Your videos are by far the most concise archives of data on this subject I have ever found. I wish I'd known about your channel when you published this. It would have saved me a ton of headaches understanding electrodynamics. I've had your lectures playing in the background for days. You are the MAN!
This is amazing! I really like the idea of learning glass solutions and hope that this teaching style spreads to many different universities. Thank you for posting Dr. A
+Bhargav Thoom Bhargav, Thanks for the comments. We are having a great time and I have been humbled by all the positive feedback. It's great getting comments from all parts of the world. I too hope that Learning Glass catches on more widely. With more adopters, we can continue to refine this educational delivery method. I do think it's a better way to teach, and I also think that we haven't yet fully tapped its potential. Cheers, Dr. A
Great follow up questions at around time 56:00 would have been to ask: 1) What is the potential on the plates? 2) How does the capacitance change when the plates are moved farther apart? 3) How does E change when the plates are moved farther apart?? 3) Does the potential change when the plates are moved farther apart? 4) Answer the same questions for the capacitor when the plates are moved closer together Explain your answers for full credit. Wayne Adams B.S Chemistry (ACS Certified) M.S. Physics R&D Chemist 9 yrs. Physics Instructor 33 yrs.
+Jegadeesan Ramasamy Good point, but remember that 1 Coulomb is about 10^19 electrons. So a micro Coulomb is still 10^3 electrons, or 10 trillion electrons! Thanks for watching, and keep up with the physics! Cheers, Dr. A
Thank you sir I really enjoyed this lecture and the other electricity lectures 19:16 there is a typo delta(V) must be negative because the given work is positive.
16:10 please, won't the work done be negative, considering the direction of the field drawn. but the change in KE in the question is a positive value; which means that the work done is also positive. Thank you
@ 19:40 potential of B is greater than A . but b/w them there is a negatively charged electron when it moves A to B it is going to accelerate and going to gain K.E and lose potential energy I think for the electron potential of A is greater than B .
at 15:43 u said that plate A is having negative charge . but the direction of an electron is always from positive to negative by sign convention rules so according to sign convention, plate A will have positive charge?????????
Two points of confusion: 1) The arrow pointing to the right indicates which way the electron will move. 2) The electric field (which I did not draw) will certainly point to the left. Since we know F = qE, the negative value for q means the electron moves opposite to the direction of the electric field. Cheers, Dr. A
OLHA EU AQUI VISITANDO SEU PERFIL QUERO TE PARABÉNIZAR PELO SEU LINDO TRABALHOS CONTINUI BRILHANDO GERAL NA TELINHA NOS TRAZENDO CONTEUDO DE QUALIDADE 👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏
Hello sir, Although I could understand why the work done will be zero along an equipotential line, I don't understand why a charge particle would move along a equipotential line when there's no potential difference throughout the path. Can you please help me understand?
A charge at rest remains at rest in an equipotential surface and a charge moving with constant speed will kept on moving. So if the charge has a velocity to begin with it will maintain the velocity and move through this equipotential surface. Hope it helped.
It's pretty obvious he is not an auto mechanic. The distributor distributes the electricity to the various spark plugs. It has nothing to do with generating the high voltage. In the old days it was a rotating disk with an electrode that moved around making contact with electrodes that had wires connected to each spark plug. todays high tech cars use fancy electronics controlled by computers to control the distribution and timing of the spark. You may have seen old movies or TV shows where the villain reaches into a car engine and pulls off this cup shaped object with wires hanging from it, that is the distributor cap. Here is a picture of a typical distributor. www.aa1car.com/library/distributor_1a.jpg The high voltage was generated by a coil that was a step-up transformer, which is device that changes low voltage to high voltage, thus the name step-up. If you look at older engines you will see a large ceramic disk with two small wires attached and a thick wire coming out the center that is attached to the center of the distributor. Here is a picture of a typical ignition coil. www.auto-repair-help.com/images/articles/articles_0808/ignition_coil.jpg The spark plug wires are insulated, so touching the wire will not harm you, unless the wires are old and the insulation is damaged, then you might get a shock. It will not kill you, but it certainly hurts. . LOL Likewise, the connection to the spark plug is covered by an insulating material (called the boot), which is usually some kind of rubber compound or some other fancy synthetic, so that you cannot be shocked. In my younger days, i used to build and drive race cars as a hobby, and I was shocked plenty of times. ;-))
Good discussion BUT At 20:22 you say "Potential is a lot like altitude". Unfortunately this overlooks the crucial point that Potential is a dot PRODUCT of Acceleration (gravitational = "g" or electrical = E) and Distance = gH cos theta or ED cos theta. Its not JUST distance or altitude. A lower altitude on earth may have greater gravitational Potential than a higher altitude on the moon. IOW all altitudes are not the same. This almost absurdly simple dot Product "business" regarding Potential is not emphasized sufficiently in most discussions getting lost or masked in the "thicket" of Joules/coulomb or Joules/Kilogram units and venerable equations like V = KQ/r etc.
