Sochne Ka Tarika EP- 5 | England Olympiad Question | IIT JEE 2025 | Anshul Singhal
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- Опубліковано 7 лют 2025
- Sochne Ka Tarika EP- 5 | England Olympiad Question | IIT JEE 2025 | Anshul Singhal
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This series is designed to help students prepare for the JEE 2025 exam with a unique approach to solving problems and teach students how to think effectively " ab sab questions honge click"
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Episode 1 - • Sochne Ka Tarika EP-1 ...
Episode 2 - • Sochne Ka Tarika EP- 2...
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New SKT Video agaya hai
Sir aise hi SKT aur fundas laate rahiye. Prob solving me help krti
Haan bilkil
sir 16:19 we will square both side & then we will take c^2 in denomiantor & Apply AM-GM then restore back the sin alpha.
Ans to question at end is : x = tan^-1 (x)
Soln of last prob
tan(2x)=c/3 , tan(x)=2/c
tan(2x)tan(x)=2/3
2t²/1-t²=2/3==> 2t²/1=2/(3+1) [CND]
TAN(x)=1/2 x=tan-¹(.5)...
Thank u guruji assuming coordinates is such an amazing approach... 🎉
Haan uska answer shayad 1/2 sin invoice(0.8) hai
@anshul8330 haa sir maine calc pr dekha dono ki value same aa rahi hai...
26.56505° aa rahi h...
@jeeaspirant7210 Wohi hai
Sir please upload relevant videos. I request you to make jee main pyq videos of last few years chapterwise. Plz atleast 5 chapter ke upload kar dijiye before jan attempt 2025.
Pnc, probability, AOD, Straight Lines, Vector 3D
PYQ aap khud solve karoge to jyada benefit hoga. They are already available on Google.
My solution for the first problem:
let the smaller angle be theta,we have:
90 deg > theta > 0
90 deg > alpha > 0
also:
tan(alpha + theta) = 2tan(theta) ---- (1)
Let tan(alpha) = y and tan(theta) = x;
Rearranging 1, we get:
2yx^2 - x + y = 0
Now since theta is in the first quadrant, tan theta is positive and hence the roots are real.
D >= 0 gives us:
y^2 s is sin(alpha)
s^/(1-s^2)
That looks good.
Sir ji har jgah har unacademy ke batch me bol diya hu ke anshul sir ka 12 batch 15 jan se aarha hai isse aur bhi bacche aayenge padhne
Problem question ans tanx=1/2
Yes
Sir please" nichoda method (of integrals)"ko bhul mat jaiyega.
Use daal denge kisi SKT video mein. Please share the video to help our little channel.
@anshul8330 already shared in group :)
Sir ab batch laa bho do ab rha nhi jata😂
Sir UA-cam par course aya ga kay
Bhai acadza UA-cam channel ke community par form fill karo class 12 ke batch ke liye for 2026
x=tan^-1(2/(root11))
I think 1/2 (sin inv (0.8)) hai
@@anshul8330 Haan sir, aaya
On further simplifying sin(a)
Sin(a) = 1/ (c²+ 4/c² +5)½
Applying AM≥GM on (c² + 4/c²) maximum value is 4
Hence
Sin(a) ≤ 1/(4+5)½
Or
Sin(a) ≤ 1/3
@@Supp12345 Haan ye achha socha aapne...Mein nahi soch raha tha tab
@xpyre9796 exactly
Very beautiful
Sir aap koi batch development par focus karte... please 🙏
@SATYAM-W7Early 12,th and ek 11th wasted batch aa raha hai
Video share kar do bro
Sir ji sahi me batch aa rha kya 12 ka
Sir ji discount kar dena thora 😅
Sir are you launching a batch for jee advanced after January mains?
Yes
Bhai acadza UA-cam channel ke community par form fill karo class 12 ke batch ke liye for 2026
Sir ji video bana ke information du na ke batch aa rha hai 12 ka early ka aur bhi bacche jane ge
Haan Bhai...Video banaunga.
@anshul8330 ji sir
In last step multiply in denominator and divide Num/Den by c and apply am gm c² +4/c² +5 >= 9
But will that work? Do alag alag terms mein AM GM? Ya fir chaaro mein mila kar?
@saketkumar- Haan you are right.
Bhai log sir batch la rhe hai bhai log
Sir ji 12 ka batch aa rha kya kitne ka hai price bata do
9999
Thank you sir but tbh it was easy sir
Pls bring tough Q and amazing fundae 😀
Funda 18 came.
Mains nazdeek hai is wajah se too tough question par nahi jaa raha hun...Chalo very soon kuchh tough laata hun
@@anshul8330 these videos are so good , im so thankful to the senior who recomended your channel to me
@@notsumittt Glad to hear. Please share with others to help our small channel.
Sir ji batch ka kab announce kar rhe hu
Soon. Bola na 9k
@anshul8330 mtlb sir prices hai 9000 na
@@FizaRizwan-zg3qp Subscriber base 9k hoga tab.
Koi x bhi bata do kitna aaya?