@@macalandongryan5293 Hi, what does this question have to do with probability word problems? Please check out our video on solving linear systems in two variables. ua-cam.com/video/tFAX__s46dM/v-deo.html I think that video will help you out :)
Thank you so much for this video! I understand the basic probabilities, but as soon are we get to these word problems I was so confused. I am so glad I found this video to help me understand where I was going wrong.
I hate statistics so much. DImes and Nickles U.S & Canada: P(AorB)=p(A)+p(B) - p(A and B) to me that formula means you always get zero. How can you add A&B and then subtract A&B and get anything but zero? Don't tell me that's not what it means because that's how it is written. It should be Minus - P(A). or -P(B). My brain just can't take it. :( Looks like I'm dropping this course until next year.
That's because + and * are different. Simplify things by just everything is 0.25. 0.25 + 0.25 = 0.5. 0.25 * 0.25 = 0.0625. Even if we're talking about probability. 1 + 2 (A + B) = 3, 1 * 2 (A * B) is 2, they are not the same.
In the last problem, how did you get 5 over 3 = 10??? I heard you say, "5 common 3 is 10." What does that mean?? Thanks, great job teaching all of the other problems.
I'm very late, but I'll just post this for others who are asking the same question. 5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. Find 5C3 from Al, Betty, Charlie, Delilah, Erin. The number of possible ways you could take 3 people from that list (Al, Betty, Charlie, Delilah, Erin) are: Al / Betty / Charlie, Al / Betty / Delilah, Al / Betty / Erin, Al / Charlie / Delilah, Al / Charlie / Erin, Al / Delilah / Erin, Betty / Charlie / Delilah, Betty / Charlie / Erin, Betty / Delilah / Erin, Charlie / Delilah / Erin. So 5 choose 3 = 10 possible combinations.
Try making an audio recording, that way when you read your notes you can listen. I used that strategy in graduate school and it helped a lot. Good luck with your sat test.
Perhaps I didn't understand the last problem correctly. If I use binomial coefficients: (1/4)^3 * (3/4)^2. I get 8.78x10^-3, which is slightly off from the answer. I'm not sure what I'm doing wrong.
@@Greenemath it kind of over laps right? you put 6/13 because you only want to include the specific two outcomes only right? also thanks for these videos !
@vividchilling2492 All of these problems have a very specific formula to use. Whether you are using this video tutorial or another, use the formula provided and follow it step-by-step to get the correct answer.
It's all based on search for math videos. I guess a thumbnail has some impact, but not like with normal UA-cam videos that people watch for entertainment.
Thank you so much for this video! I understand the basic probabilities but as soon are we get to these word problems I was so confused. I am so glad I found this video to help me understand where I was going wrong.
Check out our free website: GreeneMath.com
@@macalandongryan5293 Hi, what does this question have to do with probability word problems? Please check out our video on solving linear systems in two variables. ua-cam.com/video/tFAX__s46dM/v-deo.html
I think that video will help you out :)
@@macalandongryan5293 Hi, please see other comment. We are not a homework service. You need to set up a system of linear equations.
@@Greenemath that is not homework service :)
Its just an example on google
@@Greenemath no hate just love:)
and I think its not working in substitution
Probability is the bane of my existence
It's not that bad, just work some practice and it will get easier.
Math has literally never been a struggle to me but probability pisses me off
Thank you so much for this video! I understand the basic probabilities, but as soon are we get to these word problems I was so confused. I am so glad I found this video to help me understand where I was going wrong.
Glad it was helpful! Good luck with your studies :)
you helped alot in clearing my concep, i am solving similar problems for my assignment
Glad I could help!
I hate statistics so much. DImes and Nickles U.S & Canada: P(AorB)=p(A)+p(B) - p(A and B) to me that formula means you always get zero. How can you add A&B and then subtract A&B and get anything but zero? Don't tell me that's not what it means because that's how it is written. It should be Minus - P(A). or -P(B). My brain just can't take it. :( Looks like I'm dropping this course until next year.
Just slow down and write the problem down. Then just use the formula step by step and you'll be fine.
