@@Myactualyoutubechannel Phosphorus has 5 valence electrons which means that it's closer to stability than potassium and only needs 3 more electrons to be an octet. Since phosphorus is more electronegative than potassium, potassium will give 3 electrons to phosphorus so it can have 8 electrons. That's why it's K3P.
This is how I thought about it.... K= 1 valence e P= 5 valance e You are correct by agreeing with the above.... But you have to understand that balancing a nonmetal and metal interaction (ionic bonding) involves understanding their electronegativity factor and how that relates to the octet rule. Here P (non metal) is more electronegative because as you go up and to the right of the periodic table (or towards fluorine), you are more electronegative so this means that this atom will want to fulfill the octet rule more than K (metal) in this interaction. So if P has 5 electrons in its valence shell and K with 1 electron in its valence shell, comes along trying to interact with P....well P going to take that 1 electron and now P has 6 electrons in its valence shell....and its going to take another electron from another K....and its going to take another electron from another K.....now it was has 8 electrons in its valence shell and it only took 3 potassiums to do so. Hence, in a reaction between K and P, you are going to balance this reaction, by fulfilling the octet rule of the more electronegative atom, in this case P. P is balanced when it is interacting with 3 Ks. K3P1 this is at least how I look at it.
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does a neutron not have a larger size than a proton but
Why does P have 3 valence electrons if its in group 5A?
Same question
@@IqraNaikwadi-i7i I think he was wrong
@@Myactualyoutubechannel Phosphorus has 5 valence electrons which means that it's closer to stability than potassium and only needs 3 more electrons to be an octet. Since phosphorus is more electronegative than potassium, potassium will give 3 electrons to phosphorus so it can have 8 electrons. That's why it's K3P.
This is how I thought about it....
K= 1 valence e
P= 5 valance e
You are correct by agreeing with the above....
But you have to understand that balancing a nonmetal and metal interaction (ionic bonding) involves understanding their electronegativity factor and how that relates to the octet rule.
Here P (non metal) is more electronegative because as you go up and to the right of the periodic table (or towards fluorine), you are more electronegative so this means that this atom will want to fulfill the octet rule more than K (metal) in this interaction.
So if P has 5 electrons in its valence shell and K with 1 electron in its valence shell, comes along trying to interact with P....well P going to take that 1 electron and now P has 6 electrons in its valence shell....and its going to take another electron from another K....and its going to take another electron from another K.....now it was has 8 electrons in its valence shell and it only took 3 potassiums to do so.
Hence, in a reaction between K and P, you are going to balance this reaction, by fulfilling the octet rule of the more electronegative atom, in this case P.
P is balanced when it is interacting with 3 Ks.
K3P1
this is at least how I look at it.
It have 5 electrons in outer shell then it needs 3 electrons to be stable
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