If you wanna lift a baby from the ground, the force you will use is the weight of the baby (small force cause baby is light) If you want to lift a fat person from the ground, the force you will use is much larger. Why? Cause the weight of the person now is larger. So, the force you will apply is equal to whatever the weight of the object is. Now when you lift a rocket, you are essentially exerting a force equal to its weight to counteract the force of gravity pulling it downward.
@@learntodayIGCSE But if the force upward is equal to the weight of the day, how it will go up ? It would stay in the air as stationary or the object will rise up only if upward force would be greater than the weight of the object. As we studied in the sink and float case. Please explain
13:27 in this part the answer is wrong because the mass should be taken 2.184 not 2.2 because 2.2 is rounded value. Also the temperature will be 160 degrees (180-20=160). So final answer would be 698880, rounded to 700 000J
3:45 can we solve Q1) b)ii) like this: F = mv - mu (18000x0)-(18000x8.9) --------- = ---------------------- t d/s = 23/8.9 0-160,200 ----------- = 61,984 N 2.5845
omg you're amazing! I had no idea i had to give my answers to two s.f. and i find out just now, a DAY before my p4! Thank god i watched this video. Literal lifesaver
They are asking to state “TWO CHANGES” The image was already magnified from the first scenario. So, we don’t have to write that again as this is not a difference. The only differences are it was real then became virtual. And it was inverted then became upright.
At 14:58, for the bluetooth data connection, why is the answer not infrared? The course specification mentions that infrared is used for short range communications, and bluetooth is a type oc short range communication isn't it?
Although both Bluetooth and infrared are forms of short-range communication, they operate differently. Bluetooth is specifically designed for *data transmission* over short distances using radio waves, while infrared uses *light waves* and typically requires a direct line of sight between devices (eg. optical fibres) Hope this wasn't too confusing to understand 😅
@@learntodayIGCSE I still didn't understand, can you kindly explain why upward force can't be greater than weight there, like if upward force was greater, there would be resultant force and hence rocket would just accelerate upwards, but why can't upward force be greater than acceleration?
Hey, For question 5b What if the wave length is greater than the gap, and we are asked to draw the diffracted waves is it gonna be the same ?? Semi circles?
So your question means gap smaller than wavelength. Then yes it’s going to be semi circles. There are only two scenarios for the gap case as shown in the video.
@@learntodayIGCSE Yeah i mean in the question they asked to draw the wavelengths but what it if was a case (im not sure if they ask these), where the drew the wavelength and gap and asked us to show the diffraction and there they made the wavelength greater than the gap how would we show the diffraction?
@Abdullah-sq4ws I’m sorry but I don’t understand the question 😔😔😔 And there will be only 2 cases for gaps that will be asked and I have shown examples for both cases in the video Look at 16:34 Or email me a picture or drawing of your doubt
Can you explain how upward force and weight are equal in Q2b(ii)?
If you wanna lift a baby from the ground, the force you will use is the weight of the baby (small force cause baby is light)
If you want to lift a fat person from the ground, the force you will use is much larger. Why? Cause the weight of the person now is larger.
So, the force you will apply is equal to whatever the weight of the object is.
Now when you lift a rocket, you are essentially exerting a force equal to its weight to counteract the force of gravity pulling it downward.
@@learntodayIGCSEThank you for the explanation!
@@NayyarShazeab-tb2kg most welcome and good luck for the exams
@@learntodayIGCSE But if the force upward is equal to the weight of the day, how it will go up ? It would stay in the air as stationary or the object will rise up only if upward force would be greater than the weight of the object.
As we studied in the sink and float case.
Please explain
13:27 in this part the answer is wrong because the mass should be taken 2.184 not 2.2 because 2.2 is rounded value. Also the temperature will be 160 degrees (180-20=160). So final answer would be 698880, rounded to 700 000J
thank you thought i was tweaking
@@talachouaib1251 same bro😂
i was getting 264,000 on my calc and didn’t realise she put 60 degrees instead of 160 💀
So should we not round the answer? I used 2.2 and got 704000
Is it ok if i write 704 kJ as my final answer or would that be wrong?
@@neelofurmalik8814 ur not supposed to use the rounded value, so use 2.184 instead. otherwise you’ll get a wrong answer
I swear you are the answer of my prayers 🎉❤❤
I love ur videos so much! I always get so excited when u post🙌🏽!!
And comments like this makes me soooo happy 😍🤓
3:45 can we solve Q1) b)ii) like this:
F = mv - mu (18000x0)-(18000x8.9)
--------- = ----------------------
t d/s = 23/8.9
0-160,200
----------- = 61,984 N
2.5845
no the answer is not even the same bruv
omg you're amazing! I had no idea i had to give my answers to two s.f. and i find out just now, a DAY before my p4! Thank god i watched this video. Literal lifesaver
Glad I could help! ❤️❤️❤️🙏🏽 good luck for your paper
Hii how did ur paper 4 go
4:00 = you can calculate acceleration
(v-u)/t = (0-8.9)/(23/8.9)
????????
