Simple Equations 6 | CAT Preparation 2019 | Algebra | Quantitative Aptitude
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Simple Equations by Ravi Prakash | Algebra Quantitative Aptitude for CAT 2019
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11:16 ans 62
Y +22=( x-5) - 35
= X - 40
X-y = 62
Yess bhai correct....Ravi siir plzz check and correct ❤️
Are calculation mistake hi mat dekho bs sir ne assumption bhi galat lia h kbhi kbhi sir se bhi mistake ho jaati h answer mill be 52
@@prakharsrivastava3963 kya glt h asumption ma, pls reply
@@prakharsrivastava3963 solution to bata de bhai, suspense mai chhod dia.
@@prakharsrivastava3963 52 nhi 62 huva
I love this teacher. He coyly smiles telling us a peacock has 1 head and 2 legs.
rabbit have 4 legs I was surprised for a second there to be honest
@@KlutchyRexhas*
sir, there is a mistake -35-5=40 not 50 in that chocolate question
@simransuneja4327 Will you please explain how come X-Y is the value of no. Of chocolates from student 3 to 12. Coz Y is no. Of chocolates 2 child has. X-Y doesn't eliminate amount of chocolates 1 child has
@@All_toons23 x-y does eliminates 1st & 2nd child. 1st have x-5 chocos, rest 11 has x chocos and 2nd has y chocos, so x-y will be the no. of chocos 3rd to 12th children have.
in first question
Stage I : A=y+x & B=y-x
Stage II : A=y & B=y
Stage III : A=y-2x & B=y+2x
so now after solving you will get x=20
stage 3 mai y+4x ayega na y+x+3x B Pe aapne y+2x kaise likha hai?
Thanks 😊
one doubt what is why here
@@naveenkamath907 plzz reply whaat is y here
I was looking for this, thank you
Sir's equation and answer is correct we are backtracking the equation and logically B has more no of chocolates for question 1
11:62 62 choco.
Right ...
@@vishnuyadav-ip6ul are you writing cat this year?
@@MsRohitshaw no preparing for elitmus
@@vishnuyadav-ip6ul Best of Luck 🤞
@@MsRohitshaw thanks brother...
Thanks for the whole new approved for attacking these questions. 😍 Loved the little information in between. 😆😆
approach*
The way you teach is so simple and easy to understand. I get all the concept in one time only. I would be lucky of i get one on one classes with you
Do you need gejo sir varc?
Genuine faith towards u ,helps a lot 😊
Last question .
17 chocolates left with me after giving 7 more than 1/3 of a no of chocolates .so this no should be 2/3 of 24( ie 17+7) hence 36
36 chocolates left with me after giving 6 more than 1/4th of a no of chocolates , so this no will be 3/4th of 42 ( 36+6) hence 56
56 chocolates left with me after giving 4 more than 1/2 of a no of chocolates .so this no will be 2/1 ie twice of 60( 56+4) hence the no of chocolates is 120.
Why 2/3?
@@gsh8596cause he already gave 1 /3
@@gsh8596 Bhai percentage wala rule 1-1/3= 2/3
20) Affer the impending birth of identical twins, the percentage of boy grandchildren of old
Johnny will be either 33.33% or
44. 44 %.find the Total no of grandechildren old Johny has now
(exduding twins)
16
, 20 ,
24 ,
Canit be determined
16 is the ans using options , so total grandchildren will be 18 including the twins
33.33 % will be 1/3 of 18 which is 6 boys if identical twins are girls and 44.44 % will be 8 boys if idenitcal twins are boys
In the 12 children question, what sir has done is absolutely correct, I have applied the logic in a similar question and answer was correct. Only there is a slight error in calculation, ans is 62
Sir i feel the solution for the first one is wrong. As its A who asked B for chocolates and hence equation for A should be y+x and B should be y-x. X is equal to 20
I think it will be in this way,
Let the number of chocolates with 12 children are c1, c2 .......c12.
Now,
let c2+c3+ ..+c12 = x
this means c1 = x-5
and total chocolates with all 12 children = (2x-5).
