Funny to see that the tips that apply to the IB also apply to UK A levels. Nice summary of little tips to increase performance in Multiple Choice Tests. Can't wait to see the ratio questions video :)
Thank you Sam, Yes, in this video, I focus more on the IB as it is this program that I teach to a large majority of my students. Still, I wanted this video to help a wider range of students stressing for their exams, so I tried to make some applicable to other program (like 'Read The Question! haha). Actually some, are even valid for non-physics MCQ tests .
Love your work and great videos (Polarisation Part1, 2 drew me to you site and this is the 3rd video I watched - totally enjoyed them). Would love a video for ratio questions too - I know how to do them myself but just can't explain well to my IB kid . Much appreciated!
Hi Jeff. Thanks for your kind words. I remember when I was producing this video thinking that it would be a good idea, and then I got into other things... Thanks for reminding me of this, I'll put it on the list !
Thank you for your encouragements. I have been a little absent lately because I am currently moving countries, and do not have access to my main computer (My old laptop cannot handle the edition...). I can't wait to have everything back and running, as quite a few ideas for great physics videos are on my plate!
I wish u could come back... you saved me so much. I thought i will quit university before meeting you. I know you didnt recieved the motivation you wanted from the statistics point of view, but man , you saved so many people. Somehow, you motivated more than you were motivated. I hope you are doing well and i have an insane level of respect for you !
Thank you so much for the very kind words George! I am not gone, I had just a lot of personal things to handle, so had to slow down video production. My motivation in helping students in Physics via my channel remains intact! I am also currently moving house (on which I am doing some work) and country (administrative nightmare!), while remaining quite busy with my real life teaching business. The timing of your message is quite funny, because I managed to shoot a video this week , that I will post in a day or two after the last editing tweaks! First video in months, I know! It might remain slow for a few more months still, but I have tons of ideas, and 2022, could be the year of the rise of Physics Made Easy haha!
@@PhysicsMadeEasy Deffinetly you would need a discord community ( it's a very powerful app to stay in touch with people who follow you ) You can make diffrent channels, for questions, infos about channel , and so on. I can help you with that, just from my respect for you.
Respected Sir, lightening which is the cause of electrical discharge between cloud's and ground,so electric field should be so high to breakdown air, to conduct electricity,but why can't we feel that high electric field during lightening ,as we stand near van de Graff generator,high electric field make our hair to raise, why we can't notice during lightening?
Good question Gowri. The reason that comes to my mind is that the electric field strength during a storm is much weaker than that of a Van de graaf generator: In the range of ten thousand volts per meter on the ground during a storm and in the range of millions of volts per meter for a VdG generator…
Sir plz answer...Which of the following sets cannot enter into the list of fundamental quantities in any system of units? (a) length, mass and density (c) mass, time and velocity (b) length, time and velocity (d) length, time and mass... which is correct & why? (Only one correct option)
a, c and b. This is quite easy to pinpoint. Length, time and mass have for respective units meters, seconds and kilograms. These are fundamental SI units. Velocity and density are combinations of these units, respectively meters/second and kilograms /meter^3
@@PhysicsMadeEasy sorry sir I've to say this, that you are wrong.. the correct ans given in the book is only option B ... But I can't understand why not option A ???.. Sir its from a book named mechanics by d c pandey in India which is used for the preparation of JEE Exam in India.
Hey sir I've studied electrostatics. In electrostatics we conceptualise electric field lines and uniform electric field and Gauss Law states which says that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.
But wait i've studied gravitation also. There we studied about gravitational field can we conceptualise gravitational field lines here? Just like electric field lined and can we conceptualise uniform gravitational field? Is gauss law also applicable? For gravitational field flux for a close surface ? Can be conceptualized gravitational flux Please sir help me in this query by making a video.
Thank you Dexter for this. High school students, which is what this channel intend to help, barely scratch the surface of classical field theory, and barely touch calculus in their core physics program. this is why I do not Gauss Law when I deal with topics related to fields...
Respected sir, , We say that when two objects kept outside for long time ,it attains thermal equilibrium with surroundings ,BUT Consider a BLACK BODY(Ventablack painted),and silver coated object,KEEP THEM IN AN SUNNY DAY long period, definitely black body has higher temperature (IT ABSORBS ALMOST ALL LIGHT falling on it) than silver painted RIGHT, they never attain thermal equilibrium even when black body is good emitter sir? Am I right sir?
