This is what is happening in 9.6 f(x) - f'(x), we are doing this so that we can find the " vertical distance " between the two functions. Then we derivative the result of f(x) - f'(x). When we derivate, we have an equation for the gradient of the function representing the vertical distance. When the derivative of the function representing the vertical distance = 0. That's a turning point, and thus, where the vertical maximum distance is.
This is what is happening in 9.6
f(x) - f'(x), we are doing this so that we can find the " vertical distance " between the two functions.
Then we derivative the result of f(x) - f'(x). When we derivate, we have an equation for the gradient of the function representing the vertical distance.
When the derivative of the function representing the vertical distance = 0. That's a turning point, and thus, where the vertical maximum distance is.
why is X2 3? @ 3:36
Sir, you said we subst x=1/3 into which equation ? 🌺
At what timestamp ?
@@grade12 at 15:01 sir
We are substituting -1/3 into f(x) - f’(x)
Oh okay, I got it. Thank you so very much 🙏🏿🙏🏿