Acadza - Anshul Sir
Acadza - Anshul Sir
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Generating Functions: Funda 27 | JEE Permutations & Combination | JEE Mains & Advanced | Anshul Sir
Generating Functions: Funda 27 | JEE Permutations & Combination | JEE Mains & Advanced | Anshul Sir
Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6
what's Next After JEE 2025 Mains - forms.gle/Q8CHFUFwdXRbc3K7A
Telegram link - t.me/acadzaanshulsir
Funda Playlist - ua-cam.com/play/PLdTg6lE1EV8a3RoJ0adaeRiBmKkgd7KUR.html&feature=shared
SKT (Sochne ka Tarika) Series - ua-cam.com/play/PLdTg6lE1EV8ZcmI8GhoGsk783xPpO6FxE.html&feature=shared
In this lecture, Anshul Singhal Sir explains Important question of Jee generating functions | Jee Important Question | Jee Question for JEE Mains & Advanced
This is the 27th Funda lecture in the popular Funda Series
Don’t miss out on more valuable lessons-subscribe to the channel for updates!
Keywords-
JEE Permutations & Combination
generating functions
generating functions jee
maths short trick
maths concept jee
jee important question
anshul singhal maths class 12
anshul singhal unacademy
anshul singhal Funda 27
anshul singhal maths unacademy
#funda #permutationsandcombinations #jee2025mains #funda27anshulsir #jeetoughquestion #anshulsirmaths #pw #jee2025 #jee2025preparation #jeemaths
Переглядів: 2 359

