At time 9:17, the example of Rho_B/Rho_A = 1.25 --> The Power of PDSCH_B in this cause should be = -2.03 dB + 18.22 right? (in UA-cam is -2.03+15.22). By the way, thank you very much for the great explanation.
Please explain, why Ppdsch_B= 20.88mW? In the scenario when Pb=0, Pa=-3. If Pa = -3, as in first example (Pb= 1, Pa= -3) RS Power is 18.2 (66.67mWatt) not 15.2. it means Ppdsch_B should be 0.6264*66.67=41.47 mW. Right?
Hi, The RS power formula include the value of Pb: Prs=Psingle_port - 10*Log(12*Nrb) + Log(1+Pb). in the second example Pb=0 not 1, so the value of the RS power is 15.2 for Pb=0 and 18.2 for Pb=1. Kind Regards, Smart Telecom Education
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At time 9:17, the example of Rho_B/Rho_A = 1.25 --> The Power of PDSCH_B in this cause should be = -2.03 dB + 18.22 right? (in UA-cam is -2.03+15.22). By the way, thank you very much for the great explanation.
Great Explain, Could you pls start series on CA
Hi, Thankyou very nicely explaned. Could you please give the spec ref for Prs=Psingle_port - 10*Log(12*Nrb) + Log(1+Pb).
Thank you!
Can you explain please why you add 10*log10(1+Pb) to Reference Power formula? is it just P_RS = P_singlePort -10*log10(12*Nrb)?
Please explain, why Ppdsch_B= 20.88mW? In the scenario when Pb=0, Pa=-3. If Pa = -3, as in first example (Pb= 1, Pa= -3) RS Power is 18.2 (66.67mWatt) not 15.2. it means Ppdsch_B should be 0.6264*66.67=41.47 mW. Right?
Hi,
The RS power formula include the value of Pb:
Prs=Psingle_port - 10*Log(12*Nrb) + Log(1+Pb).
in the second example Pb=0 not 1, so the value of the RS power is 15.2 for Pb=0 and 18.2 for Pb=1.
Kind Regards,
Smart Telecom Education
can you please share link of that slides?
5g.smarttelecomedu.com/lte-downlink-power-calculation/