Constructor here, what a lovely surprise, thanks for featuring the puzzle. You hit every intended deduction. And yes that 3 cell cage always has the same make up regardless of shading options, you weren't going crazy. Only the neighbouring cage disambiguates the shading and a deadly pattern.
You're talking about the 12 cage at 44:42? I didn't see that. I knew it had to be either 134 or 146 but I failed to disproof the 146 option. I only got it when r3c7 was shaded making 4 impossible (the other two cells have a min sum of 5, therefore 8 is impossible in the cage)
50:10 you just have to love Simon says "this can't be three" pointing out the 3 ot the bottom of the column, when there's a 3 right next to the cell he's working on, which also is in the same square.
It's really awesome to see the two of you still doing these daily puzzles. I go through phrases of being really into sudoku and taking a step back and it's always nice to see these beautiful solves when I pop back in. I appreciate it. Thanks~
I always love to hear the sound Of Maverick as he leaves the ground. Now my joy is complete As I just did defeat All this green and grey twisting around.
I really loved how many times the same trick was used: the killer cages were forced to have a digit, even though there were so seemingly so many possible ways to make them up, which moved the logic along.
also when fiddling with the 12 cage, after determining that r3c7 was a 3, you could then also determine that r4c6 was always a 4, because the 6 cannot be doubled and would force the 1+3 to both be doubled making the cage too big.
The 12 box at 45:50 could’ve been solved because if 1 and 3 were doubled it would’ve been 4 in the other, but if one and 3 were both normal it would’ve been double 4 in the other as well
I finished in 82 minutes. This was a lovely puzzle. The logic between these Yin Yang squares and doublers is fantastic to work through. Without the secrets of Yin Yang, I felt this puzzle would be much harder. Luckily, I do know the secrets. I think my favorite part was seeing that r8c5 could only be a 59 pair, which fixes the 28 cage to be 68, which then in turn influences the 12 cage next to it to be 57 unshaded. Great Puzzle!
Would be fun to see a puzzle where the ying yang rule as explained at 09:12 clash with Schrödinger cells to get the shaded/unshaded cells to cross and mix
It would be quite annoying to track, having 2 completely separate shaded/unshaded parities. And it would have to be separate, Shrodinger colours exactly 9 cells but ying yang colours close to half the grid.
Argh! Finish up the 12-cage! I was getting frustrated by Simon working on the 12-cage for awhile, and then leaving it just before filling in the final 4. :) Plus, I really liked this cage because it could work either way, with the 4 doubled or the 13 doubled. And it was eventually resolved by sudoku, instead. Meh.
52:57 the fact that he had the 4 in box 5 cell 3 unsolved for so long, despite the math demanding it be a 4 was upsetting me. granted I'd have never gotten to that point on my own
Simon: I can't see a cage that demonstrates that (a "value" can repeat in a cage). 2 seconds later: Simon shows that 6 + double 3 = 12 😂😂😂 Love you, Simon! 😆
50:10 this is digit is a 3 or a 1... and it's not 3 *points to the 3 at the bottom of the column instead of the 3 in the neighboring cell* it's always amazing seeing the weird ways you go about things sometimes
Simon: literally ALWAYS uses the secret even if only slightly applicable. Also Simon: there's a 51 4-cell cage. Completely ignores the secret (at least for a long time in the video).
I had an interesting thing happen. I colored the 16 cage in box 5 the wrong way without noticing (correct numbers), and still made it all the way to the end of the puzzle with no contradictions or number errors. The only thing that tipped me off was that the very last bit of the coloring couldn't be resolved, with two possible solutions. I got the "solution correct" pop-up! It took me approximately two forevers to find the mistake,.
Finished in 46:05. I kept making some bad assumptions with the doubling issue, but it'd quickly lead me to an impossibility where I'd have to backtrack. I blame it on lack of sleep last night. Fun puzzle!
Simon, if you ever find yourself in Michigan (in the US), I would love to take you out for a round of golf on me as a thank you for all the entertainment, delight, and education you’ve delivered over the years. Cheers mate!
IIRC this is pretty standard coloring for them when they do yin-yang or cave type puzzles. "Unshaded" has a color because leaving it white means ambiguity, not "unshaded for sure".
@@aithne99It makes sense to shade it something. But for my brain green is more shaded than grey 😂 So grey should be unshaded and any colour is shaded.
