Mixing Salt and Water with Changing Volume

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  • Опубліковано 16 лис 2024

КОМЕНТАРІ • 12

  • @akusen9
    @akusen9 Рік тому +1

    very nice breakdown!

  • @jessypintoguzman9120
    @jessypintoguzman9120 2 роки тому +1

    Merci! Very helpful!

  • @MohammadDeaibes
    @MohammadDeaibes 9 місяців тому

    so where did the (0.2t^2)/2 for the next part because instead of 9000 for c i got 4500

  • @ghreqerhoah138
    @ghreqerhoah138 Рік тому +1

    Sorry Im a little hung up on where that +y went in 7:21 it just disappeared

    • @MasterWuMathematics
      @MasterWuMathematics  Рік тому

      No it didn't just disappear, it got absorbed into the derivative on the left hand side of the equation after we multiplied through by the integrating factor. I have not done a video on integrating factors as of yet, but it's coming. It may pay to review this material.

  • @afiqhaiqal3706
    @afiqhaiqal3706 3 роки тому +1

    hello again sir.. i want to ask, if the volume of substance in tank is decreasing, should the volume equation become V-initial minus with cahnge of volume? is it correct?

    • @MasterWuMathematics
      @MasterWuMathematics  3 роки тому +1

      Hi! Happy New Year. In short yes. But it doesn't matter if you chose your sign to be a Plus because your net flow rate will be negative, and a plus and a minus still gives you a minus.

    • @afiqhaiqal3706
      @afiqhaiqal3706 3 роки тому +4

      @@MasterWuMathematics woah.. tq tq 👍🏽👍🏽😂 sorry sir for disturbing.. sending love from Malaysia

  • @0.Abdulrahmannn
    @0.Abdulrahmannn 9 місяців тому

    Sorry sir but why is the initial salt quantity wasn't used?

    • @JohnJohn-xn7sp
      @JohnJohn-xn7sp 9 місяців тому

      the y(0) is the 15, so once he plugged the 0 in, c/600=15 is the equation solved to get c.