In absolute, if the silver painted body would be an ideal white body, it would just not interact with its surrounding by radiative thermal transfer… But, you know well, that nothing is perfect. In reality, the silver coated body has an emissivity close to 0, but not 0. It would just take more time for the silver coated body to reach thermal equilibrium than the ventablack painted object. In addition, with such an experiment, you also have to consider that convection and conduction would play a significant role in attaining thermal equilibrium. Good question :-)
@@PhysicsMadeEasySIR your explanations are very helpful,I have an doubt, an EM wave can be nullified, if it interfere with another wave which is out of phase to it. In a blackbody, a em wave is said to be OBSORBED(taken in), how can an oscillating Electric and magnetic field can be OBSORBED, consider an Atom of an black body in an oscillating Electric and magnetic field, in response to the changes in the field, it oscillates, how can we say that, the atom has absorbed the EM field , or the atom black body produces em wave which Out of phase to the incident em wave to nullify it and appears Black? Please correct me if I am wrong sir. And Thank you for spending your valuable time in answering my questions sir
A charge generates an electric field around it. If you move the charge relative to a fixed point, at that point, the electric field will naturally change. A magnetic field can be created by a change of an electric field. This is why when you move a charge, there is a magnetic field that is generated (due to the change of the electric field). Does this answer your question?
This is a good idea, I might consider this for the list of future videos for when I have more time for video making (Currently, you may have seen a slowing down in my video production, lots of things are happening in my life that I have to deal with... and producing/editing a video is quite time consuming), but definitely, it is an interesting subject that would plunge me back on some of the topics I really enjoyed learning during my uni years!
I have a question sir,if charges are moving in only one path then how the resistors in other paths work in a parallel connection,if voltage drops in just one path the why we say other paths also contributes the same voltage drop This confuses me a lot please help me sir....😓😭
When charges move in a cable and meet a junction (for example, where the cable splits into two ), some of the charges will go through the 1st cable, and some through the second cable... just like a river that splits into two rivers... check this video, it explains everything: ua-cam.com/video/ex7kgqhBbvc/v-deo.html
Hlo sir, WE KNOW THAT ELECTRIC FIELD DUE TO CHARGE +Q, INSIDE AN CONDUCTOR IS ZERO, IS IT possible to produce "FREE ENERGY" BY BRINGING AN TEST CHARGE(+) INSIDE AN CONDUCTOR FROM INFINITITY AND TAKING IT ( test charge) OUT OF THE CONDUCTOR NEAR +Q GIVING THE TEST CHARGE POTENTIAL ENERGY??? correct me if I am wrong
if there is a single charge +Q, there is an electric field around it, and that whatever the medium you are in. The thing is that in a conductor, all charges of that conductor are evenly distributed and will contribute to the total electric field: Electric fields strengths are going to sum to a total strength of zero. You can also see it mathematically because in a conductor a potential is constant, and as E=dV/dx, E will be zero because of that. However seen from outside the conductor, all the charges of the conductor can be viewed as a point charge Q which is the sum of all the charges in the conductor. In that case, outside of the conductor there will be an electric field that any charge that tries to approach will experience. You will have to work to bring charges closer to it. So, sorry... no 'free energy'... Does it answer your question?
Hlo sir,,.... yours answers are great,, why should EMF induced in the ELECTRIC GENERATOR IS MORE IN THE CASE OF MORE LOOP AREA ....THE AREA ENCLOSED BY THE LOOP IS JUST AN EMPTY SPACE RIGHT.... Consideration of a circular loop and Square loop made of equal length wire, surely circle encloses more area than square for same circumference length,so WHY INDUCED EMF IS MORE IN CIRCULAR LOOP Than square loop...magnetic field is linked only on the loop wire right? Why should empty area enclosed by the loop play an role In magnitude of induced emf?? Thanks a lot for answering my questions 🙂
Hi Gowri, Your confusion comes from the fact that you are considering the magnetic flux density, and not the magnetic flux! It is the change in magnetic flux that generates an emf, not the magnetic field itself. Let me try to explain quickly. If you are not familiar with the concept of magnetic flux, consider it like the ‘amount of field’, which is represented by the number of field lines (not their density - their density represents the strength of the field, and their number the amount of field). Set the area defined by a loop. For a given magnetic field, with a uniform strength, there will be a number of field lines passing through the area. When this area rotates, then the number of field lines passing through it ( = magnetic flux) will change. If this area is larger, the number of field lines will be larger, so when it rotates, the change in that number (or magnetic flux) will also be larger (thus a larger emf). I hope this helps! Edouard
Sir,Gold, silver, platinum has outermost free electrons for conducting electricity....then how could these metals be Nobel metals (not reacting with other elements)?
