they are trying to present. It's pretty funny that a you tuber can present ideas in a much more clear and straight forward matter.

    • @focusmaestro4013
      @focusmaestro4013 Рік тому +5

      @@codstary1015 LOL, Its pretty naive of you to assume that Dr.Trefor is just another youtuber!

  • @chernihivka
    @chernihivka 3 роки тому +6

    great videos, Trefor, I have been looking for the explanations with geometrical insights vs just algebra on the board. This really helps to "see" the math. thanks!

  • @hope-wq9jd
    @hope-wq9jd 2 роки тому +4

    after visualizing these concepts it became easier for me to perform the mathematical formulas thank you so much sir for the valuable information

  • @ikarus1060
    @ikarus1060 3 роки тому +4

    Ahhh, finally I fully got it, thx man:) The map help a lot. I knew what gradient is, but i strugled to get the geometric meaning

  • @Party21304
    @Party21304 2 роки тому +1

    This video is spot on! Very nice. You just clarified gradient, level curves and the directional derivative in an intuitive way. I know understand the meaning behind the math. Thank you so much!

  • @wildertapiasaenz2333
    @wildertapiasaenz2333 9 місяців тому

    I found myself really “down the rabbit hole” with this concept because it just doesn’t mean anything until you visualise it. Your videos really helped me, thank you 🙏

  • @cheerlasunny2123
    @cheerlasunny2123 2 місяці тому

    The example at the end really helped a lot in getting the concept , such a great explanation , I can't thank u enough.

  • @aln4075
    @aln4075 11 місяців тому +1

    this video is one of the greatest one's that you can find on this topic

  • @maani315
    @maani315 4 роки тому +1

    Your demonstration is just amazing Sir....the best explanation of gradient vector on UA-cam....

  • @ManojKumar-cj7oj
    @ManojKumar-cj7oj 4 роки тому +7

    Thank God I found this channel 🙌

  • @at6727
    @at6727 4 роки тому +3

    you'll make us love calculus and maths!!
    thanks for including practical example of Vancouver island

    • @DrTrefor
      @DrTrefor  4 роки тому +1

      haha I had fun with that part!

  • @rizalpurnawan23
    @rizalpurnawan23 4 роки тому +3

    Amazing lecture!
    It essentially proves the notion that the gradient is orthogonal to the level set.
    Thanks a lot Sir Trefor.

    • @DrTrefor
      @DrTrefor  4 роки тому +3

      You are welcome!

    • @sumittete2804
      @sumittete2804 11 місяців тому

      Is rate of change of function minimum in the direction of tangent vector or in the direction opposite to gradient vector ?

    • @carultch
      @carultch 11 місяців тому

      @@sumittete2804 The direction of the gradient tells you the direction of steepest ascent, and the magnitude tells you the slope of that ascent. Opposite the gradient vector, is the direction of steepest descent.
      The rate of change of the function is minimized, if the input point travels perpendicular to the gradient vector. The contour lines are perpendicular to the gradient vector.
      The principle behind Lagrange multipliers comes from this idea. Given that the point in question follows a constrained path, the candidates for the local extreme value of the function's output will occur when the path and the contour line, share a common direction.

  • @MAYANKGUPTA-c2r
    @MAYANKGUPTA-c2r 2 місяці тому

    Sir, you taught the topic deeply and with real life application...I think now I become your fan❤
    Thank you sir.

  • @AS-ix3qd
    @AS-ix3qd 4 роки тому +3

    my mind is blown, finally I understand how the tangent unit vector gives a direction along which f(x,y) is constant, Thx alot Dr.

  • @milesborowsky8140
    @milesborowsky8140 4 роки тому +1

    This is awesome. You're uploading right as I'm learning this material in class, and it's super helpful. I'm a math and education major too - this is such a great conceptual explanation. Thank you!

  • @tanayasharma7776
    @tanayasharma7776 4 роки тому +1

    my favorite math teacher on youtube

  • @nicogovindsamy9022
    @nicogovindsamy9022 4 роки тому +1

    This video is amazing. First time I'm seeing these concepts clearly since I started taking this course.

  • @minnngb
    @minnngb 2 роки тому

    i have been looking for a video to help me understand directional derivatives and the gradient for a week and this one was the most helpful!! the visual examples are amazing :)) thank you

  • @agotaopposits
    @agotaopposits 5 днів тому

    Thank you so much, I struggled with understanding why is the gradient vector pointing in the direction of the fastest increase, but now I think I get it:))

  • @HPLovecraftsCat9
    @HPLovecraftsCat9 2 роки тому +3

    Thank you for this video. You are a very clear example of the fact that you don't need 3Blue1Brown levels of visual editing in order to explain something intuitively and clearly.