Відео

Carpet Theorem: Funda 26 | Short Trick | JEE Important Question | JEE Mains & Advanced | Anshul Sir
Переглядів 3,7 тис.4 години тому
Carpet Theorem: Funda 26 | Short Trick | JEE Geometry Important Question | JEE 2025 | Anshul Sir Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 what's Next After JEE 2025 Mains - forms.gle/Q8CHFUFwdXRbc3K7A Telegram link - t.me/acadzaanshulsir Funda Playlist - ua-cam.com/play/PLdTg6lE1EV8a3RoJ0adaeRiBmKkgd7KUR.html&feature=shared funda of the day (don't miss this)- ua-cam.co...
JEE Pyq Trap! Beware Ep 3 | 99% did WRONG! JEE 2025 | Anshul Sir
Переглядів 7 тис.7 годин тому
JEE Pyq Trap! Beware Ep 3 | 99% did WRONG! JEE 2025 | Anshul Sir Telegram link - t.me/acadzaans... Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 In this lecture, Anshul Singhal Sir explains Important Question (Trap) asked in JEE mains 2021| Anshul Sir explained the Correct method to solve these type of questions Beware Series is Important for all JEE Main & Advanced Aspiran...
JEE vs 3Blue1Brown: SKT Ep-15 | Probability Important Question | JEE Mains 2025 | Anshul Sir
Переглядів 9 тис.9 годин тому
JEE vs 3Blue1Brown: SKT Ep-15 | Probability Important Question | JEE Mains 2025 | Anshul Sir Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 3blue1brown video - ua-cam.com/video/OkmNXy7er84/v-deo.htmlsi=jDq5-H6lriyXZJHA Telegram link - t.me/acadzaanshulsir Watch the Other Episodes of SKT Series Episode 1 - ua-cam.com/video/NpOyb83c3Lc/v-deo.htmlfeature=shared Episode 2 - ua-c...
Matrices Maut ka Khel: SKT Ep-14 | JEE Important Question | JEE Mains 2025 | Anshul Sir
Переглядів 3,6 тис.14 годин тому
Matrices Maut ka Khel: SKT Ep-14 | JEE Important Question | JEE Mains 2025 | Anshul Sir Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 Telegram link - t.me/acadzaanshulsir Watch the Other Episodes of SKT Series Episode 1 - ua-cam.com/video/NpOyb83c3Lc/v-deo.htmlfeature=shared Episode 2 - ua-cam.com/video/ij22Vd51Qdc/v-deo.html Funda Series by Anshul Sir Playlist - ua-cam.com...
Euler's totient function: Funda 25 | JEE Important Question | JEE Mains 2025 | Anshul Sir
Переглядів 8 тис.14 годин тому
Euler's totient function: Funda 25 | JEE Important Question | JEE Mains 2025 | Anshul Sir Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 Telegram link - t.me/acadzaanshulsir Funda Playlist - ua-cam.com/play/PLdTg6lE1EV8a3RoJ0adaeRiBmKkgd7KUR.html&feature=shared SKT (Sochne ka Tarika) Series - ua-cam.com/play/PLdTg6lE1EV8ZcmI8GhoGsk783xPpO6FxE.html&feature=shared In this lect...
Introducing Parent Dost App: Help your Child Succeed in IIT JEE & NEET Exam | Anshul Sir
Переглядів 52516 годин тому
Parent Android - play.google.com/store/apps/details?id=com.acadza.parent Parent ios - apps.apple.com/in/app/parent-dost/id6739706825 Student Android - play.google.com/store/apps/details?id=com.acadza.acadzadost Fill the Form for Anshul Sir Courses - forms.gle/eQmjnSkxEqCpHQgi6 Discover the ultimate tool for JEE aspirant parents - the Parent Dost App! Stay connected with your child's preparation...
Khatarnak Trap! Sns: Beware Ep 2 | Bonus Marks in JEE Mains 2025? | Anshul Sir
Переглядів 7 тис.21 годину тому
Khatarnak Trap! Sns: Beware Ep 2 | Bonus Marks in JEE Mains 2025? | Anshul Sir
No of Equivalence Relation: Funda 24 | Bell Number | JEE Mains 2025 Important Question | Anshul Sir
Переглядів 6 тис.День тому
No of Equivalence Relation: Funda 24 | Bell Number | JEE Mains 2025 Important Question | Anshul Sir
Scoring Short trick: Funda 23 | Straight Lines | JEE Important Question | JEE 2025 | Anshul Sir
Переглядів 4,5 тис.День тому
Scoring Short trick: Funda 23 | Straight Lines | JEE Important Question | JEE 2025 | Anshul Sir
JEE Mains 2025 Important Instructions | Do's & Don'ts | NTA JEE Guidelines | Umesh Sir
Переглядів 901День тому
JEE Mains 2025 Important Instructions | Do's & Don'ts | NTA JEE Guidelines | Umesh Sir
Eigen Values JEE Important Question | Sochne ka Tarika EP-13 | IIT JEE 2025 | Anshul Singhal
Переглядів 4,1 тис.14 днів тому
Eigen Values JEE Important Question | Sochne ka Tarika EP-13 | IIT JEE 2025 | Anshul Singhal
Mains Vs Advanced Real Difference! | Sochne ka Tarika EP-12 | IIT JEE 2025 | Anshul Singhal
Переглядів 3,1 тис.14 днів тому
Mains Vs Advanced Real Difference! | Sochne ka Tarika EP-12 | IIT JEE 2025 | Anshul Singhal
Definite Integration Probable Questions | JEE Important Question | JEE Mains 2025 | Anshul Sir
Переглядів 3,5 тис.14 днів тому
Definite Integration Probable Questions | JEE Important Question | JEE Mains 2025 | Anshul Sir
Functions Secret Trick: Funda 22 | JEE Important Question | JEE Main & Advanced | Anshul Sir
Переглядів 12 тис.14 днів тому
Functions Secret Trick: Funda 22 | JEE Important Question | JEE Main & Advanced | Anshul Sir
LOCUS Masterclass | Straight Lines JEE Mains & Advanced | Anshul Singhal
Переглядів 3,9 тис.14 днів тому
LOCUS Masterclass | Straight Lines JEE Mains & Advanced | Anshul Singhal
Beware Ep 1: Probability Mistake | JEE Main & Advanced | Anshul Sir
Переглядів 4,9 тис.21 день тому
Beware Ep 1: Probability Mistake | JEE Main & Advanced | Anshul Sir
⚠️Important Announcement | JEE Batch Announcement | Anshul Singhal
Переглядів 1,4 тис.21 день тому
⚠️Important Announcement | JEE Batch Announcement | Anshul Singhal
Sochne Ka Tarika EP- 11 | Advanced Quadratic Question | IIT JEE 2025 | Anshul Singhal
Переглядів 4 тис.21 день тому
Sochne Ka Tarika EP- 11 | Advanced Quadratic Question | IIT JEE 2025 | Anshul Singhal
Binomial Cheat Sheet | Binomial Summation All Formula | JEE Main & Advanced | Anshul Singhal
Переглядів 8 тис.21 день тому
Binomial Cheat Sheet | Binomial Summation All Formula | JEE Main & Advanced | Anshul Singhal
Funda 21: SWAG! BHIKHARI! JALLAD! | Quadratic Important Concept | JEE Main & Advanced | Anshul Sir
Переглядів 3,9 тис.21 день тому
Funda 21: SWAG! BHIKHARI! JALLAD! | Quadratic Important Concept | JEE Main & Advanced | Anshul Sir
Sochne Ka Tarika EP- 10 | Matrix ki Badi Power! Matrices Question | IIT JEE 2025 | Anshul Singhal
Переглядів 8 тис.28 днів тому
Sochne Ka Tarika EP- 10 | Matrix ki Badi Power! Matrices Question | IIT JEE 2025 | Anshul Singhal
Funda 20: NICHODA! Integration Question | JEE Main & Advanced | Anshul Singhal
Переглядів 3,7 тис.28 днів тому
Funda 20: NICHODA! Integration Question | JEE Main & Advanced | Anshul Singhal
Sochne Ka Tarika EP- 9 | Ullu Mat Bano! Sequence & Series Question | IIT JEE 2025 | Anshul Singhal
Переглядів 4,5 тис.Місяць тому
Sochne Ka Tarika EP- 9 | Ullu Mat Bano! Sequence & Series Question | IIT JEE 2025 | Anshul Singhal
Sochne Ka Tarika EP- 8 | Nine Point Circle Question | IIT JEE 2025 | Anshul Singhal
Переглядів 2,5 тис.Місяць тому
Sochne Ka Tarika EP- 8 | Nine Point Circle Question | IIT JEE 2025 | Anshul Singhal
Funda 19: Fraud Summation! Permutation & Combination Question | JEE Main & Advanced | Anshul Singhal
Переглядів 4,9 тис.Місяць тому
Funda 19: Fraud Summation! Permutation & Combination Question | JEE Main & Advanced | Anshul Singhal
Sochne Ka Tarika EP- 7 | Geometric Progression Question | IIT JEE 2025 | Anshul Singhal
Переглядів 2,5 тис.Місяць тому
Sochne Ka Tarika EP- 7 | Geometric Progression Question | IIT JEE 2025 | Anshul Singhal
Sochne Ka Tarika EP- 6 | Tricky Probability Question | IIT JEE 2025 | Anshul Singhal
Переглядів 2,5 тис.Місяць тому
Sochne Ka Tarika EP- 6 | Tricky Probability Question | IIT JEE 2025 | Anshul Singhal
Sochne Ka Tarika EP- 5 | England Olympiad Question | IIT JEE 2025 | Anshul Singhal
Переглядів 2,7 тис.Місяць тому
Sochne Ka Tarika EP- 5 | England Olympiad Question | IIT JEE 2025 | Anshul Singhal
Funda 18: JHADU POCHA! Definite Integration Question | JEE Main & Advanced | Anshul Singhal
Переглядів 4,8 тис.Місяць тому
Funda 18: JHADU POCHA! Definite Integration Question | JEE Main & Advanced | Anshul Singhal