And it is known that, c1 + 22 = x-5 -35
c1 = x -62
So, total number of chocolates with 1st and 2nd, c1 + c2 = x-5 + x -62 = 2x -67,
Number of chocolates with c3, c4, ......, c12
= Total Chocolates - (c1+c2)
= (2x -5) - (2x - 67) = 2x -5 -2x + 67 = 62 (So, Answer should be 62).
I too think so
I did the Peacock- rabbit question with the same approach as you did without even watching your way(i paised the video).
3 months of watching your videos finally have a positive impact on me!
Thank you so much sir! 😁😁♥️♥️🙏🏻🫂
bro can you solve by method 2... im facing issue solving with method 2....
i feels like soluion is wrong because question is not saying that 1 person initially have total no. of chocolate -5 its saying when he is trying to double then he is short of 5 there is a difference so initailly should be x-2.5 only then if he doubles it
Yes thats what i am trying to understand here..
the last question was full of concepts, these kind of questions were asked in previous years.
Hello sir, can you please explain, here in 1st statement A Told B to give "x" then why we solve for A" y-x" instead of "y+x"
Because initially before asking, A had y-x chocolates, only when B gives him x chocolates, he'll have y chocolates
Hats off@@purvifying
New approach to the last sum,
The initial choc. has to be the multiple 2,3 and 4, because he is dividing by this no.
and by reasoning you should start with atleast 120 because he is giving away 17choc and still left with 17 even after divinding it 3 times.
Wow, nice approach! Thanks.
Yes but LCM(2,3,4) = 12.
So answer could be 24,36,48......... Why 120 only
@@techsmash6907 better check options if any of them is a multiple of 12, it's rare to have 2 multiples of 12 as they are bit far and options are close usually
@@neelkaneriya262 it will come under TITA lol
I solved it by taking initial number of chocs as (2*3*4)x.
peacocks and rabits question can easily solved by allegetions
Could you please explain how?
take 2 assumptions
1 where all animals present are peacocks and the amt of legs in that case are 168 this is your 1st extreme and 2nd extreme is where all the animals are rabbits, will be having 336 legs and this will be your 2nd extreme and the resultant of that mix is the amt of legs given that is 222
so 168-------------------------222------------------------------336
54 114
ratio will be 9:19 and therefore the amount ratio will be 19:9 i.e. out of 28 animals 19 are peacocks and 9 are rabbits
84/28 = 3 this is your 1 unit so 19 units is 57 and 9 units is 27
@@shashanktomar7670well then I guess it can't be solved "easily"
I think first is also wrong bcz if A has given x chocolates to B so that they will have equal number of chocolates, this means before giving to B, A had y+x chocolates. and also now let B had some N chocolates and since he got X more and his chocolates become N + X = Y i.e. initially B had Y - X chocolates. Thus , can say
A B
Stage 1. Y+X. Y - X
Stage 2 Y Y
Stage 3 Y+X - 3X Y - X + 3X
After stage 3 we know the difference between the no. of chocolates they have is 80 and also know that B has more chocolates i.e. B's Chocolate - A's Chocolates is equal to 80. Hence
(Y - X + 3X)-(Y+X - 3X)= 80
X=20.
But don't know how did sir take it Y-X for A and Y+X for B,If I have done any mistake please tell me, I wanna know whether I interpreted question correctly or incorrectly.
Same doubt bro !
Did you get it cleared ??
You interpreted the question wrong. A asked B that "give me x chocolates", you thought it to be other way around.
I think in Q2 the number of chocolates will be 62. How can we identify in a question whether it's a reverse approach ? As, last question was straight forward, so we can take reverse method. How about other questions?
11:7 (x-5)-35 gives x-40 not 50 and hence x-y=62
Just hate music😒.but love teaching 💓🥰
absolutely irritating, but ravi prakash is terrific
@@shobhitmittal4273 Ravi Prakash Sir*
8:43 if 1st have 95 chocolates and all others have 100 chocolates then after taking remaining chocolates 1st will have 195 chocolates which is more than double(95*2) choclates. but in question he fell short by 5 chocolates.
1st have 100 chocolates(x+5) and all others have 95(x) chocolates so in attempt to double(100*2) he fell short by 5(100+95).
it should be like 1st have x+5 chocolates and all others have x chocolates.