  • @habilismayilov838
    @habilismayilov838 Рік тому +1

    Amazing explanation!!!! thank you so much, you make great influence in the world..

  • @electricalabc3411
    @electricalabc3411 3 роки тому +2

    Example of a mountain was superb to explain gradient..thanks bro

  • @bimankalita2960
    @bimankalita2960 Рік тому

    I wish there was the option of giving more than one like. Superb explanation!

  • @joliettraveler
    @joliettraveler 3 роки тому +1

    Fantastic explanation. Now I understand the gradient for our purposes lies in the xy plane and that it points into the mountain.

  • @gibs40
    @gibs40 Рік тому

    This channel is truly underrated

  • @Indik47
    @Indik47 Рік тому +2

    Excellent explanation

  • @shivarapolu3180
    @shivarapolu3180 3 роки тому +1

    understood the beauty of multivariable calculus and gradient operator. Thanks a lot sir :)))

  • @joaomattos9271
    @joaomattos9271 Рік тому

    Fantastic way of teaching!!! I recommend the classes here in Brazil!

  • @alfonsorodriguezruiz9007
    @alfonsorodriguezruiz9007 Місяць тому +1

    Thank you professor for the Golden Hinde application.

  • @KaviPriyan-qt6vc
    @KaviPriyan-qt6vc 4 роки тому +4

    I am doing all possible steps to take this channel to a bigger audience

    • @aarushi5570
      @aarushi5570 2 місяці тому

      i talked about him to an audience of about 150 people!!

  • @LinLin-rs2bv
    @LinLin-rs2bv 3 роки тому +1

    Great video that gives a brilliant straight explanation for the gradient vector. Hope to have your class in UVic.

  • @ishraqhossain1235
    @ishraqhossain1235 4 роки тому

    your bio says you try to do "evidence based pedagogical practices". This is just beautiful man. Hope you come up with more intuitive calculus videos

  • @rupaupadhaya8888
    @rupaupadhaya8888 3 роки тому +3

    This video is really helpful. Thank you so much,👏

  • @sergiolucas38
    @sergiolucas38 3 роки тому +2

    excellent video as always, nice example :)

  • @RSS18
    @RSS18 3 роки тому +2

    Perfectly explained. Thank you sir

  • @lakshitha99
    @lakshitha99 3 роки тому

    Best math channel. Massive respect. Thank you sir..❤️

  • @olehborys1462
    @olehborys1462 Рік тому +1

    great example, thank you for your video

  • @itsnadchaos
    @itsnadchaos 4 роки тому +3

    amazing and so interesting! keep it up

  • @chrismarklowitz1001
    @chrismarklowitz1001 Рік тому +1

    I like to think of the normal vector to the contour plot as the shortest distance between two points is a straight line. And when the distance between them next contour is infinitesimal. It is a parallel line. And anything other than normal is going to be more than just going normal.

  • @TheWildStatistician
    @TheWildStatistician Рік тому

    Absolutely fantastic explainer! Way to go!

  • @xiliu3526
    @xiliu3526 11 місяців тому +1

    Such a brilliant video, it truly heps

  • @khandkertiashazad6858
    @khandkertiashazad6858 4 роки тому +3

    At 8:39, shouldn’t you say 0 slope instead of minimum slope? I think you get the minimum slope when theta is -π

    • @sumittete2804
      @sumittete2804 11 місяців тому

      Yess....Rate of change of function is minimum in the direction opposite to gradient vector that is at angle of 180°

  • @subhajitbarman4672
    @subhajitbarman4672 4 роки тому +1

    Such a clarity in your explanation....thank you so much sir, you cleared my hardest doubt...😊😊❤❤😊❤❤❤

  • @viniciusdeobber8239
    @viniciusdeobber8239 2 роки тому

    Great video, made it easy to understand. Thanks, professor Trefor!

  • @shashankjhaa6221
    @shashankjhaa6221 2 роки тому +1

    Love your teaching sir...""LOVE""

  • @busrraengin
    @busrraengin Місяць тому +1

    Thank you ,for the video. It was a great explanation.