This is his standard for shaded/unshaded. Thinks of it as Grey is shadow & Green grass grows in sunlight. Also, on my screen the green is a bright color & grey is not.
This one caused me a couple of issues. First, when deciding the makeup of the 7 cage in column 9, when I deduced that the cage had to have a doubled cell in it, I put in a 3 because that was the different digit between 124 and 123. I got pretty far before running into a contradiction, which meant that I had to go waaaaaay back and undo a lot to fix that mistake. Second, when deciding the doubled cells in the 12 cage that spans boxes 2, 3, and 5, I thought that there was only one possible shading and used that. But in fact, with the exact same digits, a second shading possibility was there that I had neglected. That led to further mistakes down the road. Eventually I had to basically wipe out most of boxes 1, 2, 3, and 5, and start those over, to realize my oversight there. Even with those mistakes, I still had fun doing this one. My final time was precisely 60 minutes (at least within a second based on the timer), and I was solver number 3587.
Ok can someone explain how Simon decides at 31:37 that row 8 column 5 is a 1? Never mind, figured it out: 3 and 7 are already accounted for in region 8.
I tried starting this puzzle two or three days ago. I was rather busy though and didn't get far before I had to leave it. Gonna be interesting to see how Simon handles it.
I don't know how well a puzzle like this would work, but it would be interesting for a Yin-Yang puzzle to have Schrodinger cells that act like both areas. Namely it would basically be tunnels for the shaded cells to cut through cut off areas of the grid.
I can't be the only one who within the first 20 seconds after reading the rules spotted the two-cell 28 cage and went, "welp, that's clearly what Simon is gonna start with, seeing how it literally has to be both shaded and the digits in it must sum to 14, allowing only 6,8 or 5,9 as viable options", only to have to wait for another 18 minutes for Simon to even spot the same cage 😂 On a similar note, the 51 cage in the bottom left has to contain exactly three shaded cells, since the only way to get to 51 with only two shaded cells would be to have 8,9 in the shaded cells (for 2×(8+9)=34) and then another 8,9 in the unshaded cells for 34+17=51, which is obviously forbidden by the cage rules. So it's never really up in the air whether the grey can be "on top of" the green in the top left 😂
I made a serious coloring mistake, making the 1 in box 5 unshaded. Turns out, that still gets you the same unique solution in terms of numbers. I only caught the error because it doesn't disambiguate between 3 options for coloring the rest. I solved all the numbers and still hadn't gotten all the coloring because of that error.
41:30 I mean, don't the grey in box 3 and box 5 need to "get out"? No matter what, they get out through the 12 cage at R3C6. Not necessarily at that cell, just that it's the cage i am talking about. We can first rule out that all of that 12 cage is grey. Because the digits in it cannot be 1, 2, 3. And we can rule out that two cells are green, because then grey cannot get out from the right side. So there are exactly two grey and one green in that 12 cage. EDIT: OH NO, i am wrong, both cells in row 3 could be green. But this has the same implication for R3C7 anyways... So i will just leave it be. What happens if R3C7 is green? It gets STUCK is what happens. Therefore, it is grey. R3C8 is green to avoid 2 on 2 action. Now, the one cell that is green in the 12 cage needs to be an EVEN number. Last i checked, R3C6 isn't an even number so it is grey. R4C6 is green. Now, the grey cells in the cage adds to 6 or 8 when doubled. So they are [12] or they are [13], in other words R3C7 is [23] and it cannot be 2. EDIT: IF both cells of the 12 cage in row 3 are green, which they can be, the gray cell in R4C6 is not a 6 and instead is a 4 with a value of 8. So the green cells add to four, still making R3C7 a 3. EDIT #2: 43:55 "Is there something easier" *Pulls hair* EDIT #3: Oh and no matter how you twist and turn it. If the two cells in row 3 are green, then R4C6 is grey and is a 4. If the two cells in row 3 are grey, then R4C6 is a 4. It's because you always end up with 8+4 = 12 whichever way you color it. R4C6 is a 4.
33:00 Hey Simon, here's a bombshell for you... If R4C5 isn't doubled, it has to have another odd digit in the cage and that odd digit is a 9 with a 7. You already explained how, if R4C5 is doubled, it cannot be a 3 because the digit 5 isn't available to be doubled. This means, R4C5 is ALWAYS a 7.
Could the "secrets" of Yin-Yang please be explained in the Rules section? They're incredibly tedious to listen to if you've heard it all before, and they are in fact rules.
