How to Make SO2 Measurements for Your Wine.

Sulfur dioxide is the most important additive for your wine and has the largest impact on wine quality. It has antimicrobial and antioxidant properties that protect your wine from spoilage. In this video, I discuss some of the basic information about SO2, to better understand what you are doing when protecting your wine and I demonstrate the Ripper method and the calculations necessary for estimating the amount of SO2 in your wine.

[@markspc1]

Great video. It reminds me of chemistry class in college.

[@grantcramer]

Yes, it is chemistry or biochemistry!

[@uttamkumarchetia6935]

THANKS

[@grantcramer]

You're welcome!

[@WOWTECH0]

Many Thanks, Sir. I will use this method to measure the SO2 gas that I generated from acidified Na2S2O5 solution. The generated gas will be collected in a gas sampling bag. Since this is a gas phase analysis, I was wondering if you could guide me on how to modify the procedure in my case to measure the free SO2 gas.

[@grantcramer]

I am sorry Yasi, I am not knowledgeable enough to know how to do that. You might want to seek out a chemist. I am a mere plant physiologist. Sorry!

[@WOWTECH0]

@@grantcramer I appreciate your time and consideration. Sure, I will try to find an answer to it. Good content. Thanks, Sir.

[@oarfish29]

hello! do you mind giving the concentrations of H2SO4, NaOH, and iodine solution in mol? I’m a slightly confused highschool student. Thank you!

[@grantcramer]

Hi Manuela. Ok let's talk a little chemistry. Molarity is the number of moles in a liter. Normality is the number of equivalents in a liter. Equivalents are based on charge. So for NaOH, Na+ has single plus charge and OH- has a single negative charge. So in this case, 1 Normal NaOH equals 1 Molar NaOH. H2SO4 has two charges or equivalents per molecule, thus 1 N H2SO4 equals 0.5 M H2SO4. In our case we are using 25% of concentrated H2SO4. Concentrated H2SO4 is 18.4 M, thus 25% of that would be 4.6 M or 4.6 moles per liter. Now for the Iodine solution. The iodine solution was made from KI, so 1 N KI equals 1 M KI. Since the iodine solution we used was O.O2 N and it is equal to 0.02 M. Therefore there are 0.02 moles of iodine in a liter or 20 mmoles in a liter. Hope that helps! :)