Good day to you sir 😄 its 2am at the moment and im studying for a long quiz.. I must say... Thank you very because I understood the logic and mindset taught in the video! I'll be a new subscriber 😄
The AND. Formula is only for independent events like rolling dice or picking up cards and putting them back before picking a new card. When you are talking about percentages of people having donuts and/or coffee you cannot assume these are independent events, so use the OR formula. As a clue, if they give you the OR percentage, use the OR formula.
Is there a website I could go to to access this database of probability questions you're working on through the video? It would be quite beneficial to my studies
A letter is selected at random from each of the words “POOR” and “ELITE’’. Find the probability that two letters are selected are (a) both vowels b) both consonants c) a vowel and a constant
@@nellvincervantes3223 Notice that the AND formula is labeled "for independent events" in the video. Events like rolling dice or flipping a coin are independent. Also, drawing a card and putting it back before drawing a second card would be independent. Buying a doughnut and buying coffee are not independent events, so you cannot use the AND formula. You must use the OR formula as shown in the video.
Please someone can help me resolve this probability 2) Assume that the probability of experiencing homelessness among people who inject drugs is 65% . a) Pretend that we have a sample of 10 people who inject drugs. (2 points) i) Calculate the probability that none of these 10 people are experiencing homelessness. ii) Calculate the probability that 1 of these 10 people is experiencing homelessness. iii) Calculate the probability that 5 of these 10 people are experiencing homelessness. iv) Calculate the probability that at least 6 of these 10 people are experiencing homelessness.
Multiplying the two percentages will only give you the correct probability of two events happening when those two events are independent. We cannot assume these events are independent. The mention of a percentage of people who get a coffee or a donut basically tells you that’s these events are not independent and you must use the formula I used instead.
There are 7 even number in 15. These are the numbers 2,4,6,8,10,12,14. If we do it the way you did it then it will be wrong. Please recheck before uploading into UA-cam. It could possibly lead someone else into confusion. But your probability techniques are accurate. Good work.
no, the total number of the respective numbers with different colours adds up to 15. its numbers 1-5 multiplied by the 3 distinct colours that gives you the 15. hope you get what im tryna say. 😊
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Thanks for a good, clear, concise presentation of a subject that is sometimes unnecessariliy overcomplicated.
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Excellent video -super helpful and clear and I got it (after not getting it forever in my classes) - thank you!
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hoping to do well in my upcoming biostats exams with your wonderful tutorial. thank you!!
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Super helpful! Very clear and understandable explanations, thank you so much!!!
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i swear to god your explaination is way better than all of my prof
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Thank you so much for this straight forward explanation, hope to do well in the exam today :(
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superb video MrHelpfulNotHurtful. I shattered the thumbs up on your video. Always keep up the solid work.
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i owe my life to u…i had a morning before finals to learn this
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Your equation helped me most
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u saved me on my test u legend
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thank you for explaining it very well sir by the way im a student searching on how to answer probability and statistics
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This was so damn GOOOD
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Thank you, teacher
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thank youuuuuu aşkosuuuuu , I solved all the questions correctly thanks to you canımsın Öpücük
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thank you I am having a tough time learning this formula
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Good day to you sir 😄 its 2am at the moment and im studying for a long quiz.. I must say... Thank you very because I understood the logic and mindset taught in the video! I'll be a new subscriber 😄
Yay! So glad I could help. 😊
Great video
Question for #10:
Why can’t you use the “and” formula to solve? Why does the “or” condition influence the computation?
Thanks!!!
The AND. Formula is only for independent events like rolling dice or picking up cards and putting them back before picking a new card. When you are talking about percentages of people having donuts and/or coffee you cannot assume these are independent events, so use the OR formula. As a clue, if they give you the OR percentage, use the OR formula.
Is there a website I could go to to access this database of probability questions you're working on through the video? It would be quite beneficial to my studies
There’s no website or database. I am working from a OneNote notebook. Sorry.
thankyou ,it is helpful
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Cool thank you
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Nevermind: read the comments and it makes sense, my bad.
For 14:31 shouldn't it be P(D intersect C) since the question is asking for coffee AND donut?
boom boom boom...understood
Aadi singh Awesome. Glad to help. 😎
A letter is selected at random from each of the words “POOR” and “ELITE’’.
Find the probability that two letters are selected are
(a) both vowels b) both consonants c) a vowel and a constant
This requires a new video. I have a ton of work to do so I’m not sure when I can make it. If I get some free time, I will. 😎
a)(2/4)*(3/5)=6/20. b) (2/4)*(2/5)=4/20. c) (2/4)*(2/5)+(2/4)*(3/5)=10/20
@@meronyakobkibreab1813 Thank you! 💙💙
2024 and I am happy❤
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10:48
You can just youse the And formula for #10
Pranesh Balasubramaniam Thanks! 😎
@@MrHelpfulNotHurtful great video though
But they are not the same. It is 50.4% when you use P(D intersect C) = P(D)*P(C)
@@nellvincervantes3223 Notice that the AND formula is labeled "for independent events" in the video. Events like rolling dice or flipping a coin are independent. Also, drawing a card and putting it back before drawing a second card would be independent. Buying a doughnut and buying coffee are not independent events, so you cannot use the AND formula. You must use the OR formula as shown in the video.
@@MrHelpfulNotHurtful ok sir thank you
Please someone can help me resolve this probability 2) Assume that the probability of experiencing homelessness among people who inject drugs is 65% .
a) Pretend that we have a sample of 10 people who inject drugs. (2 points)
i) Calculate the probability that none of these 10 people are experiencing homelessness.
ii) Calculate the probability that 1 of these 10 people is experiencing homelessness.
iii) Calculate the probability that 5 of these 10 people are experiencing homelessness.
iv) Calculate the probability that at least 6 of these 10 people are experiencing homelessness.
How can you tell if it is aub ain anb
Sorry. I don’t understand the question. 😬
@@MrHelpfulNotHurtful don't worry I get it now
On the 10th question couldn't we just multiply the percentage of the people who buy a donut and the percentage of people who buy coffee
Multiplying the two percentages will only give you the correct probability of two events happening when those two events are independent. We cannot assume these events are independent. The mention of a percentage of people who get a coffee or a donut basically tells you that’s these events are not independent and you must use the formula I used instead.
@@MrHelpfulNotHurtful Yes I found out by watching your other videos, thank you
There are 7 even number in 15. These are the numbers 2,4,6,8,10,12,14. If we do it the way you did it then it will be wrong. Please recheck before uploading into UA-cam. It could possibly lead someone else into confusion. But your probability techniques are accurate. Good work.
no, the total number of the respective numbers with different colours adds up to 15. its numbers 1-5 multiplied by the 3 distinct colours that gives you the 15. hope you get what im tryna say. 😊
What class is this for
High school geometry
howeva
😂