  • @maximlavrenko1164
    @maximlavrenko1164 2 роки тому +2

    rewatched it several times, started losing hope but then it clicked and I was like 'wait that makes sense!'

  • @julioreyram
    @julioreyram 4 роки тому

    Brilliant explanation again :). It would be very good if you linked the previous explanations, i.e., the tension vector.

  • @anikethdesai
    @anikethdesai 6 місяців тому

    2:36 I don't get what f(x,y) is wrt r(t). Like, do you mean to say you slice a mountain, take its cross-section, then the f(x,y) is built on it which is at a height C from r(t) on the z-axis such that f(x,y) is also a level curve?

  • @Diphothara03
    @Diphothara03 Рік тому

    A legend is living among us!!!!!!!!!

  • @dienosorpo
    @dienosorpo 2 місяці тому +1

    So clever haha, loved the explanation

  • @TheEmad619
    @TheEmad619 4 роки тому +1

    thank you so much for clearing the doubt. The video was very helpful.

  • @scratchyourhead2383
    @scratchyourhead2383 3 роки тому +1

    Thank you sir ❤! You are clearing my such deep buried doubts .

  • @glax3198
    @glax3198 2 роки тому

    4:00 anyone knows how he moved from the "sum of two things multiplied" to the dot product of two sums?

  • @wildertapiasaenz2333
    @wildertapiasaenz2333 9 місяців тому

    Also really important how you pointed out grad f as in the x-y plane as that also can be very confusing initially thinking about it as the gradient itself but of course that’s why we need 😊

  • @quynhngadau5482
    @quynhngadau5482 5 місяців тому

    Great illustration, thank you!

  • @optimistprime6741
    @optimistprime6741 2 роки тому +1

    You’re literally perfect

  • @yizhang7027
    @yizhang7027 3 роки тому

    10:15 how do you determine which directions are positive for the two vectors?

  • @Festus2022
    @Festus2022 8 місяців тому

    @9:00 Why wouldn't the smallest magnitude be at 180 degrees where
    COS -theta would be minus- 1?

  • @rickgrimes47
    @rickgrimes47 3 місяці тому +1

    I cannot thank you enough kind sir.

  • @2005airplane
    @2005airplane 7 днів тому

    I am not sure if I understand about the direction of gradient. How can a gradient be living in the x,y plane and yet point to the direction of maximum ascent or descent which is in z direction?
    The gradient is going inward or outward but is in x,y plane still. If this is because of flattening of z on to x,y plane on a 2-d contour map then once we expand it back to 3-d map, shouldn't the direction of gradient also change to align with z as we go back from 2-d to 3-d?

  • @BoZhaoengineering
    @BoZhaoengineering 3 роки тому +2

    The Geometric element is fascinating. But the algebraic dot product provide a solid conclusion.

  • @shubhamvadagave8961
    @shubhamvadagave8961 3 роки тому +1

    Great explanation! Thanks alot

  • @pawanadhikari110
    @pawanadhikari110 4 роки тому +1

    Absolute trivial explanation.

  • @Festus2022
    @Festus2022 8 місяців тому

    Why is the magnitude of the gradient vector said to be the RATE of maximum ascent? When I see "rate", I think slope. Why isn't the rate of ascent simply the partial of y divided by the partial of x.? Isn't this the slope of the gradient....i.e. change in y over the change in x? What am I missing? thanks

  • @alejrandom6592
    @alejrandom6592 3 роки тому +1

    Awesome video!

  • @peterpetrov4867
    @peterpetrov4867 3 роки тому +1

    Great video!!! Is this one part of a series? How do we know the order in which to watch these great videos?

    • @DrTrefor
      @DrTrefor  3 роки тому +1

      Yup, check out the links in teh description, have a whole multivariable playlist:)

  • @continnum_radhe-radhe
    @continnum_radhe-radhe 3 роки тому +2

    Sir ,please recommend me a mathematics book for engineering, and for gate and IIT jam exams.

  • @nickknight5373
    @nickknight5373 4 роки тому +1

    Very well-explained.

    • @DrTrefor
      @DrTrefor  4 роки тому +2

      Glad you think so!

