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Well-done
@@queenogbebor540 👏
Please Sir, for the infinite line of chargeShouldn't that part for calculating E be 👇E = 2πr (q/l) E°E = 2πr∆E°Where ∆ = Lamda
Oh… not at all The correct one is the one that was written. And it was derived as well
@@FlashDavidsXOkay SirThank you
Love itt 😊🔥🔥
You’re welcome. I’m glad we could help
Well-done
@@queenogbebor540 👏
Please Sir, for the infinite line of charge
Shouldn't that part for calculating E be 👇
E = 2πr (q/l) E°
E = 2πr∆E°
Where ∆ = Lamda
Oh… not at all
The correct one is the one that was written. And it was derived as well
@@FlashDavidsX
Okay Sir
Thank you
Love itt 😊🔥🔥
You’re welcome. I’m glad we could help