In that case you'll have to take AVERAGE SPEED, which is 8.9/2
Thank you very much!
Hi could you discuss the 2024 chemistry paper4 soon. It would help a lot :]
Will do my best to cover it soon.
I’ll be doing Maths Paper 2&4 first before Chemistry
Chemistry is the first exam 😭😭 on April 29th
@@kariniku isn’t it May 3rd?
And May 2 is Biology Paper 4
IGCSE Chemistry Paper 42 - Feb/March 2024 - 0620/42/F/M/24 FULLY SOLVED
ua-cam.com/video/iHfJ1X5pqd4/v-deo.html
@@karinikuya same for me
Q4) 180-20=160 degrees and not 60 degrees
In Q4(a) my answer is: Specific heat capacity is energy transferred per unit mass, per degree celsius. Will I get the marks for this question?
20:20 why not magnified? Why isn't that correct?
They are asking to state “TWO CHANGES”
The image was already magnified from the first scenario. So, we don’t have to write that again as this is not a difference.
The only differences are it was real then became virtual. And it was inverted then became upright.
At 14:58, for the bluetooth data connection, why is the answer not infrared? The course specification mentions that infrared is used for short range communications, and bluetooth is a type oc short range communication isn't it?
Although both Bluetooth and infrared are forms of short-range communication, they operate differently. Bluetooth is specifically designed for *data transmission* over short distances using radio waves, while infrared uses *light waves* and typically requires a direct line of sight between devices (eg. optical fibres)
Hope this wasn't too confusing to understand 😅
哇哦哦，你的视频真的很6！！！我物理最差了居然还能听懂。这张卷后面挺难的反正我觉得
Glad to be helpful ❤️❤️ good luck for your exams
you are heavily underrated THANK YOU SO MUCH FOR THIS
Thank you for appreciating the effort ❤️
Good luck for your exams !
4b 2nd division change in temperature is 180-20=160, it's not 60 degree celcius.
Was the conversion from pascal to kilopascal necessary?
god bless you !!
7:15 why can't the force upwards be greater than weight to lift the object?
They’re asking for the mass is all so that’s why we make F=mg
@@learntodayIGCSE I still didn't understand, can you kindly explain why upward force can't be greater than weight there, like if upward force was greater, there would be resultant force and hence rocket would just accelerate upwards, but why can't upward force be greater than acceleration?
pls share physics notes which you've showed in the video
learntodayigcse.com
Hi teacher i was wondering where can i find those 2024 papers?? Is it publised public or??
A student of mine gave me this paper along with maths paper 2&4.
You can send me a DM on Instagram, I’ll share with u there if u need it?
@@learntodayIGCSEyes please!
Teacher whats ur insta user name if you don’t mind !:D
@learntodayigcse
@@learntodayIGCSEi followed you!
Hello, in 13:22 wouldn't the change in temperature be 160°C instead of 60°C?
Thats right 😅 Thank you for noticing !
is there a way to access the notes ur using? it would be very helpful
learntodayigcse.com/
its urgent,is there a circumstance where u should not round off to 2 significant numbers?
your videos are really helpfull but is it possible to get your notes as they are very helfull
Thank you so much❤
for question 5b. isnt that wrong cause diffraction doesn't change wavelength so just draw 3 waves with same wavelength as diffracted waves(1 cm)
that’s what I mentioned wavelength doesn’t and shouldn’t change
@@learntodayIGCSE oh i got confused and thought you said that the wavelength was the same size as the ap
180-20=160 NOT 60
hey really good videos but is it possible if you can provide a pdf version of this paper
drive.google.com/file/d/1QYVbICou_EwFzIvktv95LZwU1WGJyEHj/view?usp=drivesdk
Hey,
For question 5b
What if the wave length is greater than the gap, and we are asked to draw the diffracted waves
is it gonna be the same ??
Semi circles?
So your question means gap smaller than wavelength. Then yes it’s going to be semi circles.
There are only two scenarios for the gap case as shown in the video.
@@learntodayIGCSE Yeah i mean in the question they asked to draw the wavelengths but what it if was a case (im not sure if they ask these), where the drew the wavelength and gap and asked us to show the diffraction and there they made the wavelength greater than the gap how would we show the diffraction?
