I have a doubt how you have taken the area as 2*pi*r*l, by Fouriers law conduction is 1 dimensional but length and radius are 2 different dimensions, however heat flows along the radius so if this is the case we should take 2*pi*r*thickness right?
If I understood your point correctly, 2*pi*r*L makes sense for the area because the area is a lateral surface. In these calculations L serves only as the depth of the cylinder. (unlike with flat surfaces L is the thickness) It is r which takes care of the thickness here and on the left side of the equation with dr the fact that the are expands the further away from the center we go, is taken into account, I guess. Altho it was left a bit unclear to me, too, why we are using r instead of r_o . Or is it because we want to figure the exact heat flux at the point r which is between r_i and r_o?
@@p1ker1 actually we take r to describe the heat transferred at a instantaneous r but we usually integrate between Ro &Ri when we want to obtain total heat transfer:)
as mentioned by P1ker1, that is the lateral surface or "surface area". Think about it, 2*pi*r is the circumference, where the cross sectional area is pi*r^2, so in other words 2*pi*r*L is the surface area of the cylinder.
From cicumferential perspective, The temperature calculated from this relationship is applied to all of the points that are in the specified radius. From radial view of point, this relationship gives the temperature distribution in the radial direction.
I didn't understand how the boundary conditions were applied to solve for q(r) at the end of the video, can someone please explain?
Thank you!
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I have a doubt how you have taken the area as 2*pi*r*l, by Fouriers law conduction is 1 dimensional but length and radius are 2 different dimensions, however heat flows along the radius so if this is the case we should take 2*pi*r*thickness right?
If I understood your point correctly, 2*pi*r*L makes sense for the area because the area is a lateral surface. In these calculations L serves only as the depth of the cylinder. (unlike with flat surfaces L is the thickness)
It is r which takes care of the thickness here and on the left side of the equation with dr the fact that the are expands the further away from the center we go, is taken into account, I guess.
Altho it was left a bit unclear to me, too, why we are using r instead of r_o . Or is it because we want to figure the exact heat flux at the point r which is between r_i and r_o?
@@p1ker1 actually we take r to describe the heat transferred at a instantaneous r but we usually integrate between Ro &Ri when we want to obtain total heat transfer:)
as mentioned by P1ker1, that is the lateral surface or "surface area". Think about it, 2*pi*r is the circumference, where the cross sectional area is pi*r^2, so in other words 2*pi*r*L is the surface area of the cylinder.
@@p1ker1 r is the control volume of analysis, between r_i and r_o
super
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T(r) is the temperature distribution right ?
From cicumferential perspective, The temperature calculated from this relationship is applied to all of the points that are in the specified radius. From radial view of point, this relationship gives the temperature distribution in the radial direction.
@@alparslannasimi8752 oh thanks i got that.
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Sir, can you explain what is (qr, k)
K is the conductivity constant
Mr.kittipon khaongam
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