Mixing Salt and Water with Changing Volume

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  • Опубліковано 28 вер 2024

КОМЕНТАРІ • 12

  • @ghreqerhoah138
    @ghreqerhoah138 Рік тому +1

    Sorry Im a little hung up on where that +y went in 7:21 it just disappeared

    • @MasterWuMathematics
      @MasterWuMathematics  11 місяців тому

      No it didn't just disappear, it got absorbed into the derivative on the left hand side of the equation after we multiplied through by the integrating factor. I have not done a video on integrating factors as of yet, but it's coming. It may pay to review this material.

  • @0.Abdulrahmannn
    @0.Abdulrahmannn 8 місяців тому

    Sorry sir but why is the initial salt quantity wasn't used?

    • @JohnJohn-xn7sp
      @JohnJohn-xn7sp 8 місяців тому

      the y(0) is the 15, so once he plugged the 0 in, c/600=15 is the equation solved to get c.

  • @afiqhaiqal3706
    @afiqhaiqal3706 3 роки тому +1

    hello again sir.. i want to ask, if the volume of substance in tank is decreasing, should the volume equation become V-initial minus with cahnge of volume? is it correct?

    • @MasterWuMathematics
      @MasterWuMathematics  3 роки тому +1

      Hi! Happy New Year. In short yes. But it doesn't matter if you chose your sign to be a Plus because your net flow rate will be negative, and a plus and a minus still gives you a minus.

    • @afiqhaiqal3706
      @afiqhaiqal3706 3 роки тому +4

      @@MasterWuMathematics woah.. tq tq 👍🏽👍🏽😂 sorry sir for disturbing.. sending love from Malaysia

  • @MohammadDeaibes
    @MohammadDeaibes 8 місяців тому

    so where did the (0.2t^2)/2 for the next part because instead of 9000 for c i got 4500

  • @akusen9
    @akusen9 Рік тому +1

    very nice breakdown!

  • @jessypintoguzman9120
    @jessypintoguzman9120 2 роки тому +1

    Merci! Very helpful!