Superposition Theorem

Network Theory: The Superposition Theorem
Topics discussed:
1) Definition of the Superposition Theorem.
2) Steps to apply the Superposition Theorem.
3) Example of the Superposition Theorem.
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#NetworkTheoryByNeso #NetworkTheory #SuperpositionTheorem #NetworkTheorems

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Really helped a lot

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[@qemmm11]

Much appreciated 😊
(v/4)+(v-6)/8=3,
2v+v-6=24,v=10v

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[@nisargadk3672]

since current source is open circuited for frst case, same current must flow through 4ohm resistor just like 8ohm resistor na?

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Please complete network theory sir

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[@deboor1141]

How we recognise the Circuit which is linear or non linear ?

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Can't we use nodal analysis for this? It would be much easy..

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why cant we find the v using mesh theorem?

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[@nishantgautam7627]

In the step 2, if I replace the current source by a voltage source V= 12v in series with the 4 ohm resistor I get a different answer . Why ??
Also the voltage polarity across 4ohm due to both the sources is different , so should it be v1 - v2 when we do the algebraic sum ?

[@gourav7899]

U probably got 2 as answer.
Its the voltage drop across the resistor.
12-2 will give you 10

[@gau3463]

Why did you open circuit one and short the other?

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Sir please explain another problems in super position theorem

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Sir open circuit means resistance is infinite ?

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Did not learn current divider yet. Wish u listed the rule.

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Hello I have a question what if there's 2 voltage source? What shall I do?

[@SillyLittleMe]

if there are two voltage sources,v1 and v2,then first sc v2 and find voltage due to v1 then sc v1 and find voltage due to v2. Follow same steps for current source

[@phasepanther4423]

So is the voltage in the 8ohm resistor 12v?

[@phasepanther4423]

Or do we have to consider the direction of the current source and voltage source to see that they're in opposition, and therefore have a voltage of 4?

[@sachinbisht8227]

sir u replaced the voltage and current source by worng internal resistances

[@Kayumov]

7:34 why you didn't divide 4/4+8? You wrote 8/4+8. Please, explain

[@hasanhan900]

same notation here!!! he solved for I2 probably!! i think that is why you get different answers if you change the current source with voltage source and solve for the voltage with respect to the polarity.

[@devAzhar]

Where did the 8/ 8+4 come from. I know that I= V/R the R is 8+ 4
.Where did the division come from?????????????

[@adityavarun1498]

current and voltage division rule

[@jbonez69able]

wouldnt I1 be negative though? making V=6v?

[@nishantgautam7627]

Yess, there's something wrong here. Voltage Polarity due to both the sources across 4ohm is opposite. So it should be v1 - v2 when we do algebraic sum..
Also if I replace the corrent source by a voltage source, I get a different answer. Don't know what's wrong here, but something definitely is!

[@imruljony2630]

Why can't we solve this with mesh analysis?

[@mathiaskovendy7292]

Using current divider in the last bit, shouldn't it be (3x4)/(8+4)?

[@irvinmosoenyane4389]

that is also my concern

[@tetestoes5188]

No, because we are calculating the voltage in the 4 ohm resistor

[@AdityaSingh-pd9fj]

@@tetestoes5188 yea sl it should be (3x"4")/(8+4)

[@emmanuelnwabuike9475]

Current divider rules state that when two resistors are connected in parallel, the current of the source is multiplied by the other resistor divided by the sum of the resistors

[@rafayali3643]

When you use cdr, then the current for the resistor you are calculating, you have to take another resistor than that

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[@jamesroy9027]

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[@voidash]

can't we convert the current source into voltage source and solve the circuit?? what is wrong with that approach?

[@nishantgautam7627]

Exactly same doubt. I did that, and got a different answer. Don't know what's wrong here. 😭😭
Also the final answer should be v1 - v2. Polarity due to both the sources is opposite. Don't understand why he simply added it if it's algebraic sum.

[@somethinglyrical5365]

For first time you have open the circuit and for the second one you have short circuit that
So ho do we know when to do what??

[@SillyLittleMe]

current sources are oc and voltage sources are sc

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Problem 2 te to dependent source dhorei korchenn??

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RAM?

[@Slow-Biden9]

7:30 pretty sure you applied CDR wrong because it should be Rtotal/Rx(Itotal). If you could clarify i would appreciate this. I'm only watching this video because our teacher is ass