Good question. When we derivate, we now have the equation of the gradient of the function. We know the gradient at that point is zero because we are at the turning point, the x value there is 4 but the gradient is zero. As soon as you derivate, you can no longer sub in the y values from the original function.
Thank you sir ❤well explained keep up the good work
Pleasure
You Mr you must be called Mr Simplified Maths🎉
Sir when they ask by 4:42 which values of x is the graph increasing can you say XE(0;4) also
I wish I knew about u long ago sir
Well explained but the last question.
I have used f(x) and h(x) interchangeably, there's a lot of ambiguity. Watch recent Cubic Function questions for clarity
@@grade12 Thanks my teacher ❤️
well explained sir💙
Hey Blessing! I am glad I could help.
i have a question sir why did you derive first then sub 4 but not sub the whole point which is [4,32] x ;y
Good question.
When we derivate, we now have the equation of the gradient of the function. We know the gradient at that point is zero because we are at the turning point, the x value there is 4 but the gradient is zero. As soon as you derivate, you can no longer sub in the y values from the original function.
sir can I ask that why did we say 4-0/2 instead of 4+0/2 since that s the formula for mid-point of x
Here is a better version of the video
ua-cam.com/video/r7-claHnfss/v-deo.html
Thank you sir