Doesn't work for people seeing a video with the rule set for the first time; nothing to stop you skipping forward a minute or so whenever he's explaining stuff like that that you know already.
58:31 + a few minutes because I left the timer paused. And I had to look at the video when I broke box 5, totally not even thinking that r4c4 could be a doubler when pencil marking the possibilities. I'm surprised how well it unfolded once I bit the bullet and started pencil marking in numbers.
Mind if I ask what wording you’d have preferred? Telling the number of shaded cells would enrage a lot of people if you didn’t need the number to solve it, but my brain isn’t giving me another simple option for an alternative 🙃
@@Cthulhus_Mumthe only thing I can think of is just removing the “some” part as the rule set makes it impossible to shade every cell making the “some” kinda redundant
Wondering where ur solve goes wrong staring at a 123 triple knowing that 123 means double 1 but still unshaded colored them all ...and then come here to see why ur stuck only to see a shaded 1...
Brilliant puzzle. I'm not sure it taught you anything though. It certainly tried, but I lost count of how many times you made the same "discovery". Did you really have to explain the same really simple logic every single time?
Constructor here, what a lovely surprise, thanks for featuring the puzzle. You hit every intended deduction.
And yes that 3 cell cage always has the same make up regardless of shading options, you weren't going crazy. Only the neighbouring cage disambiguates the shading and a deadly pattern.
Wonderful debut from you!! Look forward to seeing what else you bring to us in the future!!
I love the part where you have to sort out the connection for the 12 cage
You're talking about the 12 cage at 44:42? I didn't see that. I knew it had to be either 134 or 146 but I failed to disproof the 146 option. I only got it when r3c7 was shaded making 4 impossible (the other two cells have a min sum of 5, therefore 8 is impossible in the cage)
I really liked that point in the solve when I knew all three digits, but none of the shading for that cage. Very nice!
The 1 4 6 option gives a chequerboard - so it’s always 1 3 4, with 4 worth shaded (whether it’s the 1&3 or the 4) 🥰
50:10 you just have to love Simon says "this can't be three" pointing out the 3 ot the bottom of the column, when there's a 3 right next to the cell he's working on, which also is in the same square.
50:13 Seeing the 3 all the way across the grid but not right next to the cell is so typically Simon... I love it...
And Simon's usually quicker/better at scanning rows than he is at columns... :)
@@Esperi74 I think I have noticed the opposite, very often Simon applies a column logic when I see the row logic.
It's really awesome to see the two of you still doing these daily puzzles. I go through phrases of being really into sudoku and taking a step back and it's always nice to see these beautiful solves when I pop back in. I appreciate it. Thanks~
I always love to hear the sound
Of Maverick as he leaves the ground.
Now my joy is complete
As I just did defeat
All this green and grey twisting around.
I really loved how many times the same trick was used: the killer cages were forced to have a digit, even though there were so seemingly so many possible ways to make them up, which moved the logic along.
I’m very impressed at how few cages there are. And the rule set is simple. I’m unshaded with envy.
Rules: 05:56
Let's Get Cracking: 08:50
Simon's time: 44m48s
Puzzle Solved: 53:38
What about this video's Top Tier Simarkisms?!
The Secret: 3x (08:56, 10:42, 53:00)
Bobbins: 2x (32:10, 48:51)
Maverick: 2x (50:14, 50:23)
Knowledge Bomb: 1x (11:29)
Three In the Corner: 1x (45:38)
Phistomefel: 1x (02:33)
And how about this video's Simarkisms?!