If I understand question correctly then above should be approach to solve.
if all people have 100 chocolates and you short of 5 that means you have 95 chocolates but question says you falls short of 5 chocolates when you try to double not in a initial phase so initial chocolate should be x-2.5 only then it comes 95
Please explain why 54 legs divided by 2 and not 4 as each rabbit would have 4 legs
becoz these 54 legs are of rabbit who have 2 extra legs (as already 2 legs of rabbit is counted in 168 legs so abhi bhi 2 extra legs of rabbit are left na so we are dividing ... the extra total legs of rabbit by each extra leg of rabbit. i.e 54/2= 27
Peacock has 2 legs, not 4@@shriyachopra2148
English needs to learn you. Bro you are not getting the statement right
In this question 14:23 I applied alligation method and managed to solve it easily. Being from humanities background but with profound interest in Mathematics, I was elated! Thank you, Ravi sir!
Can you explain how
@@himanshuk8085 Thank You!
in first ques if we take a+x=b-----(1) b+3x=80+a------(2) x will be 20 which is satisfying the eq. but by the way you have done it i am not saying its wrong but it does not satisfy the eq. or am i doing something wrong plzzz help
Bhatti bhai abhi bhi kabul line mai hai kya?
bhai hindi ka prayo kariye kuch smjh nahi aya ki to kehena kya chahta h ; }
@@visuder7412
I got the same answer!
my economics teacher also also teaches like sir but he cracks more jokes and
i never needed to remember answers in 11th and 12th (ratta)
i still mis his lectures
Answer should be 60 at 11:00 as the second child have to take 2 chocolates from each of 3 to 12 ..there will be 10 children
y+20=(x-5)-35
x-y=60
the answer will be 62
he will take 22 chocolates from all the remaining 11 ( which also includes the child at position 1)
@@nishantsingh7816 answer is 60
first question sir make wrong equation , it is not any where that a and b are equal , we can solve this question ,
A=a , B=b
a+x=b-x ,
a+2x=b ------------(1)
b+3x=a-3x+80 ,
b-a=80-6x-------------(2)
taking value of b from first eq.
a+2x-a=80-6x
x=10
No yaar
Lets understand with example .... IF U HAVE 2 CHOCOLATES AND I HAVE 4 AND STATEMENT IS I GIVE U 1 WE BECOME EQUAL . BUT IF WE WANT TO GET TO THE ORGINAL NUMBER OF CHOCOLATES THEN WE CAN SAY WHEN WE BOTH HAVE EQUAL NUMBER OF CHOCOLATES (NUMBER OF CHOCOLATES WITH YOU MINUS 1 , NUMBER OF CHOCOLATE WITH ME PLUS 1 ) WHAT SIR DID WAS PERFECTLY RIGHT , WITH LESS VARIABLE , YOUR SOLUTION IS RI8GHT TOO :)
I google bard that chocolate wala question it is giving ans as 23 😅
I also give CAT questions to ChatGpt (v 3.5). It gets them wrong 😂
In 2nd Question, 1st person's value should be (x+y)-5
if we take x-5 as 1st person's value then x should the value of person's 2nd to 12th persons but 2nd person's value is taken as y
so how can 1st person's value be x-5 as 3rd to 12th person's value is taken as x
please correct it if I am wrong
Bhai 54 legs remaining so each rabbit must have 4 legs that means 4 legs combine to make one rabbit right so it should be 54/4 right?
Is this the last video on linear equations
Is this last vedio of simple equation?
Y +22=( x-5 - 2) - 35
= X - 40 -2
X-y = 60
Hello, i have a little doubt at 10:21. How can we conclude that x-y is the amount of chocolates with children 3 to 12. As we've been told 'x' is total amount of chocolates with students from 2nd to straight away 12th. 'y' is amount of chocolates with 2nd, but there is 1st kid as well. We ignored him and got x-y as no. of chocos with 3rd to 12th as 'x-y'
X is the value of 2nd child to 11th child. 1st child is excluded.
Even I didn't understand
@@aaliafirdosusmani299 x is the number of chocolates in total from child 2 to 12. and y is the number of chocolates 2 has. so to get the number chocolates from 3 to 12, you subtract y to x that is chocolates with 2 to 12 minus chocolates with 2
@@aaryanair5274 but what about 1 kid
@@yashjambhale647 read the question once again we have to find no. of chocolates with 3rd to 12th kid we have been asked in the question to ignore the first kid :-)
hope you got my point .