Hi Gowri, It has to do with their electronic configuration which is quite specific. For example Copper and Silver have a configuration 4s1-3d10 and 5s1-4d10. You would think that they would be quite reactive actually because of the s orbital filled with only one electron, but this s orbital is of lower energy than the d orbital, so a reaction would imply to take out an electron from a filled d shell, which requires a lot of energy. A similar reasoning applies for Gold and Platinum. This shows up as a high electronegativity for the noble metals (Electrochemistry), and also a high work function (Photoelectricity). But they still can put their s electron in common (the atoms don’t lose it, just share a sea of s electrons). Note however that this is not fully absolute, noble metals do react with other elements, just much less than other metals. I remember during my PhD exploring compounds of gold...
Hello Ajay, I might do so one day, but it is not really on my list of potential videos coming up. If more mention it, I will consider it. Thank you for the suggestion!
@@PhysicsMadeEasy it's ok sir . And thank you for replying. You videos bought me a great curiosity for studying.After watching your videos I really feel like now i have learnt something !!
@@PhysicsMadeEasy Sir, Today is our holy festival namely “HOLI” , wishing you a very “happy 😊 holi sir" , may god let your dreams come true , for helping us through your lectures.....
It does! If you place a charge in the path of light (= oscilalting electric field), it will start to oscillate under the influence of an oscillating electric force! See these videos for more details: ua-cam.com/video/hk63uUhkZH4/v-deo.html ua-cam.com/video/wiPHp-V30lc/v-deo.html
Funny to see that the tips that apply to the IB also apply to UK A levels. Nice summary of little tips to increase performance in Multiple Choice Tests. Can't wait to see the ratio questions video :)
Thank you Sam, Yes, in this video, I focus more on the IB as it is this program that I teach to a large majority of my students. Still, I wanted this video to help a wider range of students stressing for their exams, so I tried to make some applicable to other program (like 'Read The Question! haha). Actually some, are even valid for non-physics MCQ tests .
Love your work and great videos (Polarisation Part1, 2 drew me to you site and this is the 3rd video I watched - totally enjoyed them). Would love a video for ratio questions too - I know how to do them myself but just can't explain well to my IB kid . Much appreciated!
Hi Jeff. Thanks for your kind words. I remember when I was producing this video thinking that it would be a good idea, and then I got into other things... Thanks for reminding me of this, I'll put it on the list !
please keep going , keep doing videos
Thank you for your encouragements. I have been a little absent lately because I am currently moving countries, and do not have access to my main computer (My old laptop cannot handle the edition...). I can't wait to have everything back and running, as quite a few ideas for great physics videos are on my plate!
I wish u could come back... you saved me so much. I thought i will quit university before meeting you. I know you didnt recieved the motivation you wanted from the statistics point of view, but man , you saved so many people. Somehow, you motivated more than you were motivated. I hope you are doing well and i have an insane level of respect for you !
Thank you so much for the very kind words George! I am not gone, I had just a lot of personal things to handle, so had to slow down video production. My motivation in helping students in Physics via my channel remains intact!
I am also currently moving house (on which I am doing some work) and country (administrative nightmare!), while remaining quite busy with my real life teaching business.
The timing of your message is quite funny, because I managed to shoot a video this week , that I will post in a day or two after the last editing tweaks! First video in months, I know! It might remain slow for a few more months still, but I have tons of ideas, and 2022, could be the year of the rise of Physics Made Easy haha!
@@PhysicsMadeEasy Deffinetly you would need a discord community ( it's a very powerful app to stay in touch with people who follow you )
You can make diffrent channels, for questions, infos about channel , and so on.
I can help you with that, just from my respect for you.
Thanks a lot sir 😁😁😁
You are great sir. Love from Nepal. Your videos are awesome and full of concepts.
Thank you Aashish, Love from Europe!
Respected Sir, lightening which is the cause of electrical discharge between cloud's and ground,so electric field should be so high to breakdown air, to conduct electricity,but why can't we feel that high electric field during lightening ,as we stand near van de Graff generator,high electric field make our hair to raise, why we can't notice during lightening?
Good question Gowri.
The reason that comes to my mind is that the electric field strength during a storm is much weaker than that of a Van de graaf generator: In the range of ten thousand volts per meter on the ground during a storm and in the range of millions of volts per meter for a VdG generator…
@@PhysicsMadeEasy thank you sir for your answer
Sir plz answer...Which of the following sets cannot enter into the list of fundamental quantities in any system of units? (a) length, mass and density (c) mass, time and velocity (b) length, time and velocity (d) length, time and mass... which is correct & why?