Checkerboard: 12x (09:07, 10:19, 29:09, 29:11, 29:20, 29:40, 29:50, 44:40, 45:15, 47:15, 47:19, 47:38)
Ah: 11x (11:03, 11:08, 21:59, 24:23, 26:16, 30:04, 31:46, 45:32, 45:32, 45:58, 49:59)
Sorry: 9x (04:26, 04:34, 33:06, 35:10, 36:03, 38:50, 41:48, 43:44, 44:48)
Lovely: 7x (25:14, 25:18, 29:23, 37:32, 49:38, 53:41, 54:17)
Beautiful: 7x (21:59, 30:59, 37:00, 39:35, 46:24, 47:59, 53:47)
Cake!: 7x (03:14, 03:18, 03:26, 03:29, 03:34, 03:39, 03:47)
Hang On: 6x (19:13, 27:44, 34:01, 34:41, 40:46, 44:29)
By Sudoku: 3x (37:00, 37:03, 40:37)
Obviously: 3x (38:10, 40:40, 45:06)
Nature: 3x (12:27, 14:04, 54:14)
Nonsense: 2x (34:33, 48:09)
Stuck: 2x (18:09, 32:10)
Gorgeous: 2x (28:01, 46:35)
Shouting: 2x (04:02, 04:04)
Good Grief: 1x (44:42)
Bother: 1x (52:27)
The Answer is: 1x (51:06)
Out of Nowhere: 1x (50:55)
Brilliant: 1x (05:35)
Incredible: 1x (01:31)
Losing my Marbles: 1x (34:03)
In Fact: 1x (14:56)
We Can Do Better Than That: 1x (37:22)
Wow: 1x (53:41)
Fabulous: 1x (01:43)
Pencil Mark/mark: 1x (31:50)
Most popular number(>9), digit and colour this video:
Twelve (13 mentions)
One (69 mentions)
Green (90 mentions)
Antithesis Battles:
High (2) - Low (2)
Even (31) - Odd (28)
Shaded (12) - Unshaded (8)
Row (5) - Column (3)
FAQ:
Q1: You missed something!
A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn!
Q2: Can you do this for another channel?
A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
wow
Huh, the "antithesis battle" section is surprisingly close to balanced
the solid minute of yin-yang back-and-forth from 29:00 to 30:00 was immensely satisfying
also when fiddling with the 12 cage, after determining that r3c7 was a 3, you could then also determine that r4c6 was always a 4, because the 6 cannot be doubled and would force the 1+3 to both be doubled making the cage too big.
2:28 i don’t remember this „mr beast“ ever releasing a free sudoku pack for reaching a specific amount of subscribers
The 12 box at 45:50 could’ve been solved because if 1 and 3 were doubled it would’ve been 4 in the other, but if one and 3 were both normal it would’ve been double 4 in the other as well
@@ILuvTheMavs Yes, I wanted to point out the same bc I loved the way that was constructed!
Really well-made puzzle. Not too flashy but full of cleverness.
I finished in 82 minutes. This was a lovely puzzle. The logic between these Yin Yang squares and doublers is fantastic to work through. Without the secrets of Yin Yang, I felt this puzzle would be much harder. Luckily, I do know the secrets. I think my favorite part was seeing that r8c5 could only be a 59 pair, which fixes the 28 cage to be 68, which then in turn influences the 12 cage next to it to be 57 unshaded. Great Puzzle!
Would be fun to see a puzzle where the ying yang rule as explained at 09:12 clash with Schrödinger cells to get the shaded/unshaded cells to cross and mix
It would be quite annoying to track, having 2 completely separate shaded/unshaded parities. And it would have to be separate, Shrodinger colours exactly 9 cells but ying yang colours close to half the grid.
@@pairot01 but doesnt that sound like so much fun:) 🤩
Wow. What a delightful puzzle. Intricate, beautifully constructed. Top drawer stuff
Argh! Finish up the 12-cage! I was getting frustrated by Simon working on the 12-cage for awhile, and then leaving it just before filling in the final 4. :)
Plus, I really liked this cage because it could work either way, with the 4 doubled or the 13 doubled. And it was eventually resolved by sudoku, instead. Meh.
52:57
the fact that he had the 4 in box 5 cell 3 unsolved for so long, despite the math demanding it be a 4 was upsetting me.
granted I'd have never gotten to that point on my own
77:44 and it finally happened - Simon and I used the same coloring! 🎉
Simon: I can't see a cage that demonstrates that (a "value" can repeat in a cage).
2 seconds later: Simon shows that 6 + double 3 = 12 😂😂😂
Love you, Simon! 😆
50:10 this is digit is a 3 or a 1... and it's not 3
*points to the 3 at the bottom of the column instead of the 3 in the neighboring cell*
it's always amazing seeing the weird ways you go about things sometimes
Simon: literally ALWAYS uses the secret even if only slightly applicable.
Also Simon: there's a 51 4-cell cage. Completely ignores the secret (at least for a long time in the video).
That 12 cage left me so frustrated lol
Why.. because the 6 was never an option which Simon did not pick up on.
Really good pencil mark checking this time!
