Mechanical Engineering: Ch 10: Forces on Cables (2 of 33) Concentrated Loads: Introduction

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In this video I will introduce and explain in detail of forces on cables with concentrated loads.
Next video in this series can be seen at:
• Mechanical Engineering...

[@easyengineering483]

This channel gives one of the clearest explanation of scientific concepts

[@CaliCity10]

You have literally cleared up everything up for me, which is a game-changer. So thank you

[@hamedismail5703]

thank you so much

[@positiveventure]

Can you confirm where a Zip Wire would be as is has a moving but concentrated load (the person/rider going along the zip wire. Non parabolic when there is no rider on the wire. I am look to confirm the best calculation when constructing zip wires. Thank you.

[@vigneshbalaji21]

I have a doubt, can you please explain why the horizontal component of tension is constant throught the cable ?

[@MichelvanBiezen]

That is the result of ignoring the mass of the cable (which is small compared to the loads). Since the mass of the cable is considered zero, then the tension in each section must be the same.

[@vigneshbalaji21]

@@MichelvanBiezen thank you for your reply. Just to understand better, I am reiterating your statement. Since the cable has negligible mass compared to load (cable mass is ignored). The tension is only caused by the load which is balanced by horizontal tension at both ends. If there is only one vertical load then the vertical tension is mg and both the horizontal tensions will be mg/2. Am I correct ?

[@Jasonvoobhggg]

It is like trusses

[@MichelvanBiezen]

In some ways yes, but the cable is not rigid.

[@aazad3760]

🌹🌹

[@MichelvanBiezen]

Thank you 🙂

[@judg3potat030]

Christian Bale