(Only one correct option)
a, c and b. This is quite easy to pinpoint. Length, time and mass have for respective units meters, seconds and kilograms. These are fundamental SI units. Velocity and density are combinations of these units, respectively meters/second and kilograms /meter^3
@@PhysicsMadeEasy sorry sir I've to say this, that you are wrong.. the correct ans given in the book is only option B ... But I can't understand why not option A ???..
Sir its from a book named mechanics by d c pandey in India which is used for the preparation of JEE Exam in India.
@@PhysicsMadeEasy ok sir
Hey sir I've studied electrostatics. In electrostatics we conceptualise electric field lines and uniform electric field and Gauss Law states which says that the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux in an area is defined as the electric field multiplied by the area of the surface projected in a plane and perpendicular to the field.
But wait i've studied gravitation also. There we studied about gravitational field can we conceptualise gravitational field lines here? Just like electric field lined and can we conceptualise uniform gravitational field? Is gauss law also applicable? For gravitational field flux for a close surface ? Can be conceptualized gravitational flux Please sir help me in this query by making a video.
Thank you Dexter for this. High school students, which is what this channel intend to help, barely scratch the surface of classical field theory, and barely touch calculus in their core physics program. this is why I do not Gauss Law when I deal with topics related to fields...
Respected sir,
, We say that when two objects kept outside for long time ,it attains thermal equilibrium with surroundings ,BUT Consider a BLACK BODY(Ventablack painted),and silver coated object,KEEP THEM IN AN SUNNY DAY long period, definitely black body has higher temperature (IT ABSORBS ALMOST ALL LIGHT falling on it) than silver painted RIGHT, they never attain thermal equilibrium even when black body is good emitter sir? Am I right sir?
In absolute, if the silver painted body would be an ideal white body, it would just not interact with its surrounding by radiative thermal transfer… But, you know well, that nothing is perfect. In reality, the silver coated body has an emissivity close to 0, but not 0. It would just take more time for the silver coated body to reach thermal equilibrium than the ventablack painted object.
In addition, with such an experiment, you also have to consider that convection and conduction would play a significant role in attaining thermal equilibrium.
Good question :-)
@@PhysicsMadeEasySIR your explanations are very helpful,I have an doubt, an EM wave can be nullified, if it interfere with another wave which is out of phase to it. In a blackbody, a em wave is said to be OBSORBED(taken in), how can an oscillating Electric and magnetic field can be OBSORBED, consider an Atom of an black body in an oscillating Electric and magnetic field, in response to the changes in the field, it oscillates, how can we say that, the atom has absorbed the EM field , or the atom black body produces em wave which Out of phase to the incident em wave to nullify it and appears Black? Please correct me if I am wrong sir. And Thank you for spending your valuable time in answering my questions sir
Sir , why does a moving charge causes magnetic field ?
A charge generates an electric field around it. If you move the charge relative to a fixed point, at that point, the electric field will naturally change. A magnetic field can be created by a change of an electric field. This is why when you move a charge, there is a magnetic field that is generated (due to the change of the electric field). Does this answer your question?
@@PhysicsMadeEasy thank you so much sir . Finally i got it🙏❤
sir, could you please make videos on surface tension and surface energy ?
This is a good idea, I might consider this for the list of future videos for when I have more time for video making (Currently, you may have seen a slowing down in my video production, lots of things are happening in my life that I have to deal with... and producing/editing a video is quite time consuming), but definitely, it is an interesting subject that would plunge me back on some of the topics I really enjoyed learning during my uni years!
I have a question sir,if charges are moving in only one path then how the resistors in other paths work in a parallel connection,if voltage drops in just one path the why we say other paths also contributes the same voltage drop
This confuses me a lot please help me sir....😓😭
When charges move in a cable and meet a junction (for example, where the cable splits into two ), some of the charges will go through the 1st cable, and some through the second cable... just like a river that splits into two rivers...
check this video, it explains everything: ua-cam.com/video/ex7kgqhBbvc/v-deo.html
Thank u sir....🤗
Hlo sir, WE KNOW THAT ELECTRIC FIELD DUE TO CHARGE +Q, INSIDE AN CONDUCTOR IS ZERO, IS IT possible to produce "FREE ENERGY" BY BRINGING AN TEST CHARGE(+) INSIDE AN CONDUCTOR FROM INFINITITY AND TAKING IT ( test charge) OUT OF THE CONDUCTOR NEAR +Q GIVING THE TEST CHARGE POTENTIAL ENERGY??? correct me if I am wrong
if there is a single charge +Q, there is an electric field around it, and that whatever the medium you are in.