That's because + and * are different. Simplify things by just everything is 0.25. 0.25 + 0.25 = 0.5. 0.25 * 0.25 = 0.0625. Even if we're talking about probability. 1 + 2 (A + B) = 3, 1 * 2 (A * B) is 2, they are not the same.
i hate it too I cant wait until this class is over
In the last problem, how did you get 5 over 3 = 10??? I heard you say, "5 common 3 is 10." What does that mean?? Thanks, great job teaching all of the other problems.
What's the time marker? I'll take a look and explain what's going on.
I'm very late, but I'll just post this for others who are asking the same question.
5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time.
Find 5C3 from Al, Betty, Charlie, Delilah, Erin.
The number of possible ways you could take 3 people from that list (Al, Betty, Charlie, Delilah, Erin) are:
Al / Betty / Charlie,
Al / Betty / Delilah,
Al / Betty / Erin,
Al / Charlie / Delilah,
Al / Charlie / Erin,
Al / Delilah / Erin,
Betty / Charlie / Delilah,
Betty / Charlie / Erin,
Betty / Delilah / Erin,
Charlie / Delilah / Erin.
So 5 choose 3 = 10 possible combinations.
@@virgolife4266 thank youuuuu 🥹
yea that confused me too i did it my way and got the same answer
may I know what’s your method?
i have to do shsat summer school and my math teacher talks way to fast and i barely get any answers down. this helped
Try making an audio recording, that way when you read your notes you can listen. I used that strategy in graduate school and it helped a lot. Good luck with your sat test.
Sir can I ask u something would teach me on any other platform plz
GreeneMath is free of charge
In the second question, can’t u just divide 11 by 3 to get 33? Or am I wrong?
What's the time marker?
How the is the first question 1/4 it should be half beacause 2,4,6 are even numbers in so 3 numbers from 6. So it should be 3/6 or 1/2
What's the time maker of your question?
Thank you 😊❤❤
You're welcome
Perhaps I didn't understand the last problem correctly. If I use binomial coefficients: (1/4)^3 * (3/4)^2. I get 8.78x10^-3, which is slightly off from the answer. I'm not sure what I'm doing wrong.
Hi Andrea,
Did you figure this out on your own or do you still need help with the problem? Let me know.
@@Greenemath😊
@Greenemath hey I'm still confused about the Last problem
wait for the first or question why do you need to subtract
What's the time marker of your question?
Wow.... I actually get it! 😀
I'm glad to hear that! 😎
Mr greene I was completely confused and I didn’t get you solved. Thanks
You are welcome.
Please I don’t get you
Helpful
Glad to hear that!
Thank you
You're welcome
11:37 why did you add 6/13?
11:20
Do you mean subtract 6/13? Just follow the formula listed on the screen. You need to subtract away P(A and B).
@@Greenemath it kind of over laps right? you put 6/13 because you only want to include the specific two outcomes only right? also thanks for these videos !
@@Greenemath I had looked at another video, so am kind of just piecing everything together a bit
@vividchilling2492 All of these problems have a very specific formula to use. Whether you are using this video tutorial or another, use the formula provided and follow it step-by-step to get the correct answer.
8:11
😎
Ty! This helped a lot
Glad to hear that!
13:13, 8/13 ? how?? why not 26!?
How are you getting 26! What are your steps?
Oh! @Greenemath I had wrote it different... I wrote out the 7+7 steps down and it confused me
@vividchilling2492 Just follow the steps given in the tutorial and you'll get the correct answer.
i think you dont add denominators only multiply
Thank you so much!
You're welcome!
Whats the chance that someone will watch this video after seeing the thumbnail? :-).. I mean probability...
It's all based on search for math videos. I guess a thumbnail has some impact, but not like with normal UA-cam videos that people watch for entertainment.
Thank you so much for this video! I understand the basic probabilities but as soon are we get to these word problems I was so confused. I am so glad I found this video to help me understand where I was going wrong.
You are so welcome!
@NAPSU they just copied some other person LMAO
Thank you
You're welcome
thank you
You're welcome