The fact that E is perpendicular to the equipotential surface at each point leads to a nifty experiment that allows the student to map E. It is a thin board that is coated with a graphite mixture. Two copper conducting surfaces are printed on it. They have various shapes, So one board has two points for dipoles. One has two two lines for parallel plates. One has a point and a plate, and so on. The student connects a power supply set at about 6 volts to both points. A nine volt battery also works very well. There is a potential difference of 6 volts from one connection to the other. The student connects one lead of a voltmeter to the positive end, The other lead of the voltmeter is then touched to various points on the surface around the charged points, which measures the potential difference between that point and the positive charge. Equipotential lines can now be sketched by connecting points which have the same potential. Since E is perpendicular to equipotential lines, and proportional to the potential, the student can now draw in the E field. It is perpendicular to the equipotential line with a length that is proportional to the potential at that point. If we just want the students to visualize the E field without regard to the strength, we can have them draw in continuous lines connecting one point to the next. That gives the students nice field lines connecting one charge to the other. If the students are careful they can get very good looking E field maps. Wayne Adams B.S Chemistry (ACS Certified) M.S. Physics R&D Chemist 9 yrs. Physics Instructor 33 yrs.
@@wayneyadams also even if you HAD a PHD that doesnt mean youre always correct, unless youre making an argument from authority which is a logical fallacy, propositions stand on their own merits, and guess what in 1000 years you wont be remembered just like me, so youre not that smart - you just think you are
also you got a masters from FIU, lets be honest here, thats not a top university even in america nevermind the world, i dont even think they turn down applications for entry at FIU, i go to a top 20 global university and not one professor ive met is as arrogant as you but hey maybe next lifetime youll be smart enough to get into a good school
professor dr good morning! Could you please hold a class on the topic (Electrical Grounding) demonstrating from the Laplace equation ∇^2 V=0 developing mathematics until obtaining V_P=Iρ/2π x (1/R+2∑_(N=1)^∞ K^n/√(r^2+(2nh)^2 )) from now on thank you very much.
Light follows 5 different vectors per em wave surprisingly the line in middle of b and e field comes last, so five vectors then idk...but also in five random configurations...so five vectors per wave , times five configurations...that go in order' tho calculatable with processor...goose turns few pages in his study's... humm' ...
This is amazing! I really like the idea of learning glass solutions and hope that this teaching style spreads to many different universities. Thank you for posting Dr. A
Harlbert Mayer Hsia, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A
I know this was posted like 7 Years ago but these videos help me so much, Thank You!!!
You’re seriously saving lives here !! Thank you 💗❤️
Uses of electrostatic chargers in modern days
Your videos are by far the most concise archives of data on this subject I have ever found. I wish I'd known about your channel when you published this. It would have saved me a ton of headaches understanding electrodynamics. I've had your lectures playing in the background for days. You are the MAN!
noted. currently in electro
Prof, I love you sketches. The way where you draw things with explanation is very clear.
This is amazing! I really like the idea of learning glass solutions and hope that this teaching style spreads to many different universities.
Thank you for posting Dr. A
+Bhargav Thoom
Bhargav,
Thanks for the comments. We are having a great time and I have been humbled by all the positive feedback. It's great getting comments from all parts of the world.
I too hope that Learning Glass catches on more widely. With more adopters, we can continue to refine this educational delivery method. I do think it's a better way to teach, and I also think that we haven't yet fully tapped its potential.
Cheers, Dr. A
Bhargav Thoom do you know where I can get videos explainin interefernce of waves, diffraction and young's double slit experiment?
God, online classes are killing me, but you just revive me.
i cant tell u how much this has helped me
all the concepts are crystal clear now
thank u so much for taking time to help us
be happy always
Glad to hear it. Thanks for the shout out.
Cheers,
Dr. A
I am well understood!! thanks for your awesome videos.... love u
Great follow up questions at around time 56:00 would have been to ask:
1) What is the potential on the plates?
2) How does the capacitance change when the plates are moved farther apart?
3) How does E change when the plates are moved farther apart??
3) Does the potential change when the plates are moved farther apart?
4) Answer the same questions for the capacitor when the plates are moved closer together
Explain your answers for full credit.
Wayne Adams
B.S Chemistry (ACS Certified)
M.S. Physics
R&D Chemist 9 yrs.
Physics Instructor 33 yrs.