КОМЕНТАРІ

  • @anshumandwivedi1121
    @anshumandwivedi1121 Годину тому

    Ravindra gupta sir 🎉🎉🙏

  • @vinitakumari8023
    @vinitakumari8023 Годину тому

    Our sir taught this while teaching PnC. Didnt know it was called this. Thanks. You are the only one who teaches like my teacher on youtube. I really like your concept videos.

    • @anshul8330
      @anshul8330 Годину тому

      Your sir is awesome! Pls share the video. ❤ Did he cover problem 3 also? 😊

    • @vinitakumari8023
      @vinitakumari8023 51 хвилина тому

      @anshul8330 yes he did give p3 but that was after he had taught complex numbers entirely. i shared this video with my group and they are happy to see that we have already learnt this :) pls keep bringing such interesting questions

    • @anshul8330
      @anshul8330 47 хвилин тому

      @vinitakumari8023 Thanks for sharing. Do watch the full funda playlist.

  • @CubeRex_
    @CubeRex_ 2 години тому

    Done by own 👍

    • @anshul8330
      @anshul8330 2 години тому

      ❤ pls share

    • @CubeRex_
      @CubeRex_ 2 години тому

      Done sir 🙏

    • @techyBOY1412
      @techyBOY1412 Годину тому

      Hatt jhuta

    • @anshul8330
      @anshul8330 Годину тому

      @techyBOY1412 Bro, kar sakta hai woh... Utna bhibtough nahi hai

  • @nobodylol
    @nobodylol 3 години тому

    gazab sir, pls filtering of terms using nth roots of unity etc pe funda bnado, jee main ke bad share kar diya ab competition badhe to bhi kya, hum aur badh jaynge

