Nth Term of Geometric Sequence

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[@jademichelles.sonido286]

I'm glad I found Sir Gon's channel. Complete yung topics from Junior High School to Senior High School. Nakakatulong para sa review for entrance exam and modules.

[@MathTeacherGon]

wow..Good luck on your review...😊

[@sonnyboyvlog664]

@@MathTeacherGon hi ser

[@wrathseeker647]

a12=531,441

[@RasheedMacud]

🎉let's go Tama Ako ah ah ah

[@mikaelapm8301]

Salamat po Teacher Gon ! You really saved my math grades. Best MathTeacher

[@arshaneannenriquez484]

Thank you po sir! Mas naintidihan ko po yung explaination ninyo🥰❤

[@pedslapchat]

math10 quite hard to understand so thank you for this vid!!! i understand how to solve now lol

[@evelynn7853]

thank you teacher i will ace the exzam tomorrow wacthj ez

[@fabricantephilharveyl.9970]

thank you po teacher gon! haha! bukas na pasok namin and adv reading ngayon, since g9 pinapanoodnpo kita! the answer is 531,441, thank you po!

[@xxmonstergaming4383]

Salamat po nito sir SA math ,kailangan ko po talaga Yung explanation

[@proangel3717]

Salamat po nito sir SA math ,kailangan ko po talaga Yung explanation or like kase po mahirap po SA akin mag substitute salamat po talaga nito sir 🥺👏

[@MathTeacherGon]

Salamat po

[@margaritacortinas3572]

Will you pls solve this as example of seventh term 6 12 24 48

[@meljanquilon]

A12= 58.5 answer ko ser☺️

[@sethjazziell5783]

always po ba may a sub1 sa formula.. what if po yung given is walang value sa 1st term

[@clementhubasa574]

Same process Lang poba pag 6th term Yung hinihingi?

[@MathTeacherGon]

Opo..

[@jasonsvlog9990]

If given si a1 and fraction si common ratio?

[@jhopeshiii6619]

139,968 Po ba sa a¹²=139,968

[@jasonsvlog9990]

Ser Pano Po kung Fraction Ang common ratio?🙏🙏🙏🙏🙏🙏

[@wellcharyatal2849]

A12=531,441

[@edwardd.awasjr.991]

a12=59,049

[@jcr.1536]

Paano po pag may fracrion.1. What is the 5th term of geometric sequence,3/20,3/2,15...

[@user-st3ht9vx1i]

a12 = 1,594,323 i think? Although i saw some of the comments saying na it's "531,441" i think that's just the product of the 3¹¹ you just solved, you still need to multiply it by the first term which is a1 or the number 3 right?? sana tama 'tong pinagsasabi ko oral assessment na namin bukas sa math😭

[@abdulazisabubacar1073]

no, you don't need to multiply it to the first term, the final answer is 531,441. goodluck on your oral hahaha

[@HepzebahMandokhail]

Bro , pati ako nalilito... Based on previous examples, times naman talaga yung 531,441 sa 3 (3×531,441) which can give you the number { 1,594,323 } ... But if I'm wrong , give me explanation kung paano mo nasabing 'di na siya itatimes sa 3 = ).

[@maquel._]

@@HepzebahMandokhailyou dont need to multiply A12 to 3, recheck the video kasi di naman minultiply ulit yung last term sa common ratio

[@HepzebahMandokhail]

Sir , bakit sa com.sec. sabi sagut ay 531,441? Diba itatimes pa ang 531,441 sa 3? Gaya ng previous examples mo sir na 5×2⁶=64 , then 64×5 = 320?

[@janedacumos9749]

Sir pano po yung pag nag nigative?
-1,4,-16,64?

[@spyderluvzrandomvidz1395]

Nakarating aq dito ng di oras🥺megaddd module pa more😭

[@MathTeacherGon]

Kaya mo yn

[@clementhubasa574]

OK gets

[@moisesbelnas5826]

a12=10,240

[@RasheedMacud]

❌❌

[@crimando444]

531441

[@sethjazziell5783]

pano sir kung walang a sub 1

[@moisesbelnas5826]

a12=4.608

[@CarmellaLumbera]

a12=2,916 tama po ba kasi yung a1 is 3 and yung r is 3 and yung n is 12

[@jeanvysevillano5421]

sir it's 10,240 my answer I'm not sure but i try my best to get that answer. it is that correct?

[@denisepatricia_]

no

[@mattyurmenita]

@@denisepatricia_ hhaahaahhhaaha

[@marquisaldencortezano6673]

a sub 12 = 531,441??

[@annaleahbalaan1031]

Same tayo answer HAHAHA

[@yumikosakura2615]

531,441

[@VinceGaquit]

a,12=531,441

[@adrianaaday8687]

Paano nman po sir kunin Ang sum of the geometric sequence?😁

[@bryansvlog9029]

5,20,80 term 11

[@user-nu6fx7lk5e]

a12=4104??

[@DELUVINOJOYMIE-ju9pg]

a12=531,441 po

[@estongbogart9313]

a13= 1,594,323 ?

[@denisepatricia_]

no

[@user-nu6fx7lk5e]

a12=4104???

[@nemo-qs7od]

a12 =7776

[@renzyfornis7365]

Not even close

[@rivenlee6699]

A12 = 972

[@19limgabriella87]

a12= 531441?

[@denisepatricia_]

right

[@Emmanuel67569]

a12 = 531,441

[@hazelderoxas1495]

a12=534,441

[@moisesreycaballero470]

a12=531,441

[@bonangelodefino7899]

a12=531,441

[@debilyncabutero4521]

a12 = 531,441