Can you zoom out the questions so I can see the question and the working out the same time so I know what you're doing (escpecially with the quantitive chem)
That first step is to find out how much oxygen is used up in the reaction. You take this away from the total amount of oxygen you started with to see how much would be left over at the end of the reaction. To work that out, you can use the molar ratio of your balanced equation to find the volumes as all volumes were measured at the same temperature and pressure. We know that for every 2 mols of Si2H6, 7 mols of O2 are reacted, so if the volume of Si2H6 is 30 we should do 30* 7/2 to get volume of O2. If you watch the working out again it should hopefully make sense!
Timestamps
0:20 Question 1
5:34 Question 2
14:48 Question 3
18:22 Question 4
24:23 Question 5
29:20 Question 6
34:23 Question 7
43:08 Question 8
Thank you for this video, please make more of these as it's really helpful
this was really helpful. tysm
Glad it helped!
Can you zoom out the questions so I can see the question and the working out the same time so I know what you're doing (escpecially with the quantitive chem)
in question 7.6 i think i might be dumb bc why did u do 30 x 7/2 i thought the equation was vol = moles x 24 what equation did u use
That first step is to find out how much oxygen is used up in the reaction. You take this away from the total amount of oxygen you started with to see how much would be left over at the end of the reaction.
To work that out, you can use the molar ratio of your balanced equation to find the volumes as all volumes were measured at the same temperature and pressure. We know that for every 2 mols of Si2H6, 7 mols of O2 are reacted, so if the volume of Si2H6 is 30 we should do 30* 7/2 to get volume of O2.
If you watch the working out again it should hopefully make sense!
@@HitTheBooks1 THANK YOU SO MUCH
Can u do some on physics and bio maths would be great
Absolutely - should be coming over the next few weeks!