Hi. I have a question. What if the circuit is in parallel? example is a battery and two resistors. all of them are connected in parallel. I want to determine the value/setting for the other resistor (rheostat). resistor 1 is a fixed resistor having a resistance of 120 ohms and resistor 2 is a rheostat (variable). voltage source is set to 12V. what setting should be the value of the rheostat to be able to achieve maximum power transfer to the rheostat? If I will be solving the thevenin resistance, it will be zero, Rth = 0. It means, I need to short circuit the terminals of the voltage source? Thanks for those who will answer my question.
Great question. This theorem applies to Thevenin’s Theorem, which means the circuit has been transferred from the complex one (parallel circuit) to the simple one (series circuit)
Plz could u clarify this doubt…after eq 1 u seem to have taken (a+b)^2 for denominator and then divided all terms by RL…so if ur dividing it all by RL then why is P not divided by RL…and at end the answer equates to +/-Rth = RL but resistors can’t be negative
1) he didn't divide whole equation by rl, he just too took the reciprocal of rl then took that in denominator u can say that he divided the numerator AND denominator by rl or if i divide something by (1/x) or multiply by x then both are same things 2) resistance can't be -ve that's why we'll ignore the -ve value and consider only +ve value
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Very nice and easy explanation. Thank you so much.
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Plz expain physically that why maximum power is transferred when load resistance is equal to source resistance ???
If u set the derivative of power in terms of resistance to zero to find the maximum value of resistance, you will get that Rsource=Rload
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Really woww...excellent explaination sir..thank u sir
Hi. I have a question. What if the circuit is in parallel? example is a battery and two resistors. all of them are connected in parallel. I want to determine the value/setting for the other resistor (rheostat). resistor 1 is a fixed resistor having a resistance of 120 ohms and resistor 2 is a rheostat (variable). voltage source is set to 12V. what setting should be the value of the rheostat to be able to achieve maximum power transfer to the rheostat?
If I will be solving the thevenin resistance, it will be zero, Rth = 0. It means, I need to short circuit the terminals of the voltage source?
Thanks for those who will answer my question.
Great question. This theorem applies to Thevenin’s Theorem, which means the circuit has been transferred from the complex one (parallel circuit) to the simple one (series circuit)
so the case when the circuit is in parallel can not happen
Nice explanation
very nice and impressive
Thanks sir you explain very well
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Very helpfull explain
Thank you so much sir 🙏
Plz could u clarify this doubt…after eq 1 u seem to have taken (a+b)^2 for denominator and then divided all terms by RL…so if ur dividing it all by RL then why is P not divided by RL…and at end the answer equates to +/-Rth = RL but resistors can’t be negative
1) he didn't divide whole equation by rl, he just too took the reciprocal of rl then took that in denominator
u can say that he divided the numerator AND denominator by rl
or if i divide something by (1/x) or multiply by x then both are same things
2) resistance can't be -ve that's why we'll ignore the -ve value and consider only +ve value
Sir please analog electronics series complete kr dijiye
Thank you 💖
Thanks Sir 😃😃
bravo!
Thank you sir
that was helpful thanks
Manyyy manyy tnx
This is the basis of MPPT in solar inverters.
Why in both the differentiation case gives same result??
Thank SIR
thanks
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We believe this is how much one can explain the math.
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Can you explain anyone after equation 1 what's that??.
For p to be max, denominator will me minimum. (As slope of curve at minima is zero) so on differentiating the denominator we should get zero.
🔥🔥🔥
Multiplication after eq 1 is wrong
step after equation 1 is not clear
Pmax=Pth/4 in the end
kuch app bnana sikha dijiye bhaiya
Why can't we increase the speed of this video?
you can, in the settings wheel on the bottom right, there you can speed the video up to 2x the normal speed
2:29
Please explain in Normal Tone in your future videos
From 6 minite i can not understand
step after equation 1 is not clear
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Me
Step after eq 1 is wrong 😭
Plz expain physically that why maximum power is transferred when load resistance is equal to source resistance ???
Thank you sir ❤️