How to solve the equation of rabbit and peacock ?
and if 1 first person distribute all his should he reamains with exactly the same amount
2:03 sir in this question how it is A = y - x , B = y + x....how it is?
If B give x chocolates to A then it will......A = y + x , B = y - x....ye aise equation hojayegi na 🙁
Yar please koi reply karke explain kare muze 🙏🏻🙏🏻🙏🏻.
Same daout iam also stuck in this question please somebody figure out this problem
@@RoshniKumariBBASEMSECTIONB in question B is giving x chocolates to A to make it equal. that means initially B has more chocolates and A has less chocolates therefore for B we took y+x and for A y-x. I hope you got it
This was last video right?
At 9:58 the 2nd question if we assume chocolate with the first child be 'x' and the remaining 11children have (x+5) chocolates. And 2nd child have y chocolates and after taking 2 chocolates each of the other children he will have = y+(2×11) = y+22. Then by question
y+22 = x-35
x-y = 57. Is this wrong ?
Yes because if you assume chocolates of remaining 11 children to be x+5 then no. Of chocolates from 3rd to 12th child will be (x+5)-y... And not x-y
If I'm taking 120 as total number of chocolates and verifying this value in the equation I'm left up with 19 chocolates but according to question 17 chocolates are left. Can someone explain this to me 🤔
you have to subtract 19 from 36, then you''ll get 17 : )
ya same issue
I believe the answer to the second question would be 52.
thankyou so much sir
11:06 me 1st child ko subtract nahi karege qki agar hm X-Y karege to 1st child bhi to rahega qki X hmne whole 1 TO 12 ko liya hai ar Y sirf 2nd child ko
No, sir took X to 2nd to 12th child and automatically 1st child has X-5 and Y to only second child.
i got same doubt
Thankyou 💜 so much sir ✍️
How u have taken y+22 it means that u have taken into consideration that each of them have 1 chocolates initially which is not at all mentioned anywhere.
Hi Ronit. It's written in the question that 2nd child took *exactly* 2 chocolates from each of the other children. Total children are 12. Therefore, he will take 2-2 chocolates from 11 children. 11x2=22 Chocolates. I hope it helped ;-)
@@SahilRamola10:56
Hey check at rhs (x-5)-35 will lead to x-40 naa
Where we can get these questions to practice?
Thank you Sir 🙏.
I pronounce fantastic differently now
Sir, in the 1st question, how can we understand both the statements are linked?, looks like both are individual statements not consecutive to one another. For me I got x = 20. Please kindly clarify.
Hey, I didn't get the 1st question. Can you please share your solution?
Thanku sir
I have a doubt in 1st question. If y-x-3x=y+x+3x+80 . Then x=-10 but sir says x=10 . How.? Anyone please can explain me 🙁
It should be reverse of it. The equation is reversed by sir . Equation should be y+x+3x=y-x-3x+80 than the correct answer should be 10. Hope u understand now
@@rahulsinghchauhan6182 thanku Now I understand 🤗
Last question is fantastic
For the last question, rather than doing it with reverse method, if you do it with percentage method, n assume the number of chocolates is 100%, then you get 12% left at last. N if 12/100 of x = 17, then x we get as 141.67
How can we use percentage? Because additional chocolates cannot be correlated to initial chocolates
sir, in the second question, if the 2nd child took 2 chocolates from all of the rest, then he would have taken 20 chocolates in total as there are 10 people behind him. The question doesn't specify if the first child should be considered or not but I think it won't be considered and the answer will be 60, not 62 or 72.
11 people not 10, its says from each of the other.
important info🤣💓
thnkuuuuuuuuuuuuuu sirrrrrrrrrrrrrr!!!!!!!😍😍😍😍😍
sir theres no video on three variables in this series and not even on difference of two squares type of questions
hie did you get any material for the same i want to complete those topics too ... thanks :)
@@himanshuthakur9274 no i just did it from random you tube channels , by cat pyq,q . solve cat 2017 to 2022 pyqs for the same from you tube videos and you will be sorted
Answer of the 2nd question is wrong correct answer is 62
How
Thank you sir
The solution for 1st question is wrong.