Hey a reply would be highly appreciated :)
@Abdullah-sq4ws I’m sorry but I don’t understand the question 😔😔😔
And there will be only 2 cases for gaps that will be asked and I have shown examples for both cases in the video
Look at 16:34
Or email me a picture or drawing of your doubt
@@learntodayIGCSE Oh thats answers my question so there are only two cases that are asked
in 1(b)(ii) why cant we use f=mv-mu/t ?
yes its fine both work
Both works
F=ma
F=m (v-u/2)
F=m ( v-u/t)
F=(x) (y)
Or
F=w/d
F=ma
F=m (v-u/2)
F=m ( v-u/t)
F=(x) (y)
Or
F=w/d
F=ma
F=m (v-u/2)
F=m ( v-u/t)
F=(x) (y)
Or
F=w/d
When it says three successive crests, does it mean three lines or three gaps (2 lines in total)?
3 lines
Thank you a lot🎉🥹❤
My pleasure 😇
can i get your notes?
I need this paper therefore followed you
drive.google.com/file/d/1KDiD84c-uft8aWGV0d4nHY6qfRa90G5M/view?usp=sharing :)
thanks!!!
Cab you pleassee help with work done. I am still so confused about it overall. Btw thanks ur video is very mesningful
can u explain how u got acceleration in 6:15
Change of velocity over time
1400m/s divided by time. And time here is 1s
Q2b(ii) how do i know if i should use 9.8 or 10 for g?
9.8, its given on the first page of the paper during exams. So follow that :)
hello teach, I was wondering if you could give me the 2024 papers.
drive.google.com/file/d/1QYVbICou_EwFzIvktv95LZwU1WGJyEHj/view?usp=drivesdk
@@learntodayIGCSE I would like to have all the ones that you have, please send all of them to me
drive.google.com/drive/folders/1zlHa5KEm7KjSwPzoTGGj6aUucGxVQSR1
P4 tmr, feeling confident cus of this. U got any more tips?
I thought it was Monday 😢 I was gonna post a video of all formulas and calculations to look out for
@@learntodayIGCSEits monday for me. Just make it ty
@@learntodayIGCSE it's alr, I got a pdf with all the formulas already
Very good explanation
In question 4 part b(ii) by mistake u wrote 180 -20 means 60 whixh is 160 ..
Btw ans is fine
Ooopps ! 🥲 thank you for pointing them out ❤️
Good luck for the exams
Ma'am what about rest of the questions?
ua-cam.com/video/e5q7Ki6jZUs/v-deo.htmlsi=JJVrFUxvTh0XIiit
Can all answers be written in standard form instead of prefixes or 1000 form??
Can in q.3(b) the answer be rounded off to 35 though the marking scheme says 34??
please make more videos
Can you upload the syllabus with the notes in it?
Notes :learntodayigcse.com
Syllabus : www.cambridgeinternational.org/images/595430-2023-2025-syllabus.pdf
Q3 b shouldn’t it be 3.5 cuz 0.052 divided by 0.015 to get 3.46 so we rounded it to 3.5 could you check
its 0.52 not 0.052
Hey I am from India can I buy your comprehensive revision guide for physics
Yes you can buy and download immediately from the website itself. 😄
If there’s any issues just let me know here or email me and I’ll help u out
Miss how can I get the mcq papers
I don’t have them 🥲
😢😢
Help us ànd discuss the chemistry paper too
Most definitely!
I am going to work on Maths first and then Bio then Chem
IGCSE Chemistry Paper 42 - Feb/March 2024 - 0620/42/F/M/24 FULLY SOLVED
ua-cam.com/video/iHfJ1X5pqd4/v-deo.html
Is it okay if we don't change the answer to 2 s.f?
yes its fine, in IGCSE it doesnt matter and they wont mark it wrong if you dont round your answer (unless they specifically asked you to round it)
Plz share link to download
drive.google.com/file/d/1QYVbICou_EwFzIvktv95LZwU1WGJyEHj/view?usp=drivesdk
@@learntodayIGCSE thanks
Can you please share the mark scheme of this paper
just search it up
@@mrlashari do you know any website where I can find ms for 2024 f/m papers
Btw should we round it to 2 s.f
in IGCSE it doesnt matter so dont worry too much about rounding, do focus on the units though.
teach i think there is an error on question 4
Which part?
@@learntodayIGCSE the part where the change in temperture. it changed from 20c to 180c so thats 160c not 60c
Please post pdf of this paper
drive.google.com/drive/folders/1zlHa5KEm7KjSwPzoTGGj6aUucGxVQSR1
| Kindly send MS for this paper |
how is 180-20=60
same doubt
can you please provide me physics paper 3 core 2024/feb/march
Unfortunately I don’t solve for core ☹️🙏🏽
@@learntodayIGCSE Do you have the paper by chance? Of core?
hello may i ask if you have the mark scheme for this paper?
the mark schemes are not released yet
this is the ms drive.google.com/file/d/1IuvyFv_Ng4OV-jfRgnfMVNuLjipiA2cC/view
da shno albl da