This doesnt exactly help. Would pay to explain why adding a 2nd order polynomial to a linear function results in a 2nd order polynomial. Is this always the case?
A lot of things are easier to explain from a graphing perspective; in this case, to answer your question, you'd want to look at it from an algebraic point of view. If you add a 2nd order polynomial to a linear function, you will always keep that x^2 term. There is no linear function that will be able to negate the x^2 from the polynomial; therefore, the resulting function is also a 2nd order polynomial. So, yes--this is always the case!
@@ericvillarreal937 Thanks for the clear reply. Yeah i figured that from the related algebra. My point was more that I hoped for him to more give a good reason graphically why the resulting graph is a 2nd order polynomial. Regardless, I think his videos are awesome. :)
If you think of finding the x intercepts algebraically, you would have to let y = 0 and hence let (x+2)(x-1)=0. To solve that equation, either x + 2 = 0 or x - 1 = 0. If x + 2 = 0, x = -2 (An x intercept) and if x - 1 = 0, x = 1 (Another x intercept)
speaking from a guy who studying education degree. I got to learn a whole lot from you ! keep up the good work. It helps a lot !
This doesnt exactly help. Would pay to explain why adding a 2nd order polynomial to a linear function results in a 2nd order polynomial. Is this always the case?
A lot of things are easier to explain from a graphing perspective; in this case, to answer your question, you'd want to look at it from an algebraic point of view. If you add a 2nd order polynomial to a linear function, you will always keep that x^2 term. There is no linear function that will be able to negate the x^2 from the polynomial; therefore, the resulting function is also a 2nd order polynomial. So, yes--this is always the case!
@@ericvillarreal937 Thanks for the clear reply. Yeah i figured that from the related algebra. My point was more that I hoped for him to more give a good reason graphically why the resulting graph is a 2nd order polynomial. Regardless, I think his videos are awesome. :)
Why is it (x + 2)(x - 1) and not (x - 2)(x + 1) since the parabola intersects on positive 1 and negative 2 on the x-axis?
If you think of finding the x intercepts algebraically, you would have to let y = 0 and hence let (x+2)(x-1)=0. To solve that equation, either x + 2 = 0 or x - 1 = 0. If x + 2 = 0, x = -2 (An x intercept) and if x - 1 = 0, x = 1 (Another x intercept)
Shoot, I didn’t think of that, now it’s very clear to me why it is that way. Thanks!
Great video! Can you make one for dividing functions; drawing (sinx) /(x+1)
You inspire me too much!
Perfect! Awesome!! You are the best.
not 3 quarters, 0.73205080756
What programme are you using?
Desmos
My maths teacher dotes on you and so do I ❤
Can you help me with Couchy Mean Value Theorem? Your lectures and explanations are amazing
I just want to have a teacher like you!
Please go back to the old school type,instead of this LCD projector
Great!
first comment from Morocoo
That's some 5th school year material in a Russian school