How To: Find Limiting Reagent (Easy steps w/practice problem)

A video made by a student, for a student. Showing how to find the limiting reagent of a reaction.
Kansas University. Rock Chalk Jayhawk, KU!!!!!!!!!
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Stoichiometry. Biology. Chemistry. How to work practice problem. How to convert. moles to grams
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[@shemarwatts3928]

How did you get the 1.75 moles you never explained that part

[@sciencemadeeasier7100]

you're basically, instead of saying, for every 4 moles of NH3 you need 7 Moles of O2. your dividing 4 by 4 to make it 1 and whatever you do to one side of the equation you have to do the other, so you divide 7 by 4 aswell to get 1.75. therefore for every 1 mole of NH3 you will need 1.75 Moles of O2

[@ej4458]

@@sciencemadeeasier7100 but why by 4? why not by 7?

[@bakhshizulfiqarmanzur8988]

@@ej4458 I think it's because if you divide by 7, you would get a recurring decimal if you divided by 7, thus making your life harder for no reason

[@charlierichardson8778]

@@ej4458 ​ @Bakhshi Zulfiqar Manzur you are dividing 7 by 4 so that you can find out how many moles of O2 reacts with 1 mole of NH3

[@zainpunjwani470]

@blip trip in math generally, you want to get to 1 as your least common factor, so to get 7:4 is the same as 1.75:1 since 7/4=1.75, and 4/4=1. Hope this helps! :D

[@alexxxx7826]

I'm a senior in engineering and i needed to review how to do this stuff. You made this video short, straightforward, and easy to understand. thank you

[@sciencemadeeasier7100]

Thank you very much Alex, glad I could be of assistance.Good luck, finish strong. I have a good friend in his junior year now..shit looks nasty

[@ItsAkra]

I have watched at LEAST a dozen L.R. vids, trying to understand this (including all the best known Chem people on here) and this is THE ONLY ONE I GET. Thank god I get it now!

[@sciencemadeeasier7100]

+Alexandra “North Star” Wilson Thank you so much! Thats exactly what I thought before I made my chemistry tutorials.. I couldn't find a good video online to teach me so I made my own videos to basically teach myself but others find them very useful :) Glad I could be of assistance and thank you for the compliment!

[@shanthinarayan7019]

Yeah

[@thembiemadlophe2618]

Simple, straight to the point videos like this are hard to find these days on here, thank you.

[@Strawberry.swisher.666]

Ive been stressing all week because my teacher sucks at teaching and I have to resort to UA-cam as a replacement for my teacher. I finally found a video that made finding limiting reactants simple that also showed how you find the actual mole ratios. Thank you!

[@ZacHHackable]

u saved my ass bro thanks

[@sciencemadeeasier7100]

i gotchu bro

[@adamcohen2881]

huntsman knife....xd

[@SykoPatho]

this teflon from h1z1?

[@sarahshaban906]

this makes so much sense now! my new teacher just assumed everyone knew how to find limiting reagent but some of us students need to be reminded. thank you for this video!

[@mariaremik.j.8919]

1. Quick vdo
2. Simply understand.
3. Tysm
😄ok bie.

[@scooby253]

This video saved me and I'm doing AS chemistry! My teacher is rubbish but you explained it very well!! Thanks so much!

[@lilfairyprincess1o1]

Amina Ahsan bruh I'm doing this at igcse lmao

[@denise1116]

Amina Ahsan same my chem teacher sucks 😂

[@sakshammankotia773]

your marker works perfectly well lol

[@Omxralb]

You're telling me that my university professor took an entire class to explain this, while I learned it in 3 minutes?

[@lanalana1986]

yes

[@te1327]

Your doing this in uni??

[@abhya12]

@@te1327 lol i was wondering the same cuz i m doing this in junior year of high school

[@te1327]

@@abhya12 yeah in the UK we did this in year 10 which I believe is freshman year in the us (14-15)

[@abhya12]

@@te1327 sophomore it is, and yea same, we did it in year 10 too!

[@bryyyson]

exams tomorrow wish me luck lol, and yes this video helped thanks

[@karenhany9005]

i have a chemistry test in less than 5 hours and this saved my life tytyty

[@RahulSharma-rk4nd]

He got that 1.75 by dividing the no of moles by the stoichometry of the reaction. Like 8/7

[@ragd0ll667]

thanks man, i did so many of these wrong as I mixed up how many moles needed with how many you actually have - this was a very clear explanation

[@Emily-ze5er]

This is the most helpful video I’ve found so far, thank you so much

[@Hazza9990]

Actually made sense and is a quick method unlike other videos . I’m very impressed !

[@zhehin917]

Wow thank u so much for summarising two classes into 3 min

[@srijnasahni]

Amazing!! With the easiest explanation possible.Thanks a lot.

