Sounds like a shit professor. My em professor was pretty similar. He spent more class time boasting about his research than actually teaching the subject
You explained it to me like I was a little kid, and you know what? I’m not mad. Your explanation is EASILY THE BEST one on UA-cam, and trust me, I’ve been around many a channel. Thank you for prioritizing clarity over fancy talk. You’re a real one, Jordan. Best wishes with your channel 😊🙌🏽🎊✨
I'm an EE and been reviewing some of your videos on the Fresnel equations, characteristic impedance, etc. Boy do I wish I had these during my undergrad E. Mag. courses ... haha. Thanks for the great content, really brilliantly explained
I was stuck with this concept for the last two weeks. I tried to visualize it, worked on it but couldn't actually get to the point where I could actually understand this. But now I can safely say I have grasped the concept of boundary condition. Thank you so much for the video.
Thank you for this excellent visualization and explaining the boundary condition. I have a question regarding the direction of electric field vectors in material and vacuum side. To make a loop, the tangential component of electric field vectors in material and vacuum side may be pointed in opposite direction.
The line integral of E equals zero (0). Doesn't that means that when you kind of sum/accumulate the E vectors on the loop they cancel each other out. So that the E field drawn in red should be negative to the white E field (i.e. oriented in opposite direction).
Good video, but I think it is missing an important detail to the argument that made me spend some hours thinking haha. When you say that the parallel (tangencial as you call it) components of the fields are equal, it got me a little confused because given a 2D plane (since the boundary is a plane, not a line), you need to define a specific unit vector parallel to the plane and only so can you define a specific parallel component of a vector. If you don't do this, there is an infinite possible 'tangencial component vectors' since you can rotate the trajectory you have draw. What I think is missing is to start saying that, given the two electric-field vectors on both side, one can always find a plane that contains both fields. So if you make this plane parallel to the screen (to the paper you are drawing), then you can continue with the arguments you presented and end concluding that the parallel components that are defined as (a) parallel to the boundary and (b) contained in the common plane to both vectors must be equal. If you want to go one step further, you can say too that n x (E_1 - E_2) = 0, where n is the normal vector to the boundary and 'x' is the cross-product. In the light of what I wrote and a little thinking leads to this conclusion which is a nice geometrical relation.
My EM II prof said I shouldn't try to attempt to visualize EM, but this is exactly what I needed. Thank you!
Wth
Sounds like a shit professor. My em professor was pretty similar. He spent more class time boasting about his research than actually teaching the subject
InstaBlaster.
@@thoughtful2096 Holy shit, my E&M professor was the same damn way. Im relearning E&M by myself this time with Griffiths
Isnt EM one of the most visualizable areas?
You explained it to me like I was a little kid, and you know what? I’m not mad. Your explanation is EASILY THE BEST one on UA-cam, and trust me, I’ve been around many a channel. Thank you for prioritizing clarity over fancy talk. You’re a real one, Jordan. Best wishes with your channel 😊🙌🏽🎊✨
Great work, I wish more people would adopt your clear and concise teaching method.
Thank you!! My EM teacher sucks, and the class is super hard. The material is actually easy to understand when it's explained well like this.
I'm an EE and been reviewing some of your videos on the Fresnel equations, characteristic impedance, etc. Boy do I wish I had these during my undergrad E. Mag. courses ... haha. Thanks for the great content, really brilliantly explained
I would have never understand this if it wasn't taught in this way. This is the simplest way one can teach the concept of boundary condition.
I was stuck with this concept for the last two weeks. I tried to visualize it, worked on it but couldn't actually get to the point where I could actually understand this. But now I can safely say I have grasped the concept of boundary condition. Thank you so much for the video.
You really made me fall in love more with my career. Thank you, you remainded me why this is worth it!! Have a great day.
great grat explanation, simple, clean, thank you.
best explanation after an hour long search
This was really helpful, and felt a lot more intuitive for me, thank you so much for posting!
Thank you! I struggled with the concept for a week, I finally got it
I am learning much more from you than from my university professors! thank you thank you!
This is really good point, I always had hard time to understand the BC (boundary conditions), thank you for the great explanation also
I’m currently doing my second year as a EEE student at imperial college london. I appreciate the effort put in these videos. Great Work! :)
Greetings from across the pond! Thank you :) If you have suggestions to improve them, I am all ears.
Incredibly, I understood in this video (in a different language than mine), a few hours of reading in books that I don't quite understand. Thank you
watched several videos, this has to be best video ! Great work and wonderful explanation.
This is amazingly well explained
Thank you for this excellent visualization and explaining the boundary condition. I have a question regarding the direction of electric field vectors in material and vacuum side. To make a loop, the tangential component of electric field vectors in material and vacuum side may be pointed in opposite direction.
Thanks Jordan, this was very helpful.
extremely appreciate of your excellent explanation....... It was very helpful for me. Thanks a lot .
Best explanation I have seen. Many thanks!
Hi Jordan! Thanks for the quality video.
:)
You are making such great Videos. Thank you so much for making them.
how will we do this for circular waveguide with half of it being filled with dielectric and half wih air?
thank you sir, u save my life
excellent explanation sir
The line integral of E equals zero (0). Doesn't that means that when you kind of sum/accumulate the E vectors on the loop they cancel each other out. So that the E field drawn in red should be negative to the white E field (i.e. oriented in opposite direction).
At 4:19.you have shown Electric field lines to be parallel but they are radial....is this because you are considering an infinitesimally small area?
Sweet video bro. I wish UA-cam would put the "next" video in the "up next" section...
Me too, eventually I’ll figure out how to add in those in the end credits.
clear and simple, thx
hello, i am doing a report, I have a question, does it apply for antenna study?
Yup! Usually antennas are made out of metals and so the electric field inside them is zero (or very nearly zero) everywhere.
Great explainer ✅
Sir, you are the best!!
If the interface between two material along x,, which components of the field would be continuous? like in Ex or Ey or Ez? if it is TE polarization?
Will you be continuing to add to the emag playlist?
Yes! Very shortly I will be adding to it.
Good video, but I think it is missing an important detail to the argument that made me spend some hours thinking haha. When you say that the parallel (tangencial as you call it) components of the fields are equal, it got me a little confused because given a 2D plane (since the boundary is a plane, not a line), you need to define a specific unit vector parallel to the plane and only so can you define a specific parallel component of a vector. If you don't do this, there is an infinite possible 'tangencial component vectors' since you can rotate the trajectory you have draw. What I think is missing is to start saying that, given the two electric-field vectors on both side, one can always find a plane that contains both fields. So if you make this plane parallel to the screen (to the paper you are drawing), then you can continue with the arguments you presented and end concluding that the parallel components that are defined as (a) parallel to the boundary and (b) contained in the common plane to both vectors must be equal. If you want to go one step further, you can say too that n x (E_1 - E_2) = 0, where n is the normal vector to the boundary and 'x' is the cross-product. In the light of what I wrote and a little thinking leads to this conclusion which is a nice geometrical relation.
Can you please tell me the name of App you explain on ?
Autodesk sketchbook
Thank you ♥️
This is extremely helpful!❤
good explanation
I really respect you sir
thank you so much sir
Is this anythings related to discontinuity equation
Why is E and H used as opposed to D and H or E and B.
Great explanation!
Thank you
Amazing!
Thank you sir.
brilliant thank you
In short: 9:05
Superb
why is there one dislike?
Nice!
Awesomeeeeeeeeeeeeeeeeeewweeeeeeeeeeeeeeeee 😎
👍🏼
Need more clarity on boundary ...don't assume ..just prove it...