You , deserve all the appreciation i could offer at this moment . man you just saved me a lot of time . effort and money . Liked + subscribed + favorite + notifications
A couple of things: 1. When you draw the gears '3D' the major axis of the ellipse is 90 degrees out of alignment. The gears look too 'tall'. 2. When you discuss the radius of the gear, you need to clarify if it is the pitch circle radius or the base circle radius. To me, it looks like you are assuming that the force (derived from the torque) is acting through the line of action which is at a tangent to the two pitch circle diameters? If so, it doesn't, the force acts at a tangent to the two base circles. If this is the case (I may have misinterpreted your calcs) consider redoing the video as all of your component calculations will be incorrect.
Great video 👍. Do you have any videos on understanding the concept and calculation of transmission errors in spur and helical gears? and also calculating the load rating in bending and pitting ?
Hello Thank you for your excellent effort. I have a question please At 6:19 you say the reaction doesn't exist the summation torque will not be zero Can you kindly explain this again please?
Great video but i believe you messed up on the Torque conversion (time stamp 10:07) you have 12 in in the denominator when it should be in the numerator
For a person who is learning things on gears your videos are helping alot.... I was just wondering why didn't I come across this channel earlier. I have a doubt and would be glad to get the reply sir. 1. Why would you take the radius as 1/6th of a foot. 2. What if the bearings are not equidistant then how do we do it In that case. Thank you in advance.
Thank you for this nice video. I would like to ask how I can calculate the radial and axial force components acting on the bearings of an electrical motor.
The axial and radial forces are found through the gear-shaft-bearings setup you have. It depends on the number, location and type of both the gears and the bearings. Here's a video on radial and axial loads on bearings: ua-cam.com/video/3b8yOMSWXXk/v-deo.html
Lot of great stuff, the math is not a problem, I am I'm struggling with artificial speech, so I muted the speech and turned on the translation and that's a shame
CORRECTION: At 10:07, the 12 should go in the numerator for the correct unit conversion.
This channel is literally the best for revision before an exam, important concepts with amazing illustrations, just wow !!
Thanks! Share with others!
@@LessBoringLectures already shared
You , deserve all the appreciation i could offer at this moment .
man you just saved me a lot of time . effort and money .
Liked + subscribed + favorite + notifications
Wow, thanks. Share with others!
Best Video i've ever seen regarding this topic, You are amazing!
This guy is awsome.
His videos are faaaar more better than everything taught in university
Thankyou for the video. It was stuck in the force analysis. This helped me to understand it better.
This guy deserves far more subbs
clear and sound explanation with great graphic, thanks for the sharing
Great video.. Literally cleared my cocepts
just saved me on my gears hw, thanks brother, awesome video!
can we download a pdf of your notes?
It was really helpful. Thank you.
Keep up the good work. Way better than my engineering professor
Let's hope your professor doesn't watch this channel
God bless you, Thank you so much for these videos
A couple of things:
1. When you draw the gears '3D' the major axis of the ellipse is 90 degrees out of alignment. The gears look too 'tall'.
2. When you discuss the radius of the gear, you need to clarify if it is the pitch circle radius or the base circle radius. To me, it looks like you are assuming that the force (derived from the torque) is acting through the line of action which is at a tangent to the two pitch circle diameters? If so, it doesn't, the force acts at a tangent to the two base circles. If this is the case (I may have misinterpreted your calcs) consider redoing the video as all of your component calculations will be incorrect.
Amazing video! Wowowowow!
Great video 👍. Do you have any videos on understanding the concept and calculation of transmission errors in spur and helical gears? and also calculating the load rating in bending and pitting ?
Thank you
Love it!
can you provide notes of your less boring leactures?
great job man
Hello
Thank you for your excellent effort.
I have a question please
At 6:19 you say the reaction doesn't exist the summation torque will not be zero
Can you kindly explain this again please?
What kind of tablet are you using, that thing is awesome
Great video but i believe you messed up on the Torque conversion (time stamp 10:07) you have 12 in in the denominator when it should be in the numerator
You are correct! Thanks!
keep going, nice content for engineer
Nice presentation... What's the app you're using for the presentation sir?
For a person who is learning things on gears your videos are helping alot.... I was just wondering why didn't I come across this channel earlier.
I have a doubt and would be glad to get the reply sir.
1. Why would you take the radius as 1/6th of a foot.
2. What if the bearings are not equidistant then how do we do it
In that case.
Thank you in advance.
At 8:49, shouldn't it be W32t instead of W23t?
Is is correct at 8:47 is it r2 ? Not r3 ?
Thank you for this nice video. I would like to ask how I can calculate the radial and axial force components acting on the bearings of an electrical motor.
The axial and radial forces are found through the gear-shaft-bearings setup you have. It depends on the number, location and type of both the gears and the bearings. Here's a video on radial and axial loads on bearings: ua-cam.com/video/3b8yOMSWXXk/v-deo.html
Lot of great stuff, the math is not a problem, I am I'm struggling with artificial speech, so I muted the speech and turned on the translation and that's a shame
I know this is a years later, but hopefully I can still get an answer. Where did the 60 in the numerator come from for the equation for W23t? At 8:51
It was already there ....T=H.60/2πn and T=W23t.r by equating these two equations