Yes absolutely correct
@@zayedali-bf1tr Ye takle ko nahi aata isse mat pad
Kya wrong hai ??
@@Rodha B should give chocolates to A in first case. You have taken that: A is giving chocolates to B. Which is wrong.
@@palashbundele535after giving x chocolates toA B left with y chocolates...whts wrong in it🙄
In first question what is y=?,total no.of chocolates=? Please tell me how to find
still need?
At 10:55 it is x-40 instead of x-50
Answer is 62
at 10:55... from where we get x-50 ..i didn't get it
that is x-40, think calculation mistake
Thanks for important information sir .😆😆
In second question 2 child have less35 chocolate than1st child after collection then in eq we have to add35 to first child but sir subtracted how please explain me😥😥😥
leave cat prep
@@rakshitchauhan3866 😂
Sir aapne 2 Eqn , 3 Variable wale Ques. nhi kraye h
Didn't get the last question
52 chocolates
27 rabbits would have 4 legs each thus 108 total legs and this remaining legs would be 222-108=114 thus how peacocks have 168 legs not possible
Sir x= 20 not 10,
11:00 ANSWER WILL BE 62
That friend is sanki !
CHOCLATE SOLUTION 62 ANSWER
Sir, if we resubstitute the values, it's getting different.
To his first friend, he gives 4 chocolates more than half
= 60+4=64, but we have got 56. Please help
56 is the number of remaining chocolates 120-64=56 (and he gave 64 to his first friend 120/2+4=64)
i think ans is 180
10:53
Isn't (x-5)-35 = x-40
No it will be x-30, so ans will be 52
@@teartriceps can you explain ?
Yes.. I was thinking the same thing...💯
Sir first question answer x=20
I think at 11:06 the answer should be 62
Yes 62 it is.
Yes
Can someone explain why it is 54/2 in the peacock and rabbit sum
Because rabbit has 2 legs more than peacock............thats why divide it by 2
You already accounted for one pair of the rabbit legs and all of peacock legs in 84×2. The legs that are left are the other pairs of rabbit legs only. Legs left=222-84×2=54. Hence, you divide 54 by 2 to get the number of rabbits.
Bhai 54 legs remaining so each rabbit must have 4 legs that means 4 legs combine to make one rabbit right so it should be 54/4 right?
@shriyachopra
we just assumed all 84 heads as head of 🦚 but in that heads of 🐇 also present right !
& for total 🦚 + 🐇 ( 84 heads ) , legs = 168.....now look we just considered only 2 legs here......so left over legs...that's 54 will be just other pair of legs of Rabbit 🐇 so u got 54 / 2 = 27 Rabbits 🐰
( just remember 84 is total no of heads we just assumed it to be of peacock.....& in that whatever be the no of raabbits we have just calculated it's 2 legs......when we distribute other 2 legs from remaining legs we get total no of rabbits....I hope it helps :)
❤️❤️
17:13 can any one explainthat funda why i'am calculating 1/3 rd of that 24 chocolate
Exactly what I'm wondering :/
I think sir made a calculation mistake there in question it is 1/3 but sir wrote 2/3
but if you asking what is the calculation method
👇
When we were going in forward manner chocolates distributed was 2/3 of 36 chocolates i.e 36 X 2/3 =24
but to find the answer we are going in Reverse Manner(Reverse Approach) so we have to calculate 3/2 of 24 i.e
3/2 X 24= 36
Sir in the first question why did u take equal chocolates initially? It is not mentioned they have equal chocolates right?
jahnavi gannu y is equal to the number of chocolate when A and B have equal number. It means when they start out A has y-x and B has y+x chocos
Sir takes the point where a and b has equal number of chocolates, as y. So how did it come to be equal? -> when x is reduced from b and given to a. When x is reduced from b, it becomes y. So, before b should have value y+×. Similarly a should have value y-x, so that when x is(given) added to a, it will become y.
I had a simple approach, what I did was:
Given A gets x chocolates from B. And if it happens, both will have equal no of chocolates. A becomes A+x, B becomes B-x. Now both are having equal chocolates,
=> A+x = B-x
Also, B gets thrice(3x) of chocolates from A, B will have 80 more than A.
