Differentiating sec(x), cosec(x) and cot(x) : ExamSolutions Maths Revision

Revising how to differentiate the trigonometric functions sec(x), cosec(x) and cot(x)
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[@gloss1138]

thank you so much this was very helpful

[@thebulletkin8393]

When you have -(cosx)^-2, how did you get from that to 1/cosx? I see no way you could have gotten there.

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[@lingmeowww1147]

Thanks

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That's okay. I am pleased to hear it helped.

[@GeeGeeGweppo]

Hey sir,
I'm a bit lost at this part. 5:26. Basically on the first part you got 1/cos(x) correct since you split it from -(cosx)^-2
Then for the second part you get -1/sin(x) and its the same apart from -(sinx)^-2 so i'm not sure which one is right? i hope i'm making sense and you can help me out. Why does 1 have a negative sign and the other doesn't?
I have a feeling the second part is correct and it should be -1/cos(x)
Please respond when convenient for you.
Kind Regards

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aw man why'd no one help u out😭

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[@sahiltarkase9130]

Thanks Sir

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[@amoschoo938]

thanks for showing how to do it. i had no idea how to derive all these formulas because i was forced to memorise in school

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Pleased to hear it helped.

[@sababsalam4570]

-2
why dy/dx=-[cos x] ?

[@flowerpower487]

Sir is this c3?

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C3 for most boards

[@flowerpower487]

Thanks again sir.