[@joelees3297]

Ugh. 15 in AP Chemistry - You saved me from failing a midterm. Tysm

[@juanvalencia9378]

Great video! I looked at 3-4 other sources and your explanation was by far the best. Keep up the good work!

[@jakethatsnake55]

You absolute legend, you made it so simple an easy! I know my brain is going to melt in my exam tomorrow and i probably still wont get this question right but i feel more comfortable now 😂😂😂

[@RedwaveStudios1]

Skipped a year, needed this man. Thanks!

[@diegomedina5051]

midterm tomorrow, yet another life saved by this

[@sciencemadeeasier7100]

Glad to be of assistance, Diego

[@risingwindspress]

Exam tomorrow wish me luck!!!

[@alphacooda8581]

same haha

[@triciafradrick3731]

Mine is today and i woke up 5 hours early to study 🤣

[@checker_boarder]

I got one tomorrow

[@ammaarquraishi2398]

mine is tomorrow

[@deananeal02]

@@ammaarquraishi2398 sammee

[@liamphillips9027]

thank you so much man i've been stuck on this for a few hours now and i finally get it, i've watched so many other videos but this video finally made it click! Thank you!!!!!

[@tiktokopedia2846]

THIS VIDEO WAS EXTREMELY HELPFUL. You literally saved me bro!!!

[@AkashKumar-wm6vv]

how do u get 1.75??

[@sciencemadeeasier7100]

+Akash Kumar 4 moles of NH3 require 7 moles 02. Therefore, Each mole of NH3 requires 7/4 of a mole of O2. Understand?

[@onalennamoeti4231]

+ScienceMade Easier no

[@amiracampbell5973]

Onalenna Moeti
So basically it's,
So 4/4 = 1
So 7/4 = 1.75

[@sydneym3251]

Onalenna Moeti you have 4 mol NH3 and 7 mol O2. So when you take one mol NH3, you divided the original 4 mol NH3 by 4. (4/4 =1) So to keep the ratio the same, you also need to divide the original 7 mol O2 by 4 also (7/4 =1.75) . So that’s where the 7/4 mol O2 comes from.

[@TheDrewster1123]

you're basically, instead of saying, for every 4 moles of NH3 you need 7 Moles of O2. your dividing 4 by 4 to make it 1 and whatever you do to one side of the equation you have to do the other, so you divide 7 by 4 aswell to get 1.75. therefore for every 1 mole of NH3 you will need 1.75 Moles of O2

[@rishiyadav9007]

Absolutely fantastic. Had to watch it twice, though, but the result is what matters! Cheers, ScienceMade Easier!
edit: who disliked this video?!

[@LeyahStorm]

Thanks for this. I've been super confused about Stoichiometry and I've watched other videos, even with a food analogy, but this one made the most sense. Cheers!

[@nataashaleong647]

I've BEEEEN struggling with this! Great video, thanks a million :)

[@jerinjoseph9039]

All other videos made me confused!......but this is too helpful.............

[@Kage1128]

Literally the only video i have found on youtube that explains it so simple and easy to understand. The rest is just a bunch of confusing bullshit

[@SirCreepus]

Cheerssss got my chemistry exam in one hour!

[@katielott6226]

SAME

[@sangat4315]

same lol

[@diamondwilliams5240]

at 1:45 - end I don't understand could you explain that more

[@gracemdermody]

its the night before my test on this stuff and i dont understand one bit of it but this video made me understand it hahah, lets pray i pass

[@joycedema-ala5088]

Where did the 1.75 come from?

[@inakizm]

Tomorrow I have an exam! Thanks bro u saved me

[@hollyatomic]

this makes the process so much easier, thank you !

[@thomasjoseph1545]

@Jia Dittman that is the molecular mass of NH3.
Molecular mass of N= 14
Molecular mass of 1 hydrogen = 1.
There are 3 hydrogen out there are so there are a total of 3 .
Now 14+3=17

[@zainabulbannah9935]

Nice dude👍

[@aasmohammad2181]

Bro i really like the way you write 6..BTW very well explanation..

[@manyagupta2858]

Thankyou so much! This video really helped

[@meowmeow646]

I really needed this, thanks a lot helped me very much!

[@user-od8vx2ei9g]

this is was so helpful thanks so much brother

[@lexibug6001]

This was insanely helpful, thank you!!!

[@yh7184]

Why not 2,58/4 and 8/7 instead of the 1,75 thing?

[@xtabbytayyibahx9600]

THANK YOU!!! I FINALLY UNDERSTAND THIS!!!

[@thomasjoseph1545]

@Lizzy Reese they make really confusing things in the text but conversion of moles is really easy , all you have to remember is
No. Of moles = given mass / molecular mass or atomic mass of compound

[@BruceLee-bd4pr]

Thanks for video. This really helps!!! Please make more.