Woah, you're amazing
I have greatly enjoyed your video. Please do you have videos on diffraction, interference of waves, and young's double slit experiment
I'm working on some more, but for now, here's one:
ua-cam.com/video/IuIlvmzpS64/v-deo.html
Cheers,
Dr. A
Absolutely GOATed teacher still 9 years later
I love when Doctor Strange teaching physics
I have a doubt. When you the write the force on the mass due to gravity as it is pointing downward it should be written as -mg right?
it is amazing that three micro coulomb charge can create such huge volts of 10*10^6.
+Jegadeesan Ramasamy Good point, but remember that 1 Coulomb is about 10^19 electrons. So a micro Coulomb is still 10^3 electrons, or 10 trillion electrons! Thanks for watching, and keep up with the physics!
Cheers, Dr. A
When you stated q is charge on top plate, would this apply if the charges had been reversed? We would have used a negative q?
Thank you sir I really enjoyed this lecture and the other electricity lectures
19:16 there is a typo delta(V) must be negative because the given work is positive.
what is the relationship between an electric field and electric potential?
The magnitude of the electrical field is equal to the voltage over the distance to the positive source.
The electric field is the negative spatial gradient of potential.
16:10 please, won't the work done be negative, considering the direction of the field drawn. but the change in KE in the question is a positive value; which means that the work done is also positive. Thank you
@ 19:40 potential of B is greater than A . but b/w them there is a negatively charged electron when it moves A to B it is going to accelerate and going to gain K.E and lose potential energy I think for the electron potential of A is greater than B .
at 15:43 u said that plate A is having negative charge . but the direction of an electron is always from positive to negative by sign convention rules so according to sign convention, plate A will have positive charge?????????
Two points of confusion: 1) The arrow pointing to the right indicates which way the electron will move. 2) The electric field (which I did not draw) will certainly point to the left. Since we know F = qE, the negative value for q means the electron moves opposite to the direction of the electric field.
Cheers,
Dr. A
instead of 8.99 if we take the rounded value of k=9 will it be OK? ?
It will be 99.9% okay.
Cheers,
Dr. A
how can you write on the glass inversely?
Secrets here: www.learning.glass
Cheers,
Dr. A
@@yoprofmatt nice
thank you my Daer wonderfull
How come there is no S2 Module 05 on Capacitors
What software tools do you use to present your blackboard overlaid your video.
www.learning.glass
Cheers,
Dr. A
I can’t find the s2 module 5
Is it anywhere?
Which book you follow? I am India and you content is very similar to ncert. But I still 😍 your lecture.
OLHA EU AQUI VISITANDO SEU PERFIL QUERO TE PARABÉNIZAR PELO SEU LINDO TRABALHOS CONTINUI BRILHANDO GERAL NA TELINHA NOS TRAZENDO CONTEUDO DE QUALIDADE 👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏
Ohh the dipole reminds me of a bar magnet where in the north pole represents the positive charge and south pole also represents negative charge.
Yep, similar idea.
Cheers,
Dr. A
Hello sir, Although I could understand why the work done will be zero along an equipotential line, I don't understand why a charge particle would move along a equipotential line when there's no potential difference throughout the path. Can you please help me understand?
A charge at rest remains at rest in an equipotential surface and a charge moving with constant speed will kept on moving. So if the charge has a velocity to begin with it will maintain the velocity and move through this equipotential surface. Hope it helped.
It's pretty obvious he is not an auto mechanic. The distributor distributes the electricity to the various spark plugs. It has nothing to do with generating the high voltage. In the old days it was a rotating disk with an electrode that moved around making contact with electrodes that had wires connected to each spark plug. todays high tech cars use fancy electronics controlled by computers to control the distribution and timing of the spark. You may have seen old movies or TV shows where the villain reaches into a car engine and pulls off this cup shaped object with wires hanging from it, that is the distributor cap. Here is a picture of a typical distributor.
www.aa1car.com/library/distributor_1a.jpg
The high voltage was generated by a coil that was a step-up transformer, which is device that changes low voltage to high voltage, thus the name step-up. If you look at older engines you will see a large ceramic disk with two small wires attached and a thick wire coming out the center that is attached to the center of the distributor. Here is a picture of a typical ignition coil.
www.auto-repair-help.com/images/articles/articles_0808/ignition_coil.jpg
The spark plug wires are insulated, so touching the wire will not harm you, unless the wires are old and the insulation is damaged, then you might get a shock. It will not kill you, but it certainly hurts. . LOL Likewise, the connection to the spark plug is covered by an insulating material (called the boot), which is usually some kind of rubber compound or some other fancy synthetic, so that you cannot be shocked.
In my younger days, i used to build and drive race cars as a hobby, and I was shocked plenty of times. ;-))
Old cars are so much more fun to work on than cars today with everything computerized.
best teacher im kurdesh look at your video
Awesome! Thanks!
