Limiting Reactant | Excess Reactant | Chemistry
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- Опубліковано 21 вер 2024
- This lecture is about limiting reactant, excess reactant and how to calculate numerical questions. Also, I will teach you the super easy trick of identifying limiting reactant and excess reactant in any chemical reaction.
How to calculate number of moles?
• How to calculate the n...
#limitingreactant
#excessreactant
#trick
#chemistry
To learn more, watch this animated lecture till the end.
Subscribe my channel at: / @najamacademy
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Facebook link: / najamacademy
The line" one man like me left behind " is very funny 🤣🤣🤣
Even I laughed a lot...
😂😂😂😂😂
@@NAJAMACADEMY stopped the lecture, and come in chat section to write it down because o noticed it, and Laughed alot, but it is already commented 😂
Same comment
😂😂
I too
"One man like me is left behind" That line is just 😂😂😂😂
Hahahahahahaah🙈🙈🙈
❤❤😂😂
In this video🎥
Limiting reagent
Excess reagent
Trick to calculate
Numerical question
Helpful video🎉🎉 guys must watch😊😊
AMAZING LECTURE FOR MDCAT.i paid 30 000 to acadmy but still couldn't find such tips and tricks.thanks alot sir.
0:46 "one man like me left behind"
Who is here in 2024?
I am here
Me😂
I am bro
@@roaringlionsff6984 welcome 🤗
Iam here
"One man like me is left behind" sir spitting facts
Hurtful fax tbh 🤣🤣🥲🥲
very illustrative and beautifully explained...love the way how you teach...i wish you were my teacher...!!!😄
Don't worry sir, you will get married one day 😂😂
Yooo you preparing for jee??
@@-ScrollToWin- That's, why I'm here...
@@omverma_1791 how old r u??
I think it's you who marry our sir
I needs this kind of teachers in my school 😢
Life saver if I was rich I was going to take care of u . Unfortunately I am just a student and all I can say is thank you.. and may life be fair and favorable to u
Once you get rich...
You have to remember me...
I will be wanting...
😊💗💗🙏
@@NAJAMACADEMYyou are stunning
I dont know how to thank you sir... But you really made my calculations more easier than i used to do with my original calculations.. Love you sir and thanks a lottt..
Awesome explanation sir,, first time i laughed so much while studying chemistry 🤣🤣🤣
First time 🧐 are you sure??
Dinitrogen and dihydrogen react with each other to produce ammonia according to the chemical equation N2(g)+H2(g)gives 2NH3(g). calculate the limiting reagent and it's mass.calculate the mass of ammonia produced if 2.00*10 power 3g dinitrogen reacts with 1.00*10 power 3 g of dihydrogen.sir can please solve this problem and make video please
Starting watch i can't understand what u r saying..but i don't give up so..once again i watch then finally i understood...tq sir
sir I'm from Tamilnadu. The video is informative as well as funny.
Shimon sirr!!!!!!🔥
❤🔥ADAD❤🔥
Ohoo seri seri where are you from
By making this video you literally saved me today🙏🙏🙏🙏🙏
God bless you
You are the best one more than any UA-camr I hope as you deserve 1M subscribe as soon as possible
Excellent way of teaching , beyond the limitations of book.
Example is extraordinary ❤
The line "one man is like me left behind" was personal ☠️
Great job sir well explained bohat achi examples thi waqai me 👏👍
First time , i completely understand this hard topic in very easy way just because of your wonderful explanation❤
If possible plz try to reply me😊
Really need one video on this topic..✨💯
Hope that unlucky man get married soon 😂...
Hmm inshallaha very soon 😂😂
Please make a video on stoichiometric calculation
Already uploaded!!!
That lucky man was definitely Popatlal 😂😂
Yes 😂
🤣🤣
😂😂😂😂😂 ikr
That what I want to say😂😂😂
superb sir well explained muje lagta hai ise zeda asan or koch b nhi oga most simple and easyist way .
I love yr daily life example 🙂 🙂 useful 😅
You make the best videos explaining concepts
Thank you so much ❤
Your videos are short and sweet ☺️
Easy to understand too
Keep it up sir
Sir please make vedio on :- Funadamental concept in Organic Reaction Mechanism
Your videos are so helpful keep it up 🙂
Your videos are best for understanding 😊
Exceptional❤
Good example ☺️ sir G God bless you 🙂
very nice explanation sir
Can we use ratio of Excess reagent to carbon dioxide to find mass of carbon dioxide
Please reply as soon as possible 🙏
It's very helpfull
May Allah blessed you always 🥰🥰🥰
Sir, in your terminal velocity video ,why don't you considered buoyant force exerted by water on the ball. please sir. 🙏
@Najam Academy if both have same ratio then which one is LR or ER??