[@areceipt0245]

thanks so much bro this really got me prepared for my quiz today.

[@TheFluffyMiners]

Got a test today. Wish me luck!

[@jaymaganti6604]

This is Perfect!

[@exha1edyt702]

What if it moles instead of grams like 43.9g

[@tawnyanderson3092]

super easy explanation!! great video!!!!

[@thandozulu9417]

You helped alot, I was struggling, like forever struggling bro, thanks alot💥💥💥

[@sciencemadeeasier7100]

glad to help bro

[@leena_peena]

THANK YOU SO SO MUCH!!!! I FINALLY UNDERSTAND IT

[@Vijay1591]

Thanks man... Really helped Me.

[@gear1421]

Perfectly Explained Sir

[@denise1116]

Thank you!! This is so easy to understand :)

[@bridgett1250]

what if the coefficient for both reactants is just 1?

[@franksanchez2702]

same

[@franksanchez2702]

Divide the grams given by the molar mass for both compounds and which ever one has less is the LR

[@kendigjl]

Excellent. Thank you very, very much.

[@parthchouhan7786]

Nice explanation brother 😉

[@kritikamalik2546]

Thanks for the great explanation 🌸😊

[@nermeenpal6034]

Thanks this video is helpful

[@ayushvats630]

Thank you so much
tomorrow is my exam you saved me thanks alot

[@sciencemadeeasier7100]

Good luck friend - don't forget to convert

[@ayushvats630]

Well done good in my exam thanks a lot

[@blankcuriosity...9750]

what a lifesaver

[@gageoutlaw3824]

Thank you

[@dvitipatel3330]

thank you, this video really helped me :)

[@mehakthakur7]

U r osm....thank u so much... Ur video Help me alot 💫💫☺☺☺

[@OGtrushalpatel]

That was surprisingly easy...

[@reykjaviktotoronto186]

awesome. simple method. thx man

[@elaafalmalek7401]

What if the limiting turned out to be the O2 how would it turned out to be

[@waad5497]

You just saved my ass thx so much

[@jessyleong4740]

Helped me a lot thank you 👍

[@rafsanrahman7810]

thanks bro
you explained it well.

[@_jrl_5262]

Thanks! Makes a lot more sense now :)

[@_jrl_5262]

+ѕнα∂σω✤ I've been watching other videos and they make it overcomplicated and more confusing than it has to be.

[@canttalkanymore]

I'd suggest just multiplying 4 with the molar mass NH3 right away and do the same with 7 times O2, then just look at the smaller number..

[@TheMoominAk]

It does not work like that. If you have for example 2 NH3 + 3 CuO --> N2 + 3 Cu + 3 H20. If we have 18,1g of NH3 and 90,40g of CuO, then CuO is the limiting reagent even though we then have 1,06 moles of NH3 and 1,14 moles of CuO.

[@aswitrishu4465]

Sir finding molecular weight is difficult for many complex compounds (unknown atomic number in periodic table)please tell any way without involving in moles🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

[@alisabah4744]

Can you tell me please how the NH3 is the limiting reagent?

[@jc_hz4196]

it would have been nice to go through with the whole proof of why NH3 is the limiting reagent, you only proof that you have enough to make the reaction with O2 not thst you don't have enough NH3

[@aceilshamieh557]

QUEEN u really helped me

[@TyTimeIsAwesome]

Not bad, but I would include the conversion ratios and do unit cancellation to make it more clear what you're doing.

[@nischaygirish4109]

Really neat hand writing

[@mirandawbu]

thank you. this is very helpful

[@michellaarin6422]

wait, how is it 2.58 x 1.75, isn't is supposed to be 258? im kinda confuse

[@SirCreepus]

last sec chem bang out

[@triciafradrick3731]

1:57 where did 1.75 come from?

[@joshhaugh1]

Ratio of the coefficients on the reactant side of the equation. 4/7=1.75

[@josh4467]

How'd you know whether to multiply 1.75 by 2.57moles rather than 8.06 moles of oxygen

[@farahsemary4197]

OMG thanks finally I got it :)

[@sheebavenu4329]

Thanku very much sir..

[@kaye8446]

Where did u get 17 for NH3 and 32 for O2?

[@varshapatidar7381]

you r osm thankyu 😊😊

[@philipgukassov4300]

thanks, you helped a lot

[@denabaker3794]

amazing thank you so much!!!!!

[@grantwilkinson2444]

Sweet. Thank you!!

[@mallharkhatua7374]

Thank you so much

[@tiearsinwilliams4101]

How do you get 17 when dividing I keep getting 16

[@elliemartin8957]

thank you thank you thank you

[@ZiaullahRoghani]

we have to divide no of moles by co efficent

[@aphelelefanho9819]

good idea