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Awesome!
Thanks!
Amazing 🤩
Thanks for watching!
Wow they didn't put the bracket near n + 1 so I solved this in different way. My problem becomes 2^n-1 (n + 1) is a perfect square. My solution is n = (4^k) - 1 where k is any positive integer.
Yeah I believe in the original problem they didn't include any brackets either, so I decided to keep it that way:)
Awesome!
Thanks!
Amazing 🤩
Thanks for watching!
Wow they didn't put the bracket near n + 1 so I solved this in different way. My problem becomes 2^n-1 (n + 1) is a perfect square. My solution is n = (4^k) - 1 where k is any positive integer.
Yeah I believe in the original problem they didn't include any brackets either, so I decided to keep it that way:)