No, it is corrected as displayed. The stress and force are statically equivalent. They do not make equilibrium with each other. Maybe that caused your confusion?
Q-A bar fixed at one end is pulled at the other end with a force P. The force is suddenly released. Investigate the vibration of the bar.......sir.....plz help with this
I think this question is a lot like the example that I discussed in Lecture 55. Maybe you can check it out. Due to the external force P, you will get a static displacement field u(x) = Px/EA. You can use this as an initial condition u(x,0) = Px/EA in the dynamic analysis and follow the steps in Lecture 55.
Stress must be in the opposite direction of force. Here in diagram you represented in the same direction of force.
No, it is corrected as displayed. The stress and force are statically equivalent. They do not make equilibrium with each other. Maybe that caused your confusion?
Q-A bar fixed at one end is pulled at the other end with a force P. The force is suddenly released. Investigate the vibration of the bar.......sir.....plz help with this
I think this question is a lot like the example that I discussed in Lecture 55. Maybe you can check it out. Due to the external force P, you will get a static displacement field u(x) = Px/EA. You can use this as an initial condition u(x,0) = Px/EA in the dynamic analysis and follow the steps in Lecture 55.
@@JurnanSchilder sir...... if you get some free time can u make a vedio on it..... because it is hard to relate for me.......!!!