Le Chatelier Lab ANSWERS: Fe3+ and FeSCN2+ Equilibrium
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- Опубліковано 22 сер 2024
- In the equilibrium between Fe3+ (a yellow ion in aqueous solution) and FeSCN2+ (a brown ion in aqueous solution), what are the effect of...
* Adding KSCN
* Adding Fe(NO3)3
* Adding heat, or cooling down
* Adding NaCl, Na2HPO4, NaOH, NH3
* Adding AgNO3
All of these can be answered with Le Chatelier's Principle.
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Thank you ! My college labs are based on this. AMAZING explanation.
this is exactly what I needed for my chem lab report. thank you so much.
thank you, I have an upcoming lab on very similar compounds, after watching your video I feel a lot more confident.
Na2HPO4 has HPO4(2-) as the anion, not HPO4(-)! Prepare better next time. You're responsible for what you present to the audience. Thanks.
Does the Fe3+ concentration ever change when we add KSCN- into the equilibrium mixture. As concentration of SCN- on the reactant side increases, according to Le Chatelier principle, the concentration of SCN- on the product side should decrease, no ? so overall the fe3+ concentration should remain unchanged ?
Great work my Guy
If it is not given whether a reaction is endo or exo then how we would check ? please answer .
when u heat it or cool it it goes either left or right... it depends on the change. when u heat it, it goes against the heat side
Awesome dude! Keep up the good work
why is the FeNCS ion not wrtten as FeNCS3 due to the criss cross method?
What happens when we add oxalic acid
I hope someone replies to this but I have a question to make. In the problem of NH3, OH and NaCl, we did we apply this to the reactant side instead of the product? Does this only apply because the solution has a cation? so anions tend to react instead of having no effect?
These are generally things you're ADDING into the solution which is already at equilibrium.
Things that go INTO the solution and react generally go on the reactant side.
What happens if you add H2O?
Molar concentration will decrease due to increase in volume and the equilibrium shifts towards left(backwards as the concentration is to be compensated by the product) le chatliers principle
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Cool....
thanks dude
Mand was here