I had an interesting thing happen. I colored the 16 cage in box 5 the wrong way without noticing (correct numbers), and still made it all the way to the end of the puzzle with no contradictions or number errors. The only thing that tipped me off was that the very last bit of the coloring couldn't be resolved, with two possible solutions. I got the "solution correct" pop-up!
It took me approximately two forevers to find the mistake,.
I just come from a graduation party at our neighbors. I am sure you would have approved of the cake, chocolate with lots of icing
28:13 for me. a bit tricky at some places. the no checkered 2x2 rule is vital for the solve.
Finished in 46:05. I kept making some bad assumptions with the doubling issue, but it'd quickly lead me to an impossibility where I'd have to backtrack. I blame it on lack of sleep last night.
Fun puzzle!
The way he talks about his mind and subconscious reminds me of Greg House
Simon, if you ever find yourself in Michigan (in the US), I would love to take you out for a round of golf on me as a thank you for all the entertainment, delight, and education you’ve delivered over the years. Cheers mate!
This is the second puzzle that I've seen where Simon has used green for unshaded and grey for shaded and I'm still mad about it 😂
At least it's not purple water and gray land
IIRC this is pretty standard coloring for them when they do yin-yang or cave type puzzles. "Unshaded" has a color because leaving it white means ambiguity, not "unshaded for sure".
@@aithne99It makes sense to shade it something. But for my brain green is more shaded than grey 😂 So grey should be unshaded and any colour is shaded.
Well in my brain, shade something, add a shadow, grey is the perfect color for it. I guess there is a reasoning that works for every person 😅
This is his standard for shaded/unshaded. Thinks of it as Grey is shadow & Green grass grows in sunlight.
Also, on my screen the green is a bright color & grey is not.
This one caused me a couple of issues. First, when deciding the makeup of the 7 cage in column 9, when I deduced that the cage had to have a doubled cell in it, I put in a 3 because that was the different digit between 124 and 123. I got pretty far before running into a contradiction, which meant that I had to go waaaaaay back and undo a lot to fix that mistake. Second, when deciding the doubled cells in the 12 cage that spans boxes 2, 3, and 5, I thought that there was only one possible shading and used that. But in fact, with the exact same digits, a second shading possibility was there that I had neglected. That led to further mistakes down the road. Eventually I had to basically wipe out most of boxes 1, 2, 3, and 5, and start those over, to realize my oversight there.
Even with those mistakes, I still had fun doing this one. My final time was precisely 60 minutes (at least within a second based on the timer), and I was solver number 3587.
Ok can someone explain how Simon decides at 31:37 that row 8 column 5 is a 1? Never mind, figured it out: 3 and 7 are already accounted for in region 8.
Great solve from Simon!!
Lovely puzzle , couldn’t finish it but enjoyed your solve
I tried starting this puzzle two or three days ago. I was rather busy though and didn't get far before I had to leave it. Gonna be interesting to see how Simon handles it.
Brilliant and very exciting puzzle.
Great solve Simon.👋
Lovely solve!
I don't know how well a puzzle like this would work, but it would be interesting for a Yin-Yang puzzle to have Schrodinger cells that act like both areas. Namely it would basically be tunnels for the shaded cells to cut through cut off areas of the grid.
😱😱😱
I liked this puzzle, thank you.
Lovely lovely puzzle, not too diff, was able to solve it during lunch❤❤❤❤❤
65:43
Fantastic puzzle with lots to find.
We’ve had 2-3 feet of rain in 3 days 😳 the flooding is crazy here. Yay it’s the wet season.
where are you?
We had exactly the same weather in Seattle. Hail, thunderstorms, hi Summer.
I’m sure with the level of puzzles you do you are bored by regular sudoku, but would you ever do a speed run of a basic one just to show everyone?
Great puzzle and great solve! 😊
28:51 for me. Fantastic puzzle!!
I can't be the only one who within the first 20 seconds after reading the rules spotted the two-cell 28 cage and went, "welp, that's clearly what Simon is gonna start with, seeing how it literally has to be both shaded and the digits in it must sum to 14, allowing only 6,8 or 5,9 as viable options", only to have to wait for another 18 minutes for Simon to even spot the same cage 😂
On a similar note, the 51 cage in the bottom left has to contain exactly three shaded cells, since the only way to get to 51 with only two shaded cells would be to have 8,9 in the shaded cells (for 2×(8+9)=34) and then another 8,9 in the unshaded cells for 34+17=51, which is obviously forbidden by the cage rules. So it's never really up in the air whether the grey can be "on top of" the green in the top left 😂
I made a serious coloring mistake, making the 1 in box 5 unshaded. Turns out, that still gets you the same unique solution in terms of numbers. I only caught the error because it doesn't disambiguate between 3 options for coloring the rest. I solved all the numbers and still hadn't gotten all the coloring because of that error.
