MsJovi102 Voltage is low, so no real hazards. Just take care as input to powerpack is from mains. Resistor can get hot for big currents so take care when handling. Sources of error: calibration of meters (zero error), reading scales on meters, minor fluctuations in readings during each trial; if you are going to find R of resistor using the graph gradient, then the resistance of connecting wires is another source of error to consider.
components may become heated due to the current flowing through the circuit, causing the effective resistance to increase which affects the p.d and current reading.
If you connect your power supply the other way around, the circuit will still work. A current will still flow (just the other way). The only difference would be that ammeter and voltmeter would show negative values if we reversed the terminals of the power supply.
I have a doubt .Suppose I connect the power supply directly to the ammeter .Does the ammeter give any value?Does this value is more than the ammeter reading when we out a resistor in the circuit.
Ammeter has very small (ideally zero) resistance. Thus, current will become very large if just the ammeter is connected (a short circuit). Most powerpacks protect against this by having a circuit breaker, which automatically turns powerpack off if current gets too big. Remember: current is voltage/resistance, so if resistance gets very small, current gets VERY big.
Hi, if you have a constant voltage supply, and want to use a rheostat to vary the voltage across the resistor/bulb, then connect your resistor/bulb as in this diagram - bit.ly/2M6ZzU9 - and put your ammeter in series with bulb/resistor, and voltmeter in parallel with the bulb/resistor. You can then use the rheostat to vary the bulb voltage from 0 to max.
my worst embarrassment as a physics student is my lack of knowledge about circuits... but this video helps a LOT. thanks man
same
same, I can handle theory stuff but when it comes to circuits i get so annoyed and frustrated
Same
you weren't the only one
Thank you . It was very useful . It cleared all my misconceptions . Keep up the good work
Who is watching in 2024😂
Meeeee😂😂
me 😂
7 yrs later he became a legend
Thanks.....It helped me a lot
Hey......I am replying on my own comment😆😆😆
Lol
Nice explanation...this video helped me so much ....👍
Well explained cleared all my misconceptions
It's just amazing and thanks because of you I passed in my exams
I had my practical exams tomorrow thank u for clear explanation
Same as me.
This really helped in my practical exam Thanks❤
it's sooooo helpful thnq really it hlped me a lot..!!
Thank you so much
It is really a very helpful video!!
Can you list some precautions and possible sources of error for an experiment such as this? Thank you.
MsJovi102 Voltage is low, so no real hazards. Just take care as input to powerpack is from mains. Resistor can get hot for big currents so take care when handling. Sources of error: calibration of meters (zero error), reading scales on meters, minor fluctuations in readings during each trial; if you are going to find R of resistor using the graph gradient, then the resistance of connecting wires is another source of error to consider.
components may become heated due to the current flowing through the circuit, causing the effective resistance to increase which affects the p.d and current reading.
Thanks its very helped for me
Thanks bro for the information 🙂
Very interesting video
It's really confusing in another tutorial the negative terminal of the transducer is connected to positive of ammeter
If you connect your power supply the other way around, the circuit will still work. A current will still flow (just the other way).
The only difference would be that ammeter and voltmeter would show negative values if we reversed the terminals of the power supply.
Thanks for perfect explanation!!
Thank you so much for your video is helpful for my exem perpose
helpful, well explained
Thanks l got it all
great sir u explain very well
Thanks for your support!
Very helpful kind sir. Have a nice day
I have a doubt .Suppose I connect the power supply directly to the ammeter .Does the ammeter give any value?Does this value is more than the ammeter reading when we out a resistor in the circuit.
Ammeter has very small (ideally zero) resistance. Thus, current will become very large if just the ammeter is connected (a short circuit). Most powerpacks protect against this by having a circuit breaker, which automatically turns powerpack off if current gets too big. Remember: current is voltage/resistance, so if resistance gets very small, current gets VERY big.
keep it up
May God bless your soul.
Sir please tell me how to plot a graph for Ohm's law flower.
U made it easy sr thanks
Thanks this really helped
Excellent job sir 👍😊
Thank you! Cheers!
Thanks !!!Dude!!!
Thanks helped a lot...👍😇
Very clear , thanks
nice video
its really working🤗😊
Well explained...thank you
thanks helped a lot
Great help.Thank you so much
This is wonderful
May I ask how do we know which wire to use to connect the terminals? And how to know which terminal connect to which?
Its colour coordinated
thank you!!!!!!!
thnx..it's very useful
Even Helpful after 7 years 😱😱😱
easy method thank you for
helpful thank you, sir
super
Thank you❤❤❤
thank you so much sir
I love this keep it up
thanks sir
Thank you so much!!
If I will connect ammeter after resistor (near positive terminal) what will happen. Is current varies?
Simple and good one.
🎉thank you
Informative!
Thank you
good idea
,thanks it is well understood
Thanks sir
very useful
Can u make good process to write in exam
Can you add a load like the knob type resistor box to this circuit
Name of Connective wire
Well explained.
Thanks
2021 and still helpful
thank u.very useful
Thank you sir👍👍👍
Need For exam can you explain it with whole process
Out of all the useless crap i learned in school circuits is by far the top of my list
Pls tell why ammeter is connected negative to negative and positive to positive?
They are just made that way - it's convention. If you hook it up the other way you will get a negative reading.
Good but where is the rheostat
e🅱ic
tysm very helpful
Haw to mark Ampiyr metor resisror....
can you make a video on the kinds of resistors?
Carbon Composition Resistor.
Thermistor.
Wire Wound Resistor.
Metal Film Resistor.
Carbon Film Resistor.
Variable Resistor.
Varistor
Light Dependent Resistor.
Among d 2 small machines which one is ammeter and voltmeter
Robert George The one with A on it is ammeter, V is voltmeter. It is kinda small, but you should be able to see it.
ohm law setting information is fine
thanks and love u
Rheostat kahan par hai
What is the name of the nosil you added to connect wire to key
Do you mean the crocodile clip? Some call them alligator clips :)
Tq..
After 30 min.... I have to give my practical 😂😂
Thankyou
Thx bro
no clear on reding
Can we make the circuit without using resistor or rheostat?
Tq
Hi
Where's rhrostat
the power source itself can alter the voltage across the circuit
Love it
Ohm my gosh you should try this application! scout circuit solver on the playstore!
Upload thevenins theorem
is voltmeter reads from zero or is just a source of error (+ error)
isnt voltage inversely proportional to current!!
No rheostat
shah j No. I am testing the effect of supply voltage on current so I am not changing resistance - so I am not using a rheostat.
Felix Olsson ok but can you make rheostat video circuit with rheostat plz😫😫😫
❤
Sir how to connect rheostat in this circuit
Hi, if you have a constant voltage supply, and want to use a rheostat to vary the voltage across the resistor/bulb, then connect your resistor/bulb as in this diagram - bit.ly/2M6ZzU9 - and put your ammeter in series with bulb/resistor, and voltmeter in parallel with the bulb/resistor. You can then use the rheostat to vary the bulb voltage from 0 to max.
thxx
How we we record the obseve data in this expeeiment
How much ampere it was ?
how many ohm did u use for resistor ?
Cant remember, but you should be able to work it our from the voltage and current😁