Introduction to Electric Circuits - Delta-Wye (Δ-Y) Conversion Example

In this video, we show you how to use Delta-Wye (Δ-Y) conversion to solve for a single source electric circuit. This circuit is used in circuit laboratory setting. The circuit is verified using PSPICE in another video.

[@muhammadzakiahmad8069]

After roaming about 3 hours on internet for a comprehensive yet basics clearing video i was tired I did'nt wanted to to watch a 26 min video but wow THIS WAS THE VIDEO I WAS LOOKING FOR ,Thanks Sir,May Allah bless you with the best of his never ending treasures.

[@hankhamner3671]

I appreciate the simple and understandable way you explained this. It really helped in my understanding of complex resistor networks.

[@Lexyvil]

Very easy to follow explanation! Thanks!

[@JovaGoose]

Wow! Excellent explanation sir, many thanks!!

[@trisley7772]

Thankyou so much sir! I find it difficult to understant this part of electrical circuits but you explain it very well.

[@clydeceniza2521]

Thank you so much for the informative video! This will help a lot of students especially now classes are done online.

[@epkademy4010]

Thank you very much sir for this lecture. I was having problem understanding this topic. You made it simple to understand.

[@The09hale]

Thank You very much! It is very helpfull to find this lecture.

[@Ivan-go8yk]

Very Nicely explained... Thank you so much

[@_droosak910]

ما شاء الله يا دكتور 💝

[@AJ-et3vf]

Great video sir! Thank you!

[@mxj7019]

Good explanation greetings from Germany 👍🏻 thank you

[@ronricogarcia3216]

I understood it well! Thanks

[@sohailjanjua123]

Hi, I like your lecture. Thanks

[@ila7590]

Thank you so much sir.you made it too easy

[@hadideyal9377]

Thank's sir it was helpful a lot

[@Expl0rer.]

Thank you ,sir .❤

[@simozy4475]

thx for the exercise

[@NoahHensley]

If I wanted to find the voltage across R5 would I use VR5 = Vs((R5||R6)/Rt) or would I reduce it further and use VR5 = Vs((R55||R66)/Rt)? I am a little confused about this concept and I am rapidly approaching finals. Any insight would be greatly appreciated.

[@hassaninternet5729]

Thanks

[@PhillipsENGR]

i believe there is a problem when solving for R33. R1= 2k and R4=2k. Was it supposed to R2 and R4 in the numerator? R2=1k which would give the correct product and fit with the equation, or am i missing something?

[@PhillipsENGR]

also, when solving for I1 you used a different value for Req... Req = 5.1 k, then I1=10/5.2385 k?

[@death6834]

Thank you very much for this lecture sir, i have one doubt as to why do you write the current in mA? Shouldnt it just be 1.96Amperes?

[@oren9836]

if in Amperes, the answer will be 0.00196 A.

[@death6834]

@@oren9836 i see... thanks

[@asuka-ryo]

I'm extremely disappointed and sort of angry that I wasn't introduced to this by my lecturers.

[@shakhriyorkh]

That Arabian pronunciation of R really caught me

[@CarlosGonzalez-pm5kg]

why is it only 7 and not 7k for when you are finding the R11, R22, and R33, in the denominator?

[@ronricogarcia3216]

Typo error, K cancels out anyways

[@ioriTenjin]

where did the 5.2385k came from?

[@WhisperedTales713]

the sum of R33 and R5 (they are connected in series after conversion)

[@MdRonyKhun-eh4pl]

I'll tbj

[@irfannaqlishbahar8127]

why is R11 not involved in calculating I5 and I6?

[@ismi612]

Dia like je, x bagitau pun nape ek

[@irfannaqlishbahar8127]

@@ismi612 dah biasa dah kene palau huhu

[@ismi612]

@@irfannaqlishbahar8127 🤣🤣🤣🤣