You , deserve all the appreciation i could offer at this moment . man you just saved me a lot of time . effort and money . Liked + subscribed + favorite + notifications
Hello Thank you for your excellent effort. I have a question please At 6:19 you say the reaction doesn't exist the summation torque will not be zero Can you kindly explain this again please?
Thank you for good video. During the video, I wonder just one thing about rotating. You said that because of the steady-state, load torque is equal with the reaction forces. Then, how it can rotate? there isn't any kind of net force to the gear, so gear can't rotate. Please comment about this question!!
Thank you for this nice video. I would like to ask how I can calculate the radial and axial force components acting on the bearings of an electrical motor.
The axial and radial forces are found through the gear-shaft-bearings setup you have. It depends on the number, location and type of both the gears and the bearings. Here's a video on radial and axial loads on bearings: ua-cam.com/video/3b8yOMSWXXk/v-deo.html
Great video but i believe you messed up on the Torque conversion (time stamp 10:07) you have 12 in in the denominator when it should be in the numerator
Great video 👍. Do you have any videos on understanding the concept and calculation of transmission errors in spur and helical gears? and also calculating the load rating in bending and pitting ?
A couple of things: 1. When you draw the gears '3D' the major axis of the ellipse is 90 degrees out of alignment. The gears look too 'tall'. 2. When you discuss the radius of the gear, you need to clarify if it is the pitch circle radius or the base circle radius. To me, it looks like you are assuming that the force (derived from the torque) is acting through the line of action which is at a tangent to the two pitch circle diameters? If so, it doesn't, the force acts at a tangent to the two base circles. If this is the case (I may have misinterpreted your calcs) consider redoing the video as all of your component calculations will be incorrect.
Lot of great stuff, the math is not a problem, I am I'm struggling with artificial speech, so I muted the speech and turned on the translation and that's a shame
For a person who is learning things on gears your videos are helping alot.... I was just wondering why didn't I come across this channel earlier. I have a doubt and would be glad to get the reply sir. 1. Why would you take the radius as 1/6th of a foot. 2. What if the bearings are not equidistant then how do we do it In that case. Thank you in advance.
CORRECTION: At 10:07, the 12 should go in the numerator for the correct unit conversion.
This channel is literally the best for revision before an exam, important concepts with amazing illustrations, just wow !!
Thanks! Share with others!
@@LessBoringLectures already shared
This guy is awsome.
His videos are faaaar more better than everything taught in university
You , deserve all the appreciation i could offer at this moment .
man you just saved me a lot of time . effort and money .
Liked + subscribed + favorite + notifications
Wow, thanks. Share with others!
Thankyou for the video. It was stuck in the force analysis. This helped me to understand it better.
This guy deserves far more subbs
Best Video i've ever seen regarding this topic, You are amazing!
Great video.. Literally cleared my cocepts
clear and sound explanation with great graphic, thanks for the sharing
just saved me on my gears hw, thanks brother, awesome video!
God bless you, Thank you so much for these videos
Keep up the good work. Way better than my engineering professor
Let's hope your professor doesn't watch this channel
It was really helpful. Thank you.
keep going, nice content for engineer
At 8:49, shouldn't it be W32t instead of W23t?
Hello
Thank you for your excellent effort.
I have a question please
At 6:19 you say the reaction doesn't exist the summation torque will not be zero
Can you kindly explain this again please?
can we download a pdf of your notes?
great job man
Is is correct at 8:47 is it r2 ? Not r3 ?
Thank you
I know this is a years later, but hopefully I can still get an answer. Where did the 60 in the numerator come from for the equation for W23t? At 8:51
It was already there ....T=H.60/2πn and T=W23t.r by equating these two equations
What kind of tablet are you using, that thing is awesome
Thank you for good video. During the video, I wonder just one thing about rotating. You said that because of the steady-state, load torque is equal with the reaction forces. Then, how it can rotate? there isn't any kind of net force to the gear, so gear can't rotate. Please comment about this question!!
Amazing video! Wowowowow!
Thank you for this nice video. I would like to ask how I can calculate the radial and axial force components acting on the bearings of an electrical motor.
The axial and radial forces are found through the gear-shaft-bearings setup you have. It depends on the number, location and type of both the gears and the bearings. Here's a video on radial and axial loads on bearings: ua-cam.com/video/3b8yOMSWXXk/v-deo.html
Great video but i believe you messed up on the Torque conversion (time stamp 10:07) you have 12 in in the denominator when it should be in the numerator
You are correct! Thanks!
Great video 👍. Do you have any videos on understanding the concept and calculation of transmission errors in spur and helical gears? and also calculating the load rating in bending and pitting ?
can you provide notes of your less boring leactures?
Nice presentation... What's the app you're using for the presentation sir?
Love it!
A couple of things:
1. When you draw the gears '3D' the major axis of the ellipse is 90 degrees out of alignment. The gears look too 'tall'.
2. When you discuss the radius of the gear, you need to clarify if it is the pitch circle radius or the base circle radius. To me, it looks like you are assuming that the force (derived from the torque) is acting through the line of action which is at a tangent to the two pitch circle diameters? If so, it doesn't, the force acts at a tangent to the two base circles. If this is the case (I may have misinterpreted your calcs) consider redoing the video as all of your component calculations will be incorrect.
Lot of great stuff, the math is not a problem, I am I'm struggling with artificial speech, so I muted the speech and turned on the translation and that's a shame
For a person who is learning things on gears your videos are helping alot.... I was just wondering why didn't I come across this channel earlier.
I have a doubt and would be glad to get the reply sir.
1. Why would you take the radius as 1/6th of a foot.
2. What if the bearings are not equidistant then how do we do it
In that case.
Thank you in advance.