=> B+3x = A-3x + 80
=> A-B = 6x-80
Also, from the first equation, A-B = -2x
Equate both the equations,
=> 6x-80 =-2×
=> 8x = 80
=> x = 10.
Where is the 7th video?
Did u find it ?
X will be 20 in the first question.
Shreya 10 is right but sir's equation is wrong
@Shreya Jha. Well The answer is right. The answer will be 10 only.
Carefully note Ravi Sir is going from 2nd statement to 1st statement.
So since he is going reverse. You need to reverse the 1st statement as well.
So Answer is completely fine
@@Sidswamiofficial Sir Equation is completely right. As I mentioned sir is following reverse approach from 2nd statement to 1st statement instead of going the other way round
Lets cook those extra legs😂
Sorry for this
Let the person is having 'x' chocolates.
1st friend - ( x/2 + 4)
Remening choc. = ( x/2 - 4)
.
2nd friend - [ 1/4( x/2 - 4) + 6 ]
Remaining choc. =
[ 1/4 ( x/2 - 4) - 6 ]
.
3rd friend -
{ 1/3[ 1/4( x/2 - 4) - 6] + 7}
Remaining chocs.
= { 1/3[ 1/4( x/2 - 4) - 6] - 7}
.
At last,
{ 1/3[ 1/4( x/2 - 4) - 6] - 7} = 17
Thrf., final answer is getting,
'x= 368'!
.
Help me with this anyone...
After giving 2nd friend, remaining chocolates would be [3*1/4(x/2 - 4) - 6] as he is giving only 1/4th part to 2nd friend and 3/4th would be left with him
12:04 is a very information 😂😂😂😂😂😂😂
very important info.~🤣🤣
another very important info.~🤣🤣🤣🤣🤣🤣🤣🤣
In first que ur first statement is wrong when B is giving x chocolates then y-x
It is completely correct
yes it should reverse of it..... for A it must be Y + x because he wants x chocolates from B
@@avinashnair8433 watch it again broo...
@@prayasdivlogging6925 ...it's completely correct...reverse process....difference between them is of 2x and when b will give x chocolate to A...then x will get cancelled on A side and both will be left with y chocolate...put X=10 and crosscheck by taking initial value (A=60 and B= 80) 👍
@@prayasdivlogging6925 what sir has written is correct. Yes A recieves the chocolate. But A and B values are taken to be y, when the transaction of x had already happened. So to come to the point of y(from I to II), A had received x chocolates. So before, A was having y-x.
So when A receives x chocolates, at II, A will have y-x + x = y chocolates. That's y sir wrote it as y-x in I . This is quite confusing, it takes more time for us to understand.
Very Important Information 😂
Explanation op 🔥
That short cut method for rabbit peacok i could not get. can someone tell. Why 54/2? Can you tell?
@@dhruvsharma9083
Bro 54 legs are extra (after counting peacock’s legs) .
There are total 54 legs left . But one rabbit has 2 legs left .
Therefore 54 /2 = 27 rabbits
It’s just like u got 10 chocolates for 100RS
so for 1 chocolate u spent 100/10 = 10Rs
@@dhruvsharma9083 there were total 222 legs
But 168 legs were of peacock
Therefore remaining 54 has to be of rabbits
@@piyushbarkur2112 but a rabbit has 4 legs , Right ??
@@dhruvsharma9083 yes they have 4 legs but we already counted their 2 legs .
Ok see .
Assume that each of them has minimum 2 legs .
Total 222 legs .
168 legs of peacock .
54 legs left of rabbit ( we already counted 2 legs of rabbit )
We assumed that each of them minimum has 2 legs . So now we will divide 54 by 2 because the other 2 we have already counted while assuming
First answer x=20
Verification: Let a=2 then,
2 + 20 = 22
now b=22
according to the statement
b + 3x = 80+a
22 + 60 = 80+2
82=82
therefore x=20
Same
So according to u B initially had 42 chocolates....then 42+60 would be 102 not 82
@@purvifying it's 22+60 intially 22
1st question is wrong
answer should be 20
Hi, no it's correct he is doing in reverse way
Both should have equal by b giving to a and a receiving from b
Which means
B should have had one extra before giving
And a should have had one less before receiving
Hope it clears
Thank You Sir