The thing is that in a conductor, all charges of that conductor are evenly distributed and will contribute to the total electric field: Electric fields strengths are going to sum to a total strength of zero. You can also see it mathematically because in a conductor a potential is constant, and as E=dV/dx, E will be zero because of that.
However seen from outside the conductor, all the charges of the conductor can be viewed as a point charge Q which is the sum of all the charges in the conductor. In that case, outside of the conductor there will be an electric field that any charge that tries to approach will experience. You will have to work to bring charges closer to it.
So, sorry... no 'free energy'...
Does it answer your question?
Hlo sir,,.... yours answers are great,, why should EMF induced in the ELECTRIC GENERATOR IS MORE IN THE CASE OF MORE LOOP AREA ....THE AREA ENCLOSED BY THE LOOP IS JUST AN EMPTY SPACE RIGHT.... Consideration of a circular loop and Square loop made of equal length wire, surely circle encloses more area than square for same circumference length,so WHY INDUCED EMF IS MORE IN CIRCULAR LOOP Than square loop...magnetic field is linked only on the loop wire right? Why should empty area enclosed by the loop play an role In magnitude of induced emf?? Thanks a lot for answering my questions 🙂
Hi Gowri,
Your confusion comes from the fact that you are considering the magnetic flux density, and not the magnetic flux! It is the change in magnetic flux that generates an emf, not the magnetic field itself. Let me try to explain quickly.
If you are not familiar with the concept of magnetic flux, consider it like the ‘amount of field’, which is represented by the number of field lines (not their density - their density represents the strength of the field, and their number the amount of field).
Set the area defined by a loop. For a given magnetic field, with a uniform strength, there will be a number of field lines passing through the area. When this area rotates, then the number of field lines passing through it ( = magnetic flux) will change. If this area is larger, the number of field lines will be larger, so when it rotates, the change in that number (or magnetic flux) will also be larger (thus a larger emf).
I hope this helps!
Edouard
Sir,Gold, silver, platinum has outermost free electrons for conducting electricity....then how could these metals be Nobel metals (not reacting with other elements)?
Hi Gowri,
It has to do with their electronic configuration which is quite specific. For example Copper and Silver have a configuration 4s1-3d10 and 5s1-4d10. You would think that they would be quite reactive actually because of the s orbital filled with only one electron, but this s orbital is of lower energy than the d orbital, so a reaction would imply to take out an electron from a filled d shell, which requires a lot of energy. A similar reasoning applies for Gold and Platinum.
This shows up as a high electronegativity for the noble metals (Electrochemistry), and also a high work function (Photoelectricity). But they still can put their s electron in common (the atoms don’t lose it, just share a sea of s electrons).
Note however that this is not fully absolute, noble metals do react with other elements, just much less than other metals. I remember during my PhD exploring compounds of gold...
Sir . Can you please upload videos on ray optics🙏. It would be very helpful.
Hello Ajay, I might do so one day, but it is not really on my list of potential videos coming up. If more mention it, I will consider it. Thank you for the suggestion!
@@PhysicsMadeEasy it's ok sir . And thank you for replying. You videos bought me a great curiosity for studying.After watching your videos I really feel like now i have learnt something !!
thank you sir pls help me with physics question in neet exam sir 🙏
Sir, after a very long time...
You know what it is, pre-exam periods, busy busy with my students... I am even surprised I was able to pull this off in time before the exams!
@@PhysicsMadeEasy sir, I am from India, and love your lectures a lot....Thank you so much sir for reprint........
@@PhysicsMadeEasy Sir, Today is our holy festival namely “HOLI” , wishing you a very “happy 😊 holi sir" , may god let your dreams come true , for helping us through your lectures.....
Sir Light is electromagnetic wave and it is made of electric and magnetic field then why it does not attract charge ??
It does!
If you place a charge in the path of light (= oscilalting electric field), it will start to oscillate under the influence of an oscillating electric force! See these videos for more details:
ua-cam.com/video/hk63uUhkZH4/v-deo.html
ua-cam.com/video/wiPHp-V30lc/v-deo.html
@@PhysicsMadeEasy thanks a lot
from which country
Europe :-)