Lumped System Analysis

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  • Опубліковано 1 сер 2024
  • His video will derive equation of Lumped System Analysis in simple steps.

КОМЕНТАРІ • 52

  • @johnmosheim
    @johnmosheim 12 днів тому +1

    the clearest step by step derivations that a regular chem eng understands thanks a ton

    • @SampurnaEngg
      @SampurnaEngg  12 днів тому

      Thank you 🙏
      Please go through playlist of Heat Transfer subject - ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @Delta_07
    @Delta_07 Рік тому +2

    At video 10:35 how is possible the term ln(ti - ta) is positive when it will go to LHS then it will negative then how you place it to denominator

    • @kales.s.9395
      @kales.s.9395 Рік тому

      Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms.
      The step is correct.

  • @matharshaik
    @matharshaik 9 місяців тому +2

    Good explanation sir thank you sir please continue more heat transfer topics ❤❤

    • @SampurnaEngg
      @SampurnaEngg  9 місяців тому

      Thank you 🙏
      Please go through playlist of Heat Transfer subject - ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @bluzbucket7908
    @bluzbucket7908 3 роки тому

    Thankyou sir.

  • @kirank7350
    @kirank7350 Рік тому +2

    derive the expression for temperature distribution in a body at time t during a Newtonian heating or cooling is given by T-Ta / Ti-T = e^-BiFo. What is answer for this sir ? Same ansr in your video ?? Please reply sir

    • @kirank7350
      @kirank7350 Рік тому

      Please reply sir. This question asked in engineering heat transfer exam . Yesterday

  • @kaushalsonagra5149
    @kaushalsonagra5149 2 місяці тому +1

    Excellent concept explanation sir . Thanks

    • @SampurnaEngg
      @SampurnaEngg  2 місяці тому

      Thank you 🙏
      Please go through playlist of Heat Transfer subject - ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @-DanishShafi
    @-DanishShafi Рік тому +2

    at 11:13 you have done a mistake, when we take a term on the other side of equal sign it becomes either positive or negative, and in case of multiplication it goes into divide. how had you taken the ln term to divide?

    • @SampurnaEngg
      @SampurnaEngg  Рік тому +1

      Positive log on right side, when it moves to left side becomes negative and subtractions of log can be written as a ratio of the terms, so in the derivation log subtraction is written as ratio of terms.
      The step is correct.

  • @annjeena4194
    @annjeena4194 3 роки тому +6

    Sir...can u plz put video on heat transfer in semi infinite and infinite solids...

  • @methodseven6556
    @methodseven6556 3 роки тому +1

    very nice explain thank you sir

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @TonyMontana-yp1lh
    @TonyMontana-yp1lh 3 місяці тому +2

    nmt ln becomes minus not divide at 11:11

  • @512abrarazadbhat6
    @512abrarazadbhat6 Рік тому +7

    Tomorrow is my paper 🥺🥺

  • @sriramkadali9096
    @sriramkadali9096 3 роки тому

    Tnq

  • @natarajganesan5572
    @natarajganesan5572 5 місяців тому

    It can T infinity fluid temperature

  • @JitendraPavan-se3fc
    @JitendraPavan-se3fc 5 місяців тому +1

    Great explanation sir

    • @SampurnaEngg
      @SampurnaEngg  2 місяці тому

      Thank you 🙏
      Please go through playlist of Heat Transfer subject - ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @annjeena4194
    @annjeena4194 3 роки тому +4

    Previous video and this one is very helpful sir

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

    • @timepass5045
      @timepass5045 Рік тому

      Are you mechanical engineer

    • @SampurnaEngg
      @SampurnaEngg  9 місяців тому

      Yes

  • @shubhamkamble3187
    @shubhamkamble3187 Рік тому +1

    Thank you sir

    • @SampurnaEngg
      @SampurnaEngg  Рік тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @Chandankumar-qm4nb
    @Chandankumar-qm4nb 2 роки тому +1

    Thank you sir 😌

    • @SampurnaEngg
      @SampurnaEngg  2 роки тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @pavanvutukuri7482
    @pavanvutukuri7482 3 роки тому

    Where is previous video

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Previous videio-👇👇
      ua-cam.com/video/EYCp-sQoBFY/v-deo.html

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @VivekKumar-ui1ro
    @VivekKumar-ui1ro Рік тому +1

    nice

    • @SampurnaEngg
      @SampurnaEngg  Рік тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @sirftum8913
    @sirftum8913 7 місяців тому +1

    super sir 😘😘😘

    • @SampurnaEngg
      @SampurnaEngg  7 місяців тому

      Thank you 🙏
      Please go through playlist of Heat Transfer subject - ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

  • @SyambabuWAOI
    @SyambabuWAOI 3 роки тому +1

    super sir

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Thank you 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html

    • @SyambabuWAOI
      @SyambabuWAOI 3 роки тому

      Sir boundary layer concept

  • @laughingedits2172
    @laughingedits2172 2 роки тому

    You made mistake in log

  • @mafiamrkiller1347
    @mafiamrkiller1347 3 роки тому

    You have done mistake in log it will be difference.

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому +2

      Dear,
      Complete derivation is correct. Log difference can be written as ratio. For example logX- logY can be written as log(X/Y).
      Pls check.

    • @raswin8058
      @raswin8058 2 роки тому +2

      @@SampurnaEngg it can be written as log(X/Y) but not logX/logY as you have done in 10:45, kindly look into this!

    • @shadabpatel5813
      @shadabpatel5813 Рік тому

      Seems like sir also bunked imp classes like us

  • @bluzbucket7908
    @bluzbucket7908 3 роки тому +1

    Thankyou sir.

    • @SampurnaEngg
      @SampurnaEngg  3 роки тому

      Thanks 🙏,
      Please go through our channel playlist of Heat Transfer subject for more videos 👇👇👇
      Heat Transfer: ua-cam.com/play/PLxUmNri4cRzDG5v2Xay4PiWwZWK9Zx_e3.html