I wish I could solve this kind of puzzle. It looks like so much fun. But I can't even figure out where to start.
41:30 I mean, don't the grey in box 3 and box 5 need to "get out"?
No matter what, they get out through the 12 cage at R3C6. Not necessarily at that cell, just that it's the cage i am talking about.
We can first rule out that all of that 12 cage is grey. Because the digits in it cannot be 1, 2, 3.
And we can rule out that two cells are green, because then grey cannot get out from the right side.
So there are exactly two grey and one green in that 12 cage.
EDIT: OH NO, i am wrong, both cells in row 3 could be green. But this has the same implication for R3C7 anyways... So i will just leave it be.
What happens if R3C7 is green? It gets STUCK is what happens.
Therefore, it is grey. R3C8 is green to avoid 2 on 2 action.
Now, the one cell that is green in the 12 cage needs to be an EVEN number. Last i checked, R3C6 isn't an even number so it is grey.
R4C6 is green.
Now, the grey cells in the cage adds to 6 or 8 when doubled. So they are [12] or they are [13], in other words R3C7 is [23] and it cannot be 2.
EDIT: IF both cells of the 12 cage in row 3 are green, which they can be, the gray cell in R4C6 is not a 6 and instead is a 4 with a value of 8. So the green cells add to four, still making R3C7 a 3.
EDIT #2: 43:55 "Is there something easier"
*Pulls hair*
EDIT #3: Oh and no matter how you twist and turn it. If the two cells in row 3 are green, then R4C6 is grey and is a 4.
If the two cells in row 3 are grey, then R4C6 is a 4. It's because you always end up with 8+4 = 12 whichever way you color it.
R4C6 is a 4.
1:16:25 - Loved it!
106:02 for me, solve counter 571.
(I used green for doubled, yellow for single.)
Sounds like typical English summer weather.
33:00 Hey Simon, here's a bombshell for you...
If R4C5 isn't doubled, it has to have another odd digit in the cage and that odd digit is a 9 with a 7.
You already explained how, if R4C5 is doubled, it cannot be a 3 because the digit 5 isn't available to be doubled.
This means, R4C5 is ALWAYS a 7.
Could the "secrets" of Yin-Yang please be explained in the Rules section? They're incredibly tedious to listen to if you've heard it all before, and they are in fact rules.
Doesn't work for people seeing a video with the rule set for the first time; nothing to stop you skipping forward a minute or so whenever he's explaining stuff like that that you know already.
Napoleon cake is 90% vanilla cream, to add chocolate filling or icing would be far too much. Even for Simon?
So sorry about your horrible weather!! Our temperature hit 100 F today!! 🥵
Stay cool and hydrated my friend. Low to mid 90s coming up for me early in week. Take care of self.
@@davidrattner9 you too!!! 🧡
58:31 + a few minutes because I left the timer paused. And I had to look at the video when I broke box 5, totally not even thinking that r4c4 could be a doubler when pencil marking the possibilities. I'm surprised how well it unfolded once I bit the bullet and started pencil marking in numbers.
Finished in 54:16 with help from the video.
52:34 for me. Nice puzzle!
The wording "shade SOME cells" bothered my OCD quite a bit. That aside, very fun puzzle
Mind if I ask what wording you’d have preferred? Telling the number of shaded cells would enrage a lot of people if you didn’t need the number to solve it, but my brain isn’t giving me another simple option for an alternative 🙃
@@Cthulhus_Mumthe only thing I can think of is just removing the “some” part as the rule set makes it impossible to shade every cell making the “some” kinda redundant
i needed 48h to solve it
Wondering where ur solve goes wrong staring at a 123 triple knowing that 123 means double 1 but still unshaded colored them all ...and then come here to see why ur stuck only to see a shaded 1...
Brilliant puzzle. I'm not sure it taught you anything though. It certainly tried, but I lost count of how many times you made the same "discovery". Did you really have to explain the same really simple logic every single time?
41:13 for me
Well done!
51:51 for me.