there is another way for solving the question,, lets say the ordered triplet say (a,b,c) satisfies abc=1. let without loss of generality a>=b>=c then a^3>=abc=1 => a>=1, now a^3(b+c)=3*1/(2*a^4).. now for a=lower bound=1 the RHS is max=3/2.. hence LHS
Great explanation! The trickiest part is the step where we need to apply Titu's lemma
there is another way for solving the question,, lets say the ordered triplet say (a,b,c) satisfies abc=1. let without loss of generality a>=b>=c then a^3>=abc=1 => a>=1, now a^3(b+c)=3*1/(2*a^4).. now for a=lower bound=1 the RHS is max=3/2.. hence LHS
Thanks for such a helpful video.
Superb vdo. Pls make a series for olympiad
I think the answer is 63.
Yep
How can I take ur Inmo batch sub
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