  • @somanathdash3153
    @somanathdash3153 3 роки тому +2

    Oh god it helped me so much thanks sensai

  • @youssefdirani
    @youssefdirani 3 роки тому

    Super thanks Dr.
    May you be blessed

  • @continnum_radhe-radhe
    @continnum_radhe-radhe 3 роки тому +2

    Thanks a lot sir 🔥🔥🔥

  • @ahmadwael8541
    @ahmadwael8541 10 місяців тому

    thanks a lot for the great explanation

  • @Niglnws
    @Niglnws Рік тому

    13:30 is important.
    Del f is into the mountain which is still normal to the curve and it is logical as del f components are in i and j directions.
    We move in x and y and the result is change in z which the magnitude of the gradient tells us.

  • @muktasane6046
    @muktasane6046 2 роки тому

    Thanks so much it helped me understand the gradient concept.

  • @LS-oh6po
    @LS-oh6po Рік тому

    Good afternoon Fellow mathematicians, could you please help? There is a function of two variables. I need to find its minimum. I start from a certain point. Next, what is the minimum search algorithm? For example: an increment of one variable is taken, a function is considered, we look - less or more than the previous step. Further we take an increment by the same change or another? Or it is necessary to take an increment at once of two variables?

  • @divcurl
    @divcurl 4 роки тому +1

    @Trefor Bazett - another great video! And another question from me regarding the gradient pointing perpendicular to level curves/surfaces. I can't see 'intuitively' why the gradient should be perpendicular to a level surface. To use your mountain analogy. Let's say that I am standing at a point on a contour on a mountain, and I'm 'designing' the mountain, can't I just pick a direction that's not perpendicular to the contour as the direction of steepest ascent?
    And second question, is there a way of 'intuitively' seeing why the grad vector points in the direction of the maximum rate of change? To me it is quite a surprising fact - I can't actually see intuitively why this should be the case without going through the algebra. Am I meant to be surprised by this or is there a way that makes this intuitively obvious?

    • @jiachen8353
      @jiachen8353 4 роки тому

      hey I think you can but this is where you have to use lagrange multiplier to find the max. which you can determine in witch you go is the steepest. I mean I maybe wrong, but this is what I think.

  • @anandita166
    @anandita166 4 роки тому +2

    thankyou so much! this one's great!!🌟

  • @RobertWF42
    @RobertWF42 4 роки тому +1

    I've read conflicting definitions of the gradient vector. Sometimes it's a normal vector perpendicular to the tangent plane at point P on a surface. In other definitions the gradient is a vector pointing "downhill" and lies *within* the tangent plane.

    • @DrTrefor
      @DrTrefor  4 роки тому +1

      The issue is whether we are talking about the gradient of f, where z=f(x,y), or the gradient of F where F(x,y,z)=f(x,y)-z. The former gives a 2D vector in the x,y-plane (note: not the tangent plane), while the latter gives the normal to the surface

    • @RobertWF42
      @RobertWF42 4 роки тому

      @@DrTrefor @Dr. Trefor Bazett Thank you, this is a helpful clarification!
      The method of Lagrange multipliers matches the grad f directions for two functions, correct? And I think statistical or machine learning methods that use gradient descent to find solutions for data modeling also utilize grad f, not grad F.

  • @wowlilo29
    @wowlilo29 3 роки тому

    Does any know in 5:32 why the tangent goes along the curve?
    Great Video. Simple and understanding.

  • @henriqueserra3233
    @henriqueserra3233 7 місяців тому

    what if the normal vector of dr/dt was pointing in the other direction?... I mean, the vector that makes 180 degres with the gradient vector is still normal to the tangent, but it does not point in the direction of maximum slop, what does that mean?

  • @maureenhamilton7460
    @maureenhamilton7460 4 роки тому +1

    Does the gradient point to the top of the mountain? In your diagram your gradient pointed to a 'local max' but you would have needed another gradient to actually reach the top?

    • @DrTrefor
      @DrTrefor  4 роки тому +1

      The gradient lives in two dimensions, i.e. it is a direction on a map. It doens't have an up/down component.

  • @anthonymaione8307
    @anthonymaione8307 Місяць тому

    so with a with the gradient we can determine the most optimal way to climb up the mountain? For example the rate of climb?

  • @arnavgupta7392
    @arnavgupta7392 8 місяців тому +1

    Please can anyone explain me why the gradient is orthogonal to the contour of the curve? Thank you for such a nice video

    • @TelepathShield
      @TelepathShield 19 днів тому +1

      The dot product of the gradient with the tangent line is 0, meaning that the angle between the two is 90°, and since the tangent goes along the curve, the gradient points away at a 90° angle, or in other words is orthogonal to the contour of the curve