What I like about this is, the same skills by which you find the derivative will come into play again when you do epsilon-delta. For a more general proof of the derivate of x^a, I had to resort to logarithmic differentiation.
All first principle videos: Square root, all arctrig except arccot, plus some other various functions. Gotta say, I feel like a bit of a teachers pet doing this, he has a playlist. But its here for the record too
I've always wondered: why does the limit definition give the slope? Perhaps I never fully understood it, l'm in Calc3 now, but it seems like you'd get 0 in the denominator, of course that's undefined. Logically, it makes sense, but it's just never worked conceptually in my head.
It’s the (y2-y1)(x2-x1) definition of the slope of a line at two points very close together. The goal is to get the “h,” which is technically nonzero, to cancel so that there is no division by 0 when you approximate “h” to be 0
The first principle is to watch all the videos by Prime Newtons! ❤🎉😊
Never stop learning
Wow, No one can explain it better than this, this guy does not skip even the obvious step….impressive, clear.
You reminded me of this lesson when I was 17 years old. Now I am 60 years old. Thank you.
*_Never stop learning._* Advice I liked to give my own students. And when you master the understanding, you can more easily do word problems.
😎♥✝🇺🇸💯
As soon as I saw you I just knew it was gonna be exactly what I needed. Cheers mate
It is a universal truth that applies in all human endeavors: when you want to understand something, always start with first principles.
Once i learned the power rule, I never looked back. But this is so important to know...its how you solve complex stuff
Along with the math, dispensing valuable life advice like "never touch the bottom"
What I like about this is, the same skills by which you find the derivative will come into play again when you do epsilon-delta.
For a more general proof of the derivate of x^a, I had to resort to logarithmic differentiation.
Finally i got what i was Searching for ☺️☺️♥️♥️
love your sir from 🇳🇵♥️
❤❤❤❤great sir😊😊
How fabulous the presentation on the math question😊
Nice broh 🙌🙌
It is just beautiful! Good job.
Very clean proof, my friend. 👍
You are a good teacher ❤
i did this by using newton's binomial theorem to expand (x+h)^(1/2) but then i realized you can just multiply by the conjugate 😅😅
Is it possible to use the same principle to prove the derivation rule for generic radials (derived from the nth root)?
Awesome 🙌
👍
Great explanation thank you! What chalk do you use? It looks amazing by the way.
very well explained!
Very good. Thanks 🙏
Thank you 😊 sir
All first principle videos: Square root, all arctrig except arccot, plus some other various functions. Gotta say, I feel like a bit of a teachers pet doing this, he has a playlist. But its here for the record too
Thank you. Now I know I have to do arccot x
Just wonderful!!!
I've always wondered: why does the limit definition give the slope? Perhaps I never fully understood it, l'm in Calc3 now, but it seems like you'd get 0 in the denominator, of course that's undefined. Logically, it makes sense, but it's just never worked conceptually in my head.
It’s the (y2-y1)(x2-x1) definition of the slope of a line at two points very close together. The goal is to get the “h,” which is technically nonzero, to cancel so that there is no division by 0 when you approximate “h” to be 0
Where is the 1/root x derivative video? I can't find it on your channel sir.
ua-cam.com/video/BX1-byIHJ44/v-deo.html
@@PrimeNewtons thank you very much sir.
Thank you very much sir!
The coolest maths teacher I've ever seen 😎👍Your explanations are very clear and easy to understand 😊 Thank you for such lovely videos 😇
... f'(X) = LIM(h -> 0) [ SQRT(X + h) - SQRT(X) / h ] ... [ rewriting the denominator in its original form ... h = (X + h) - X ] .... LIM(h -> 0) [ SQRT(X + h) - SQRT(X) / ( (X + h) - X ) ] .... now treating the denominator as a Difference of 2 Squares as follows ... h = (X + h) - X = ( SQRT(X + h) - SQRT(X) )( SQRT(X + h) + SQRT(X) ) ... observing a common factor ( SQRT(X + h) - SQRT(X) ) between numerator and denominator, so after cancelling this factor we obtain the solvable LIMIT form ... f'(X) = LIM(h -> 0) [ 1 / ( SQRT(X + h) + SQRT(X) ) ] = 1 / ( SQRT(X) + SQRT(X) ) = 1 / 2*SQRT(X) ... the derivative of f(X) = SQRT(X) ...
Bravo
Please explain the derivative of a factorial function
Yes! It cant be calculated via first principles but interesting nonetheless.
You are the best. Many Thanks
I love you ❤
Should we as viewers scower your videos to see which principles you havent done
Hyperbolic tangent maybe?
Yes please
w proffff
Bros cooking
asnwer=1x