    • @anshul8330
      @anshul8330 Годину тому

      Is baar mains mein bhi aaya hai ye wala filtering

    • @anshul8330
      @anshul8330 Годину тому

      Pls share the video❤

  • @MadhavSah007
    @MadhavSah007 3 години тому

    beautifulq and explaination...thank u

  • @believerboy9120
    @believerboy9120 3 години тому

    First step was the only thing to think.....thank u sir for this video❤

  • @OjasAgrawal-i2v
    @OjasAgrawal-i2v 5 годин тому

  • @Colded-h1m
    @Colded-h1m 10 годин тому

    a₁+a₂+a₃+a₄+a₅+a₆+a₇=2n 1≤a₁,a₂,a₃,a₄,a₅,a₆,a₇≤6 4≤n≤21 Sum of coefficient of even powers in expansion of (x+x²+x³+...+x⁶)⁷=f(x) [say] i.e.{f(1)+f(-1)}/2=6⁷/2 (Ans) Thank you sir

    • @anshul8330
      @anshul8330 7 годин тому

      Superb. Please share the video

  • @Colded-h1m
    @Colded-h1m 11 годин тому

    2/3 Will try that tetrahedron wala using this Will share working when i'm done

  • @believerboy9120
    @believerboy9120 13 годин тому

    Sher ne like share comment kr diya🤠 Subscribed pehle se tha😎 Btw sir naya concept seekha video se... Thank u

  • @unnati5385
    @unnati5385 15 годин тому

    Sir aapka adv batch kab aayega ?

  • @VenoM274-r4f
    @VenoM274-r4f 15 годин тому

    sir pls make a video on the binomial fundas the concept was amazing!

    • @anshul8330
      @anshul8330 15 годин тому

      Pls share the video with others.

  • @pearls456
    @pearls456 17 годин тому

    And now the syllabus bolne waale ro rahe hain😅😅😅😅 Thanks sir for alerting us

  • @OmVerma-x1w
    @OmVerma-x1w 17 годин тому

    All the 7 dice have 6 faces and so (6⁷-1)/2

    • @anshul8330
      @anshul8330 17 годин тому

      Correct! Pls share the video

    • @arhamnadeem4049
      @arhamnadeem4049 14 годин тому

      ​​@@anshul8330 Why (6^7 -1) / 2 If we put -1 in (x +x2 +x3 + x4 + x5 + x6 ) then we get 0 So answer should be (6^7)/2

    • @anshul8330
      @anshul8330 14 годин тому

      @arhamnadeem4049 correct

  • @AnaySarda
    @AnaySarda 17 годин тому

    Very good question sir . Thank you sooo much. Shared with all friends

  • @KAAVYAVAKHARIA
    @KAAVYAVAKHARIA 17 годин тому

    Actually this is the proof of beggar's method through multinomial

    • @anshul8330
      @anshul8330 17 годин тому

      Yes. And it's more versatile.

  • @RISHITHKUMARREDDYP
    @RISHITHKUMARREDDYP 17 годин тому

    sir the same concept can be used in a question which states as find the coefficent of x^99 in (x-1)(x-2)(x-3)(x-4)........(x-100) ans is 100^C1 *(-1)^99*X^99

    • @anshul8330
      @anshul8330 17 годин тому

      Yes...😊 Pls share the video

  • @ajayyadav-qb1sk
    @ajayyadav-qb1sk 18 годин тому

    ❤️❤️❤️

  • @Cooososoo
    @Cooososoo 18 годин тому

    Sir aap live bhi thoda lijiye channel ki growth hogi

    • @anshul8330
      @anshul8330 18 годин тому

      Batao live mein kya padhana hai?

  • @FizaRizwan-zg3qp
    @FizaRizwan-zg3qp 19 годин тому

    Sir ji 12 batch any information

  • @pranjalverma9111
    @pranjalverma9111 19 годин тому

    19:56 --> Yes sir please make a seperate video on this funda

  • @devcaster4144
    @devcaster4144 20 годин тому

    Sir jese aapne ke end me binomial ka result bataya addition wala sir please aese concepts pe video laate rhiyega please

    • @anshul8330
      @anshul8330 20 годин тому

      Video share kariye. ❤ Agar support milega to lekar aayenge hi.

