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hello Professor don't we have to check the biot number for this problem if not can you please explain why? because when i checked the biot number it is greater than .1 Bi=(hLc/K)=(20*50.025)/360 =2.77916 which is greater than 0.1 (Lc = volume /surface area= .07854/.001570=50.025)
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sir cud u pls tell me that what is the relation between newton's law of cooling and lumped body analysis..I mean exactly how are they related ? Are the same thing or a bit different? Or what Please make a video on that And newtons law of cooling is for every body whether lumped or not ? Nd do lump bodies topic comes under newtons law.??? Is it so ???
The values of C (heat capacity) and density should be those of copper, not of air. The question and answer should read "thermophysical properties of copper".
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load of peas at a temperature of 25°C is to be cooled down in a room at a constant air temperature of 1°C. (a) How long the peas will rquire to cool down to 2°C when the surface heat transfer coefficient of the peas is 5.81 W/m2 K? (b) What is the temperature of the peas after a lapse of 10 min from the start of cooling? (c) What air temperature must be used if the peas were to be cooled down to 5°C in 30 min? The peas are supposed to have an average diameter of 8 mm. Their density is 750 kg/m3 and specific heat 3.35 kJ/kg K.
Sir best way ..of teaching 🙏🏻
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hello Professor don't we have to check the biot number for this problem if not can you please explain why? because when i checked the biot number it is greater than .1 Bi=(hLc/K)=(20*50.025)/360 =2.77916 which is greater than 0.1 (Lc = volume /surface area= .07854/.001570=50.025)
Superb explanation. Very easy to understand.
Very clear language used seeing this I can solve problems like this
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Very nice Sir ji.very well explanation 💐💐💐👌👌
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sir cud u pls tell me that what is the relation between newton's law of cooling and lumped body analysis..I mean exactly how are they related ?
Are the same thing or a bit different? Or what
Please make a video on that
And newtons law of cooling is for every body whether lumped or not ?
Nd do lump bodies topic comes under newtons law.???
Is it so ???
Sir this video is not available in HT Playlist
The values of C (heat capacity) and density should be those of copper, not of air. The question and answer should read "thermophysical properties of copper".
Nice sir
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Sir please do sum problems on heat exchangers
Sure, I will do.
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load of peas at a temperature of 25°C is to be cooled down in a room at a constant air temperature of 1°C.
(a) How long the peas will rquire to cool down to 2°C when the surface heat transfer coefficient of the peas
is 5.81 W/m2 K? (b) What is the temperature
of the peas after a lapse of 10 min from the start of cooling?
(c) What air temperature must be used if the peas were to be cooled down to 5°C in 30 min? The peas are
supposed to have an average diameter of 8 mm. Their density is 750 kg/m3 and specific heat 3.35 kJ/kg K.