Thanks for watching.
Cheers,
Dr. A
Sir can you please make video on transmission lines
u are an amazing professor
Thank you. Keep up with the physics.
Cheers,
Dr. A
It's actually a little frightening that university students couldn't recognise a spark plug.
Good discussion BUT
At 20:22 you say "Potential is a lot like altitude".
Unfortunately this overlooks the crucial point that Potential is a dot PRODUCT of Acceleration (gravitational = "g" or electrical = E) and Distance = gH cos theta or ED cos theta.
Its not JUST distance or altitude. A lower altitude on earth may have greater gravitational Potential than a higher altitude on the moon. IOW all altitudes are not the same.
This almost absurdly simple dot Product "business" regarding Potential is not emphasized sufficiently in most discussions getting lost or masked in the "thicket" of Joules/coulomb or Joules/Kilogram units and venerable equations like V = KQ/r etc.
The fact that E is perpendicular to the equipotential surface at each point leads to a nifty experiment that allows the student to map E. It is a thin board that is coated with a graphite mixture. Two copper conducting surfaces are printed on it. They have various shapes, So one board has two points for dipoles. One has two two lines for parallel plates. One has a point and a plate, and so on.
The student connects a power supply set at about 6 volts to both points. A nine volt battery also works very well. There is a potential difference of 6 volts from one connection to the other. The student connects one lead of a voltmeter to the positive end, The other lead of the voltmeter is then touched to various points on the surface around the charged points, which measures the potential difference between that point and the positive charge. Equipotential lines can now be sketched by connecting points which have the same potential. Since E is perpendicular to equipotential lines, and proportional to the potential, the student can now draw in the E field. It is perpendicular to the equipotential line with a length that is proportional to the potential at that point.
If we just want the students to visualize the E field without regard to the strength, we can have them draw in continuous lines connecting one point to the next. That gives the students nice field lines connecting one charge to the other. If the students are careful they can get very good looking E field maps.
Wayne Adams
B.S Chemistry (ACS Certified)
M.S. Physics
R&D Chemist 9 yrs.
Physics Instructor 33 yrs.
signing your name like that is cringe, no one cares, arguments stand on their own merits get over your ego
@@Loots1 I do it to stop inane comments like yours.
@@wayneyadams my comment isnt silly but your ego is
@@wayneyadams also even if you HAD a PHD that doesnt mean youre always correct, unless youre making an argument from authority which is a logical fallacy, propositions stand on their own merits, and guess what in 1000 years you wont be remembered just like me, so youre not that smart - you just think you are
also you got a masters from FIU, lets be honest here, thats not a top university even in america nevermind the world, i dont even think they turn down applications for entry at FIU, i go to a top 20 global university and not one professor ive met is as arrogant as you but hey maybe next lifetime youll be smart enough to get into a good school
professor dr good morning!
Could you please hold a class on the topic (Electrical Grounding) demonstrating from the Laplace equation
∇^2 V=0 developing mathematics until obtaining V_P=Iρ/2π x (1/R+2∑_(N=1)^∞ K^n/√(r^2+(2nh)^2 )) from now on thank you very much.
for me that's strange nobody knows spark and coil . don't they have motorcycle?
Not that many motorcycles in the USA. And pretty soon, those will be electric too.
Cheers,
Dr. A
thank you sir..
Capacitors, voltage, energy, equipotentials, spark plug.
Quite the list.
Cheers,
Dr. A
fuck... the sound from the marker...
Light follows 5 different vectors per em wave surprisingly the line in middle of b and e field comes last, so five vectors then idk...but also in five random configurations...so five vectors per wave , times five configurations...that go in order' tho calculatable with processor...goose turns few pages in his study's... humm' ...
IT's a spark plug.
Why do you look like a teenager is some of your videos and like doctor Strange in this video?
The power of photoshop.
Cheers.
Dr. A
ALLDRY
my guess is spark plug
fuckin knew it, so proud of myself lmfao
wow the man is so handsome
If he was a black man would you still say that?
Ashlyn Nundlall always bringing race into something
@@ashlynnundlall you must be racist
You’re seriously saving lives here !! Thank you 💗❤️
I hope so. That would be icing on the cake.
Cheers,
Dr. A
This is amazing! I really like the idea of learning glass solutions and hope that this teaching style spreads to many different universities.
Thank you for posting Dr. A
I hope so too!
Cheers,
Dr. A
thank you my Daer wonderfull
Harlbert Mayer Hsia,
You're very welcome. Glad you're enjoying the videos.
You might also like my new site: www.universityphysics.education
Cheers,
Dr. A