Young Laplace Equation

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  • Опубліковано 18 лют 2023
  • An introduction to the Young-Laplace equation. One of a series of videos using lightboard technology developed at Imperial College London. I would like to thank Ollie Inglis, Hywel Jones and Lekan Ladipo from the Digital Media Centre in the Faculty of Engineering at Imperial College London for their help producing this and the other lightboard videos.

КОМЕНТАРІ • 18

  • @anubhavarora3282
    @anubhavarora3282 10 місяців тому +3

    Sir your way of explaining is truly fabulous. I am grateful to you for providing such a quality content

  • @user-ck2ew2oq7z
    @user-ck2ew2oq7z 6 місяців тому +1

    Finally I understand the basis behind the 2σ/r. Thank you for sharing your knowledge, Professor.

  • @DANGJOS
    @DANGJOS Місяць тому

    You make it look easy, thanks!

  • @agamjain9138
    @agamjain9138 Місяць тому

    Thank you sir❤

  • @IndiraYessenaliyeva
    @IndiraYessenaliyeva Рік тому +3

    Crystal clear, thank u 🙏

  • @Fawad.ANizamani
    @Fawad.ANizamani Рік тому +2

    OH MY GOD you are back

  • @pizzalove4693
    @pizzalove4693 3 місяці тому

    Very nice explanation
    Thank you for such quality content

  • @manikmehta2090
    @manikmehta2090 2 місяці тому

    ❤️❤️thanks sirr

  • @zq88
    @zq88 Місяць тому

    Hello, Professor. Thanks for your video!
    Can you explain how to determine the curvature sign? My understanding is that if the curvature center is in the denser phase, then it is positive. Is that right?

    • @BoffyBlunt
      @BoffyBlunt  Місяць тому

      I think you have this the wrong way round. We define the capillary pressure as the difference in pressure between the less dense phase and the denser phase, then positive curvature is when the less dense phase bulges out into the less dense phase (think gas and water).

    • @zq88
      @zq88 Місяць тому

      ​@@BoffyBlunt Thank you sir! I think I've got it.😃

  • @User-Tal1951
    @User-Tal1951 9 місяців тому

    Hi I need to ask something. How to reach you? Thanks

    • @BoffyBlunt
      @BoffyBlunt  9 місяців тому +1

      You can email me at m.blunt@imperial.ac.uk

  • @coldchickennoodles5575
    @coldchickennoodles5575 2 місяці тому

    I still don't understand the equation, can someone explain pls

    • @BoffyBlunt
      @BoffyBlunt  2 місяці тому

      What specifically would you like help with? I can try to clarify points that you are confused with.

    • @coldchickennoodles5575
      @coldchickennoodles5575 2 місяці тому

      @@BoffyBlunt Thank you so much for answering. I just find the 'dv' part in the first equation you presented slightly confusing and the V=4/3(pi)r^3

    • @BoffyBlunt
      @BoffyBlunt  2 місяці тому +1

      @@coldchickennoodles5575 The dV comes from work - the work done from basic physics is PdV where P is pressure and dV is the change in volume. The equation V - 4/3(pi)r^3 is the equation for the volume of a sphere in terms of its radius r.

  • @noodles8439
    @noodles8439 Місяць тому

    I understand everything except that the professor can write backwards.