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Proper recovery...!
Don't listen to the haters. People can make respectful and constructive comments without the spite.
Analyze the equation!!What is obvious? X must be negative. One root follows and using synthetic divisionthe other two appear. Analyze before solving.
The solution x=-1/2 doesn't satisfy the equation x=x+1
x=-2; or x=(3+i*V15)/2; or x=(3-i*V15)/2.
You have done the right thing brotherly.You are on point, ride on.
Ya lo sé, X= -2.
12= (-2)^2×3=x^2×(1-x)So x=-2
x^3-x^2+12=0 , by faktoring , add 6x , -6x , x^3+2x^2 -3x^2-6x +6x+12 = 0 , -> (x+2)(x^2-3x+6)=0 , x+2=0 , x=-2 , test , (-2)^2 - (-2)^3 = 4+8 , 4+8=12 , OK , /// for complex , x^2-3x+6=0 , x= (3+i*sqrt15)/2 , (3-i*sqrt15)/2 , /// ,
Too long for nothing! Check with that divide 12!
Noted sir
my goat
Proper recovery...!
Don't listen to the haters. People can make respectful and constructive comments without the spite.
Analyze the equation!!What is obvious? X must be negative. One root follows and using synthetic division
the other two appear. Analyze before solving.
The solution x=-1/2 doesn't satisfy the equation x=x+1
x=-2; or x=(3+i*V15)/2; or x=(3-i*V15)/2.
You have done the right thing brotherly.
You are on point, ride on.
Ya lo sé, X= -2.
12= (-2)^2×3=x^2×(1-x)
So x=-2
x^3-x^2+12=0 , by faktoring , add 6x , -6x , x^3+2x^2 -3x^2-6x +6x+12 = 0 , -> (x+2)(x^2-3x+6)=0 , x+2=0 , x=-2 ,
test , (-2)^2 - (-2)^3 = 4+8 , 4+8=12 , OK , /// for complex , x^2-3x+6=0 , x= (3+i*sqrt15)/2 , (3-i*sqrt15)/2 , /// ,
Too long for nothing! Check with that divide 12!
Noted sir
my goat