  • @Soulofindia111
    @Soulofindia111 20 годин тому

    We want video on Stirling number method of first and second kind for pnc chapter 🙏

  • @FizaRizwan-zg3qp
    @FizaRizwan-zg3qp 20 годин тому

    Bhai log share karo sab

  • @cygnus-x7968
    @cygnus-x7968 20 годин тому

    Sir, complex no. and Matrix pai funda please

    • @anshul8330
      @anshul8330 20 годин тому

      Haan Bhai haan

    • @anshul8330
      @anshul8330 20 годин тому

      Video share kar do...Nahi to ye funda series band karni hogi

    • @anshul8330
      @anshul8330 20 годин тому

      😊

  • @Aryusingh17
    @Aryusingh17 21 годину тому

    is ans to hw q (6^7)/2 ?

    • @anshul8330
      @anshul8330 20 годин тому

      Pls share the video. Channel needs support.

  • @SangeetaSingh-gd1sw
    @SangeetaSingh-gd1sw 21 годину тому

    Thank you sir❤

    • @anshul8330
      @anshul8330 20 годин тому

      Glad you liked it. Please share the video.

  • @ajajjsbsjsbkbqpbpqnpa9549
    @ajajjsbsjsbkbqpbpqnpa9549 21 годину тому

    Sir can this method be used universally for all problems related to distribution of objects ? Like you said that beggar method fails in front of this method so I am asking that is this method more fundamental than beggar method ?

    • @anshul8330
      @anshul8330 21 годину тому

      Yes it's even more elementary. It has its advantages that the other method doesn't. The coin beggar is easy but weaker.

    • @ajajjsbsjsbkbqpbpqnpa9549
      @ajajjsbsjsbkbqpbpqnpa9549 21 годину тому

      Sir but I tried doing it for this question : let n1<n2<n3<n4<n5 be positive integers such that n1+n2+n3+n4+n5 = 20 then number of distinct arrangements…… sir I think here it won’t work function generation as there is constraint sir so I did it with manually checking cases…… So we can’t apply this method if constraints are there ??? Plz tell sir

    • @anshul8330
      @anshul8330 21 годину тому

      @ajajjsbsjsbkbqpbpqnpa9549 In this scenario even coin beggar won't work. You will have to take cases and that's why a smaller number 20 is given.

    • @HilariousRickroller
      @HilariousRickroller 19 годин тому

      This method is so powerful that you can even solve recurrence relation

    • @anshul8330
      @anshul8330 19 годин тому

      @HilariousRickroller Yes that's true.

  • @adityadadhich3320
    @adityadadhich3320 22 години тому

    £(r+1)ncr=101(2*101 -1)

  • @adityadadhich3320
    @adityadadhich3320 22 години тому

    My ans :101((2*101) -1)

  • @Jay-hh4ul
    @Jay-hh4ul 22 години тому

    Which formula do you use for circular permutations of alike objects

  • @honestadministrator
    @honestadministrator 23 години тому

    Another way Given problem may be mapped into What is the probability that largest angle of a triangle, ( x say) would be > = 90° . Minimum value of x would attain for an equilateral triangle. Hereby 60 ° <= x <= 180° Centre would be inside the triangle if x < = 90° Hereby probability is ( 90° - 60°)/ ( 180° - 60°).= 1/4

  • @unstoppablegaming577
    @unstoppablegaming577 День тому

    Sir please make a video on. Complex nos. in polynomial... Can we use f(w³)+f(w²)+f(w)+f(1)/4 for coeff. of x⁴ in polynomial??

    • @anshul8330
      @anshul8330 День тому

      Chalo bana dete hain very soon. Aap is video ko share karo. Channel grow nahi hoga to dead ho jaayega. ❤

    • @anshul8330
      @anshul8330 День тому

      Then we have to use fourth root of unity

    • @unstoppablegaming577
      @unstoppablegaming577 День тому

      @@anshul8330 ok 👍

  • @shivx3295
    @shivx3295 День тому

    Ioqm ke time seekha tha last time probability aur PNC mai use kiya tha isse ❤❤ ab revise hogya thanks sir ❤❤

    • @anshul8330
      @anshul8330 День тому

      Glad you liked it. Pls share with others.

  • @adityajha2889
    @adityajha2889 День тому

    If px is a polynomial such that px>0 for all x belongs R Then prove that px+p'x+p''x+p'''x.....upto nth derivative is positive

    • @anshul8330
      @anshul8330 День тому

      Ise kis series mein daalein?

    • @adityajha2889
      @adityajha2889 2 години тому

      @anshul8330 funda series me toh ye baith nhi rha

  • @adityadadhich3320
    @adityadadhich3320 День тому

    Ans to hw question is 6*7/2

    • @anshul8330
      @anshul8330 День тому

      Correct. Please share the video