Better than pws and any other 1 hour lectures🎉
Best channel I found😂
4 hours before my exam🥲
Example is good sir and funny and education
But maturity is realising that 'that 1 man is the luckiest among others' 🤣🤣
In a reation mixture , the reactant that is completely consumed is called the " Limiting reactant " .
Other reactants are called " Excess reactants " .
Thankyou sir 🙏🙏
🙏
Thank you very much Sir 🙏🙏
Sir.can limiting reactant comes is equal to excess reactant
You've saved my life..bless u❤❤❤❤I love you ❤❤❤
THIS IS WHAT CALLED AS TEACHING
Super videos understanding very easily
Bhai meri duayen lele 😂😂for the best concept vedio🎉🎉
Very well said 👍
Sir plzz make a lecture about Calculation Ex mole-mole calculation mole-mass calculation and some other calculations .
this topic is related to first chapter STOCHIOMETRY chemistry 1styear.plzzz Sir 👏👏👏.....!!!!
No need to say "PLEASE"...
It is already upload...
"How to calculate number of moles Najam Academy"
Search this in UA-cam...
🙌🙌🙌
@@NAJAMACADEMY Thanks Sir 💖💖💖💖💖
I love chemistry by U u'r so a good teacher tnks
Very nice, it was very helping lecture, it helped me todat alot, coz I have to deliver a lecture on it tomorrow and I was so scary, coz it's the most difficult topic in chemitry I guess.. 🙄
Best of luck!!🖒🖒🖒🖒
Allah bless you!!!
can we use these tricks in exams or do we have to use long methods for it
Plz sir make a video on hydrocarbon method of preparation of alkenes. Alkanes.alkynes
Very good explanation 👍❤️😊
Thank you sir for making this channel.
0:48 one man like me is left behind 😂😂😂😂😂
Sir love you so much
marry him
Excellent explanation keep uploading more videos sir
You are doing great ,may god bless you❤
Sir you are best
0:50 sir said one man left like me behind😂😂
Love your videos. Presentation*****5stars 😂😂as a teacher i request you to give more examples on numericals for students
I feel sympathy for this unlucky man😅😂😊🎉
Great explanation and love the examples!!!!!!! Very funny
Best lecture sir👍🏻👍🏻
where are the 3 and 5 moles from ????
It's damn easy to understand
tqq sir..
Amazing ❤️
Sir, please explain Hyperconjugation with orbitals overlapping
Very good explanation 👍
Awesome example sir 😁
We pray that you marry with a nice women soon 😊😊
Thank you...
So far the best comment ever received on my UA-cam channel...👍
Not woman a beautiful girl
imagine if this video played in my school
If they give in grams
One man like me was personal 😂👍🏻
Thanks u very much 💕
I am from MYANMAR
That line one man is left 🙂😂like me!(pain)🙂 was was kept constant there😂lots of love and blessings from Pakistan💚
Watching 2 hour before my exam😂
Thanks ❤❤
I love your teaching dear sir this is so helpful for us 🙂
I love your explanation and pink ❤
9:32
Love you Pinky ❤❤
Sir can youuu pleaaaseee tell can we solve like this in our achool examinations.. Will they give us marks
Plz tell me the meaning of two drops of aniline are dissolved in excess of dil hcl
Where is the link given??
Check the description...
We have updated it...
🙌🙌🙌❤
Thank you so much you have helped Me a lot by making these videos .
thanks sir, it is good explanation
why have you taken mass of carbon as 44 at the end
It's molar mass of co2
For c =12
For o = 2*16 = 32
For co2 = 12+32 = 44
can you tell me about the percentage yield it is hard to understand
Hi najam, i request you to make any type of video in calculation/ conversion in gases in stoichiometric problem❤❤❤❤
Yes sir Weee need a vidoe for calculation and tricks for it
Fun fact : I'm a maths student and I Don't even know to calcualte
Sir fomred is wrong its formed🙌
god bless you
One man like me😂😂😂😂😂😂😂😂😂😂😂😂
Thank you so much ❤ sir
yet im still very confused it like i havent tapped into the understanding part its so frustrating
Following up I get it now thank you Jesus😂
Sir ur concept is great 👍
THANK YOU!!!!!!!!!!!!!! 🙏🙏🙏🙏🙏🙏🙏
Very helpful😊❤