Frame Analysis Example - Shear and Moment Diagram (Part 2) - Structural Analysis

Example problem for analyzing a structural frame with an inclined member. The process followed in the video is as follows:
1) Label frame members
2) Calculate external reactions
3) "cut" out members and draw them with respect to their i (start) and j (end)
4) Draw axial, shear, and moment diagrams for each member

[@theovolz3073]

You truly are the king of kings....

[@bentosonline]

I’m confused about what happened at joint C. Why are the shear and axial forces between members one and two not matching?

[@pratapb8768]

explained in detail and its very useful :)

[@structurefree]

Thank you!

[@edg4246]

great video by the way, easy to follow. Thanks!

[@ichantongohan5951]

Yes of course, it's insightful and useful! Thank you very much.

[@2iiAaron]

in part 1, you used the angle to get N = -20.64kN and V = 7.64kN on the cut just before joint C, may i know how can i get 9.2kN reaction back from 7.64? because both 7.64 cos and sin 45 gives 5.4kN.

[@ashugupta8090]

When we draw the parabola for BMD, how do we know which side the parabola would open? Upward or downward?

[@engwasan7926]

Thank you so much

[@lilshrimp9554]

Such a life saver! Thank you!

[@patni1000]

Question - With the loading in the original X and Y axes (as mentioned as the end of the video), can the AFD SFD and BMD be drawn? That would be a pretty confusing drawing, especially for the angled member! :-/

[@KILONEWTONS]

Nice

[@muhammadmosaad4556]

I have a confusion: how the moments through joint c when we draw the bending moment diagram have the same direction
Thanks
Structure Freeeeeeeeeee Learniiiiiing

[@farookali6693]

Please explain stable and unstable structure.

[@khaitkanwal4572]

effective one

[@RickChan]

Have been watching ur video since I do Mechanic of solid and now Structure Analysis. Do you have a video teaching for drawing diagrams for Axial forces, shear forces and bending moment on a Frame shape or L shape without doing any calculation?

[@carlogepiga3728]

very nice :)

[@ancestro2404]

so when do i apply the equilibrium equations?? in order to not repeat steps

[@edg4246]

9:52 ... why is it 4.2kN*m ? shouldn't it be 4kN*m ? as your uniformly distributed load...

[@ShubhamPatil-rl4jk]

how he calculated that ? i'm lilttle confused here

[@OmarFM94]

he wrote it as 4.2 , but calculated it as 4 >> 9.2/4 = 2.3

[@lovelyjeancortejos6474]

ratio and proportion : (4-x)/x = 6.8/9.2 .... therefore, x=2.3

[@shaungrey850]

N2i must be -20kn

[@ANISH4217]

Nonsense!!!!!